Question Number 64619 by Aysha Abedin last updated on 19/Jul/19 $${show}\:{that}\:\int_{−\alpha} ^{\alpha} {sinc}\left({x}\right){dx}=\int_{−\alpha} ^{\alpha} {sinc}^{\mathrm{2}} \left({x}\right){dx}=\Pi \\ $$ Commented by mathmax by abdo last updated…
Question Number 130082 by benjo_mathlover last updated on 22/Jan/21 $$\mathrm{Given}\:\mathrm{sin}^{−\mathrm{1}} \left(\mathrm{sin}\:{a}+\mathrm{sin}\:{b}\right)+\mathrm{sin}^{−\mathrm{1}} \left(\mathrm{sin}\:{a}−\mathrm{sin}\:{b}\right)=\frac{\pi}{\mathrm{2}} \\ $$$$\mathrm{what}\:\mathrm{is}\:\mathrm{the}\:\mathrm{value}\:\mathrm{of}\:\mathrm{sin}\:^{\mathrm{2}} {a}\:+\mathrm{sin}\:^{\mathrm{2}} {b}. \\ $$ Answered by liberty last updated on 22/Jan/21…
Question Number 130054 by EDWIN88 last updated on 22/Jan/21 $$\mathrm{The}\:\mathrm{maximum}\:\mathrm{value}\:\mathrm{of}\:\mathrm{f}\left(\mathrm{x}\right)=\mathrm{sin}\:^{\mathrm{2}} \left(\frac{\mathrm{2}\pi}{\mathrm{3}}+\mathrm{x}\right)+\mathrm{sin}\:^{\mathrm{2}} \left(\frac{\mathrm{2}\pi}{\mathrm{3}}−\mathrm{x}\right)\:\mathrm{is}\:? \\ $$ Answered by liberty last updated on 22/Jan/21 Commented by MJS_new last…
Question Number 130047 by liberty last updated on 22/Jan/21 $$\:\mathrm{Given}\:\mathrm{4cos}\:^{\mathrm{2}} \mathrm{x}\:\mathrm{sin}\:\mathrm{x}−\mathrm{2sin}\:^{\mathrm{2}} \mathrm{x}\:=\:\mathrm{3sin}\:\mathrm{x} \\ $$$$\mathrm{where}\:−\frac{\pi}{\mathrm{2}}\leqslant\mathrm{x}\leqslant\frac{\pi}{\mathrm{2}}\:.\:\mathrm{Find}\:\mathrm{the}\:\mathrm{sum}\:\mathrm{of} \\ $$$$\mathrm{all}\:\mathrm{posibble}\:\mathrm{value}\:\mathrm{of}\:\mathrm{x}. \\ $$ Answered by MJS_new last updated on 22/Jan/21…
Question Number 130041 by liberty last updated on 22/Jan/21 $$\mathrm{Given}\:\mathrm{A}\:\mathrm{and}\:\mathrm{B}\:\mathrm{are}\:\mathrm{the}\:\mathrm{solution} \\ $$$$\mathrm{of}\:\mathrm{equation}\:{a}\:\mathrm{tan}\:{x}\:+\:{b}\:\mathrm{sec}\:{x}\:=\:{c}\: \\ $$$${find}\:\mathrm{tan}\:\left({A}+\mathrm{B}\right). \\ $$ Answered by nueron last updated on 22/Jan/21 Commented by…
Question Number 64498 by slotto last updated on 18/Jul/19 $$\mathrm{please},\:\mathrm{anyone}\:\mathrm{help}\:\mathrm{me}\:\mathrm{to}\:\mathrm{solve}\:\mathrm{this} \\ $$$$\mathrm{i}.\:\underset{\mathrm{k}=\mathrm{1}} {\overset{\mathrm{n}} {\sum}}\mathrm{cos}\left(\frac{\mathrm{k}^{\mathrm{2}} \pi}{\mathrm{n}}\right) \\ $$$$\mathrm{ii}.\:\underset{\mathrm{k}=\mathrm{1}} {\overset{\mathrm{n}} {\Sigma}}\mathrm{sin}\left(\frac{\mathrm{k}^{\mathrm{2}} \pi}{\mathrm{n}}\right) \\ $$$$\mathrm{thank}\:\mathrm{you}. \\ $$ Terms…
Question Number 129958 by bemath last updated on 21/Jan/21 $$\:\mathrm{3}+\mathrm{cos}\:\left(\mathrm{6x}\right)\:=\:\mathrm{2}\:\left(\frac{\mathrm{sin}\:\mathrm{3x}}{\mathrm{cos}\:\mathrm{4x}}\right)−\mathrm{4tan}\:^{\mathrm{2}} \left(\mathrm{4x}\right) \\ $$ Answered by MJS_new last updated on 21/Jan/21 $${s}=\mathrm{sin}\:{x} \\ $$$$… \\ $$$${s}^{\mathrm{14}}…
Question Number 64299 by mathmax by abdo last updated on 16/Jul/19 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 129807 by bramlexs22 last updated on 19/Jan/21 $$\:\mathrm{8}.\left(\mathrm{1}+\mathrm{sin}\:\frac{\pi}{\mathrm{8}}\right)\left(\mathrm{1}+\mathrm{sin}\frac{\mathrm{3}\pi}{\mathrm{8}}\right)\left(\mathrm{1}−\mathrm{sin}\:\frac{\mathrm{5}\pi}{\mathrm{8}}\right)\left(\mathrm{1}−\mathrm{sin}\:\frac{\mathrm{7}\pi}{\mathrm{8}}\right)=?\: \\ $$ Answered by EDWIN88 last updated on 19/Jan/21 $$\:\mathrm{sin}\:\mathrm{x}\:=\:\mathrm{sin}\:\left(\pi−\mathrm{x}\right) \\ $$$$\:\mathrm{sin}\:\frac{\mathrm{3}\pi}{\mathrm{8}}=\mathrm{sin}\:\frac{\mathrm{5}\pi}{\mathrm{8}}\:\mathrm{and}\:\mathrm{sin}\:\frac{\mathrm{7}\pi}{\mathrm{8}}=\mathrm{sin}\:\frac{\pi}{\mathrm{8}} \\ $$$$\Leftrightarrow\:\mathrm{8}\left(\mathrm{1}+\mathrm{sin}\:\frac{\pi}{\mathrm{8}}\right)\left(\mathrm{1}−\mathrm{sin}\:\frac{\pi}{\:\mathrm{8}}\right)\left(\mathrm{1}+\mathrm{sin}\:\frac{\mathrm{3}\pi}{\mathrm{8}}\right)\left(\mathrm{1}−\mathrm{sin}\:\frac{\mathrm{3}\pi}{\mathrm{8}}\right)= \\…
Question Number 129801 by bramlexs22 last updated on 19/Jan/21 $$\:\mathrm{cot}\:\mathrm{15}°\:\mathrm{cot}\:\mathrm{16}°\:\mathrm{cot}\:\mathrm{17}°…\:\mathrm{cot}\:\mathrm{75}°= \\ $$ Answered by EDWIN88 last updated on 19/Jan/21 $$=\mathrm{1} \\ $$$$\:\left[\:\mathrm{cot}\:\mathrm{15}°=\mathrm{tan}\:\mathrm{75}°\:\mathrm{etc}\:\right]\: \\ $$ Terms…