Question Number 124501 by mnjuly1970 last updated on 03/Dec/20 $$\:\:\:\:\:\:\:\:\:\:….{nice}\:\:{calculus}.. \\ $$$$\:\:\:{in}\:{A}\overset{\Delta} {{B}C}\::\:{sin}^{\mathrm{2}} \left({A}\right)+{sin}^{\mathrm{2}} \left({B}\right)+{sin}^{\mathrm{2}} \left({C}\right)=\mathrm{2} \\ $$$${prove}\:{that}:\:{A}\overset{\Delta} {{B}C}\:{is}\:{right}\:{triangle} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\mathscr{G}{ood}\:{luck}. \\ $$ Answered by…
Question Number 189941 by Rupesh123 last updated on 24/Mar/23 Answered by Frix last updated on 24/Mar/23 $$\mathrm{2arctan}\:{x}\:+\mathrm{arctan}\:{y}\:=\mathrm{arctan}\:\frac{{x}^{\mathrm{2}} {y}−\mathrm{2}{x}−{y}}{{x}^{\mathrm{2}} +\mathrm{2}{xy}−\mathrm{1}} \\ $$$$\mathrm{answer}\:\mathrm{is}\:\mathrm{0} \\ $$ Commented by…
Question Number 124404 by benjo_mathlover last updated on 03/Dec/20 $${Find}\:{minimum}\:{value}\:{of}\:{function} \\ $$$${f}\left({x}\right)=\mathrm{sin}\:^{\mathrm{7}} \left({x}\right)+\mathrm{cos}\:^{\mathrm{11}} \left({x}\right) \\ $$ Commented by benjo_mathlover last updated on 03/Dec/20 Commented by…
Question Number 189897 by Mingma last updated on 23/Mar/23 Answered by mr W last updated on 24/Mar/23 $${a}^{\mathrm{2}} =\mathrm{cos}^{\mathrm{2}} \:{x}+\mathrm{4}\:\mathrm{sin}^{\mathrm{2}} \:{x} \\ $$$${b}^{\mathrm{2}} =\mathrm{4}\:\mathrm{cos}^{\mathrm{2}} \:{x}+\mathrm{1}+\mathrm{4}\:\mathrm{cos}^{\mathrm{2}}…
Question Number 189896 by Rupesh123 last updated on 23/Mar/23 Answered by HeferH last updated on 24/Mar/23 $$\frac{\mathrm{x}}{\mathrm{3}}\:=\:\frac{\mathrm{b}}{\mathrm{2}} \\ $$$$\frac{\mathrm{6}}{\mathrm{4}}\:=\:\frac{\mathrm{y}}{\mathrm{2}};\:\mathrm{y}\:=\:\mathrm{3}\: \\ $$$$\mathrm{b}\:=\:\sqrt{\mathrm{6}\centerdot\mathrm{3}−\mathrm{4}\centerdot\mathrm{2}}\:=\:\sqrt{\mathrm{10}} \\ $$$$\mathrm{x}\:=\:\frac{\mathrm{3}\sqrt{\mathrm{10}}}{\mathrm{2}} \\ $$…
Question Number 58776 by George Mark Samuel last updated on 29/Apr/19 $$\mathrm{81}^{{sin}^{\mathrm{2}} {x}} +\mathrm{81}^{{cos}^{\mathrm{2}} {x}} =\mathrm{30} \\ $$$$\mathrm{0}\leqslant{x}\leqslant\pi.{solve}\:{for}\:{x}. \\ $$ Answered by behi83417@gmail.com last updated…
Question Number 124309 by bemath last updated on 02/Dec/20 $$\:{If}\:\mathrm{sin}\:\theta+\mathrm{2cos}\:\theta=\mathrm{1}\:;\:{then}\: \\ $$$$\:\mathrm{2sin}\:\theta−\mathrm{cos}\:\theta=? \\ $$ Answered by MJS_new last updated on 02/Dec/20 $${t}=\mathrm{tan}\:\theta \\ $$$$\mathrm{sin}\:\theta\:+\mathrm{2cos}\:\theta\:=\frac{{t}+\mathrm{2}}{\:\sqrt{{t}^{\mathrm{2}} +\mathrm{1}}}=\mathrm{1}\:\Rightarrow\:{t}=−\frac{\mathrm{3}}{\mathrm{4}}…
Question Number 189665 by Rupesh123 last updated on 20/Mar/23 Answered by HeferH last updated on 20/Mar/23 $$\mathrm{AB}^{\mathrm{2}} \:=\:\mathrm{16}\centerdot\mathrm{9} \\ $$$$\mathrm{AB}\:=\:\mathrm{12} \\ $$ Commented by cortano12…
Question Number 189664 by Rupesh123 last updated on 20/Mar/23 Answered by BaliramKumar last updated on 20/Mar/23 $${tan}\mathrm{5}°{tan}\left(\mathrm{60}°−\mathrm{5}°\right){tan}\left(\mathrm{60}°+\mathrm{5}°\right){tan}\mathrm{75}° \\ $$$${tan}\left(\mathrm{3}×\mathrm{5}°\right){tan}\mathrm{75}° \\ $$$${tan}\mathrm{15}°{tan}\mathrm{75}° \\ $$$${tan}\mathrm{15}°{cot}\mathrm{15}°\:=\:\mathrm{1} \\ $$…
Question Number 58521 by malwaan last updated on 24/Apr/19 $$\boldsymbol{{sin}}\:\mathrm{16}^{°} \:=? \\ $$$$\boldsymbol{{cos}}\:\mathrm{16}^{°} \:=? \\ $$$$\boldsymbol{{without}}\:\boldsymbol{{using}}\:\boldsymbol{{cos}}\left(\mathrm{3}\theta\right) \\ $$$$\boldsymbol{{algebric}}\:\boldsymbol{{method}}\:\boldsymbol{{please}} \\ $$ Answered by tanmay last updated…