Question Number 1206 by gs8763330@gmail.com last updated on 14/Jul/15 $${prove}\:{that}\:\:\mathrm{2sin}^{−\mathrm{1}} \mathrm{3}/\mathrm{4}=\mathrm{tan}^{−\mathrm{1}} \mathrm{24}/\mathrm{7} \\ $$ Commented by 123456 last updated on 14/Jul/15 $$\mathrm{sin}\:\alpha={a}\overset{{b}.{c}} {\Leftrightarrow}\alpha=\mathrm{sin}^{−\mathrm{1}} {a} \\…
Question Number 132205 by Arijit last updated on 12/Feb/21 Commented by Arijit last updated on 12/Feb/21 $$\boldsymbol{\mathrm{Please}}\:\boldsymbol{\mathrm{Help}}\:\boldsymbol{\mathrm{me}}\:\boldsymbol{\mathrm{to}}\:\boldsymbol{\mathrm{solve}}\:\boldsymbol{\mathrm{this}}….. \\ $$ Answered by mathmax by abdo last…
Question Number 1113 by 123456 last updated on 15/Jun/15 $$\mathrm{sin}^{−\mathrm{1}} \left[\frac{\sqrt{\mathrm{3}}}{\mathrm{8}}\left(\sqrt{\mathrm{13}}−\mathrm{1}\right)\right]+\mathrm{sin}^{−\mathrm{1}} \frac{\sqrt{\mathrm{3}}}{\mathrm{4}}=? \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 1018 by prakash jain last updated on 15/May/15 $$\mathrm{Find} \\ $$$$\mathrm{tan}\:\theta+\mathrm{2tan}\:\mathrm{2}\theta+\mathrm{2}^{\mathrm{2}} \mathrm{tan}\:\mathrm{2}^{\mathrm{2}} \theta+…+\mathrm{2}^{{n}} \mathrm{tan}\:\mathrm{2}^{{n}} \theta \\ $$ Answered by prakash jain last updated…
Question Number 132081 by liberty last updated on 11/Feb/21 $$\mathrm{Prove}\:\mathrm{tan}\:\left(\mathrm{A}+\mathrm{B}\right)−\mathrm{tan}\:\mathrm{A}=\:\frac{\mathrm{sin}\:\mathrm{B}}{\mathrm{cos}\:\mathrm{A}\:\mathrm{cos}\:\left(\mathrm{A}+\mathrm{B}\right)} \\ $$ Answered by rs4089 last updated on 11/Feb/21 $${tan}\left({A}+{B}\right)−{tanA} \\ $$$$\frac{{sin}\left({A}+{B}\right)}{{cos}\left({A}+{B}\right)}−\frac{{sinA}}{{cosA}} \\ $$$$\frac{{sin}\left({A}+{B}\right).{cosA}−{sinA}.{cos}\left({A}+{B}\right)}{{cos}\left({A}+{B}\right).{cosA}} \\…
Question Number 132016 by bramlexs22 last updated on 10/Feb/21 $$\mathrm{Trigonometry} \\ $$$$\:\mathrm{What}\:\mathrm{is}\:\mathrm{the}\:\mathrm{minimum}\:\mathrm{value}\:\mathrm{of} \\ $$$$\:\sqrt{\left(\mathrm{3sin}\:\mathrm{x}−\mathrm{4cos}\:\mathrm{x}−\mathrm{10}\right)\left(\mathrm{3sin}\:\mathrm{x}+\mathrm{4cos}\:\mathrm{x}−\mathrm{10}\right)}\:. \\ $$ Answered by EDWIN88 last updated on 11/Feb/21 $$\:\mathrm{consider}\:\left(\left(\mathrm{3sin}\:\mathrm{x}−\mathrm{10}\right)−\mathrm{4cos}\:\mathrm{x}\right)\left(\left(\mathrm{3sin}\:\mathrm{x}−\mathrm{10}\right)+\mathrm{4cos}\:\mathrm{x}\right)= \\…
Question Number 132006 by bramlexs22 last updated on 10/Feb/21 $$\:\mathrm{Given}\:\begin{cases}{\sqrt{\mathrm{2}}\:\mathrm{cos}\:\mathrm{A}=\mathrm{cos}\:\mathrm{B}+\mathrm{cos}\:^{\mathrm{3}} \mathrm{B}}\\{\sqrt{\mathrm{2}}\:\mathrm{sin}\:\mathrm{A}=\mathrm{sin}\:\mathrm{B}−\mathrm{sin}\:^{\mathrm{3}} \mathrm{B}}\end{cases} \\ $$$$\mathrm{what}\:\mathrm{is}\:\mathrm{the}\:\mathrm{value}\:\mathrm{of}\:\mathrm{sin}\:\left(\mathrm{A}−\mathrm{B}\right). \\ $$ Answered by EDWIN88 last updated on 10/Feb/21 $$\:\begin{cases}{\mathrm{2cos}\:^{\mathrm{2}} \mathrm{A}=\mathrm{cos}\:^{\mathrm{2}}…
Question Number 764 by prakash jain last updated on 13/Mar/15 $$\mathrm{tan}\:{x}+\mathrm{tan}\:\mathrm{2}{x}+\mathrm{tan}\:\mathrm{4}{x}+…+\mathrm{tan}\:\mathrm{2}^{{n}} {x}=? \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 752 by 112358 last updated on 06/Mar/15 $${Show}\:{that}\:,\:\forall{b}\in{R}^{+} ,\: \\ $$$${tan}^{−\mathrm{1}} {b}+{tan}^{−\mathrm{1}} \frac{\mathrm{1}}{{b}}=\frac{\pi}{\mathrm{2}}\:. \\ $$ Answered by 123456 last updated on 06/Mar/15 $${lets}\:{f}\left({x}\right):=\mathrm{arctan}\:{x}+\mathrm{arctan}\:\frac{\mathrm{1}}{{x}},{x}>\mathrm{0}…
Question Number 722 by malwaan1 last updated on 04/Mar/15 $${solve}\:{the}\:{equation}\:{cos}^{\mathrm{2001}} {x}−{sin}^{\mathrm{2001}} =\mathrm{1} \\ $$$$ \\ $$ Commented by malwaan last updated on 04/Mar/15 $${what}\:{about}\:{cos}^{{n}} {x}−{sin}^{{n}}…