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Category: Trigonometry

Question-62347

Question Number 62347 by rajesh4661kumar@gamil.com last updated on 20/Jun/19 Answered by Kunal12588 last updated on 20/Jun/19 cscθsinθsecθcosθ=a3b3$$\Rightarrow{cot}\:\theta\:\frac{\mathrm{1}−{sin}^{\mathrm{2}} \theta}{\mathrm{1}−{cos}^{\mathrm{2}} \theta}=\frac{{a}^{\mathrm{3}} }{{b}^{\mathrm{3}} }…