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Category: Trigonometry

Question-140803

Question Number 140803 by jlewis last updated on 12/May/21 Answered by Ar Brandon last updated on 12/May/21 tany=2xx21,1+tan2y=sec2y$$\Rightarrow\mathrm{cosy}=\pm\frac{\mathrm{1}}{\:\sqrt{\mathrm{1}+\mathrm{tan}^{\mathrm{2}} \mathrm{y}}}=\pm\frac{\mathrm{1}}{\:\sqrt{\mathrm{1}+\left(\frac{\mathrm{2x}}{\mathrm{x}^{\mathrm{2}} −\mathrm{1}}\right)^{\mathrm{2}}…

A-vertical-pole-3m-high-is-2m-south-of-a-wall-which-runs-directly-east-and-west-The-sun-is-south-west-at-an-elevation-of-35-Find-to-the-nearest-centimeter-the-height-of-the-shadow-of-the-pole-on-th

Question Number 9709 by tawakalitu last updated on 28/Dec/16 Averticalpole3mhighis2msouthofawallwhichrunsdirectlyeastandwest.Thesunissouthwestatanelevationof35°.Findtothenearestcentimetertheheightoftheshadowofthepoleonthewall. Answered by mrW last updated…