Trigonometry – Page 33

cot-2-pi-7-cot-2-2pi-7-cot-2-3pi-7-

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Question Number 128582 by john_santu last updated on 08/Jan/21 $\cot^{2} (\frac{π}{7}) + \cot^{2} (\frac{2 π}{7}) + \cot^{2} (\frac{3 π}{7}) = ?$ Answered by liberty last updated on 08/Jan/21 $$\:\mathrm{T}\:=\:\mathrm{cot}\:^{\mathrm{2}} \left(\frac{\pi}{\mathrm{7}}\right)+\mathrm{cot}\:^{\mathrm{2}} \left(\frac{\mathrm{2}\pi}{\mathrm{7}}\right)+\mathrm{cot}\:^{\mathrm{2}}…

find-a-simple-expression-for-y-sin-1-sin-x-x-R-and-x-in-rad-

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Question Number 128546 by mr W last updated on 08/Jan/21 $f i n d a s i m p l e e x p r e s s i o n f o r$ $y = \sin^{- 1} (\sin x)$ $x \in R a n d x i n r a d .$ Commented by liberty last updated on 08/Jan/21…

f-x-R-1-M-2-sin-2-atan-N-sin-x-c-g-x-acos-A-sin-atan-N-sin-x-c-B-cos-atan-N-sin-x-c-cos-D-x-f-x-g-x-L-x-L-x-

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Question Number 128361 by DomaPeti last updated on 06/Jan/21 $f (x) =$ $\frac{R}{\sqrt{1 - M^{2} {s i n}^{2} (a t a n (N \cdot s i n (x + c)))}}$ $g (x) = a c o s (A \cdot s i n (a t a n (N \cdot s i n (x + c))) +$ $B \cdot c o s (a t a n (N \cdot s i n (x + c))) \cdot c o s (D - x))$ $\int (f (x) \cdot g {(x)}^{'}) = L (x)$ $L (x) = ?$ $$ \…

If-sec-x-tan-x-sec-x-tan-x-5-then-what-is-the-value-of-3cos-2x-1-3cos-2x-1-

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Question Number 128336 by liberty last updated on 06/Jan/21 $If \frac{\sec x + \tan x}{\sec x - \tan x} = 5 then what is the$ $value of \frac{3 \cos 2 x + 1}{3 \cos 2 x - 1} ?$ Answered by bramlexs22 last updated on 06/Jan/21 $\Rightarrow \frac{\sec x + \tan x}{\sec x - \tan x} = 5$ $$\Rightarrow\frac{\mathrm{cos}\:{x}\left(\mathrm{sec}\:{x}+\mathrm{tan}\:{x}\right)}{\mathrm{cos}\:{x}\left(\mathrm{sec}\:{x}−\mathrm{tan}\:{x}\right)}\:=\:\mathrm{5} \…

Prove-that-tan-30-30-6-2-3-2-

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Question Number 128333 by liberty last updated on 06/Jan/21 $Prove that \tan 30 ° 30^{'} = \sqrt{6} + \sqrt{2} - \sqrt{3} - 2$ Commented by MJS_new last updated on 06/Jan/21 $not true ?!$ $\tan (7.5 ° + 180 ° \times n) = - 2 + \sqrt{2} - \sqrt{3} + \sqrt{6}$ Commented…

if-cos-cosA-cosB-1-cosA-cosB-prove-that-Tan-2-Tan-A-2-Cot-B-2-

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Question Number 62761 by lalitchand last updated on 25/Jun/19 $if \cos θ = \frac{cosA . cosB}{1 - cosA . cosB} prove that Tan \frac{θ}{2} = Tan \frac{A}{2} . Cot \frac{B}{2}$ Commented by Prithwish sen last updated on 25/Jun/19 $I think it is$ $\cos θ = \frac{cosA - cosB}{1 - cosAcosB}$ $$\frac{\mathrm{1}−\mathrm{cos}\theta}{\mathrm{1}+\mathrm{cos}\theta}\:=\:\frac{\mathrm{1}−\mathrm{cosA}+\mathrm{cosB}−\mathrm{cosAcosB}}{\mathrm{1}+\mathrm{cosA}−\mathrm{cosB}−\mathrm{cosAcosB}}…

Lines-5x-12y-10-0-and-5x-12y-40-0-touch-circle-C-1-of-diameter-6-If-the-center-of-C-1-lies-in-the-Ist-quadrant-find-the-equation-of-circle-C-2-which-is-concentric-with-C-1-and-cuts-intercep

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Question Number 62698 by Ankit0512 last updated on 24/Jun/19 $L i n e s 5 x + 12 y - 10 = 0 a n d 5 x - 12 y - 40 = 0$ $t o u c h c i r c l e C_{1} o f d i a m e t e r 6 . I f t h e$ $c e n t e r o f C_{1} l i e s i n t h e I s t q u a d r a n t,$ $f i n d t h e e q u a t i o n o f c i r c l e C_{2} w h i c h i s$ $c o n c e n t r i c w i t h C_{1} a n d c u t s i n t e r c e p t$ $${of}\:{length}\:\mathrm{8}\:{on}\:{these}\:{lines}. \…

Prove-that-the-area-of-any-quadrilateral-ABCD-is-s-a-s-b-s-c-s-d-abcd-cos-2-A-C-2-

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Question Number 128178 by bemath last updated on 05/Jan/21 $Prove that the area of any$ $quadrilateral ABCD is$ $\sqrt{(s - a) (s - b) (s - c) (s - d) - abcd \cos^{2} (\frac{A + C}{2})} .$ Answered by mr W last updated on 05/Jan/21…

what-is-2sin-2-cos-2-

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Question Number 62595 by Pranay last updated on 23/Jun/19 $w h a t i s 2 {s i n}^{2} θ {c o s}^{2} θ ?$ Commented by ajfour last updated on 23/Jun/19 $${same}\:{as}\:\:\mathrm{2}×\frac{{p}^{\mathrm{2}} }{{h}^{\mathrm{2}} }×\frac{{b}^{\mathrm{2}} }{{h}^{\mathrm{2}}…

prove-that-sin-2x-2h-sin-2x-2cos-2x-h-sin-h-

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Question Number 128130 by physicstutes last updated on 04/Jan/21 $prove that$ $\sin (2 x + 2 h) - \sin 2 x = 2 \cos (2 x + h) \sin h$ Answered by Olaf last updated on 04/Jan/21 $\sin a - \sin b = 2 \sin (\frac{a - b}{2}) \cos (\frac{a + b}{2}) (1)$ $${a}\:=\:\mathrm{2}{x}+\mathrm{2}{h}\:\mathrm{and}\:{b}\:=\:\mathrm{2}{x} \…

Category: Trigonometry