Question Number 132006 by bramlexs22 last updated on 10/Feb/21 $$\:\mathrm{Given}\:\begin{cases}{\sqrt{\mathrm{2}}\:\mathrm{cos}\:\mathrm{A}=\mathrm{cos}\:\mathrm{B}+\mathrm{cos}\:^{\mathrm{3}} \mathrm{B}}\\{\sqrt{\mathrm{2}}\:\mathrm{sin}\:\mathrm{A}=\mathrm{sin}\:\mathrm{B}−\mathrm{sin}\:^{\mathrm{3}} \mathrm{B}}\end{cases} \\ $$$$\mathrm{what}\:\mathrm{is}\:\mathrm{the}\:\mathrm{value}\:\mathrm{of}\:\mathrm{sin}\:\left(\mathrm{A}−\mathrm{B}\right). \\ $$ Answered by EDWIN88 last updated on 10/Feb/21 $$\:\begin{cases}{\mathrm{2cos}\:^{\mathrm{2}} \mathrm{A}=\mathrm{cos}\:^{\mathrm{2}}…
Question Number 764 by prakash jain last updated on 13/Mar/15 $$\mathrm{tan}\:{x}+\mathrm{tan}\:\mathrm{2}{x}+\mathrm{tan}\:\mathrm{4}{x}+…+\mathrm{tan}\:\mathrm{2}^{{n}} {x}=? \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 752 by 112358 last updated on 06/Mar/15 $${Show}\:{that}\:,\:\forall{b}\in{R}^{+} ,\: \\ $$$${tan}^{−\mathrm{1}} {b}+{tan}^{−\mathrm{1}} \frac{\mathrm{1}}{{b}}=\frac{\pi}{\mathrm{2}}\:. \\ $$ Answered by 123456 last updated on 06/Mar/15 $${lets}\:{f}\left({x}\right):=\mathrm{arctan}\:{x}+\mathrm{arctan}\:\frac{\mathrm{1}}{{x}},{x}>\mathrm{0}…
Question Number 722 by malwaan1 last updated on 04/Mar/15 $${solve}\:{the}\:{equation}\:{cos}^{\mathrm{2001}} {x}−{sin}^{\mathrm{2001}} =\mathrm{1} \\ $$$$ \\ $$ Commented by malwaan last updated on 04/Mar/15 $${what}\:{about}\:{cos}^{{n}} {x}−{sin}^{{n}}…
Question Number 131595 by Algoritm last updated on 06/Feb/21 Commented by Algoritm last updated on 06/Feb/21 $$\mathrm{x}_{\mathrm{1}} =\mathrm{37}/\mathrm{2}\:\:\:\mathrm{x}_{\mathrm{2}} =\mathrm{77}/\mathrm{4}\:\:\:\mathrm{x}_{\mathrm{3}} =\mathrm{65}/\mathrm{4} \\ $$$$\Sigma\boldsymbol{\mathrm{x}}=\mathrm{37}/\mathrm{2}+\mathrm{77}/\mathrm{4}+\mathrm{65}/\mathrm{4}=\mathrm{54}\:\: \\ $$$$\boldsymbol{\mathrm{prove}}\:\boldsymbol{\mathrm{that}}! \\…