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Category: Trigonometry

Question-213519

Question Number 213519 by RojaTaniya last updated on 07/Nov/24 Answered by mr W last updated on 07/Nov/24 tanα=1xtan(α+β)=3xtan(α+α+β)=6x$$\frac{\mathrm{6}}{{x}}=\frac{\frac{\mathrm{1}}{{x}}+\frac{\mathrm{3}}{{x}}}{\mathrm{1}−\frac{\mathrm{1}}{{x}}×\frac{\mathrm{3}}{{x}}}=\frac{\mathrm{4}{x}}{{x}^{\mathrm{2}} −\mathrm{3}}…