Question Number 126381 by liberty last updated on 20/Dec/20 $$\:\mathrm{arctan}\:\mathrm{1}\:+\:\mathrm{arctan}\:\mathrm{2}\:+\:\mathrm{arctan}\:\mathrm{3}\:=? \\ $$ Answered by benjo_mathlover last updated on 20/Dec/20 $$\left(\bullet\right)\:\mathrm{arctan}\:\mathrm{1}+\mathrm{arctan}\:\mathrm{2}=\mathrm{arctan}\:\left(\frac{\mathrm{1}+\mathrm{2}}{\mathrm{1}−\mathrm{1}.\mathrm{2}}\right) \\ $$$$\:\mathrm{arctan}\:\left(−\mathrm{3}\right) \\ $$$$\left(\bullet\bullet\right)\:\mathrm{arctan}\:\left(−\mathrm{3}\right)+\mathrm{arctan}\:\left(\mathrm{3}\right)=\mathrm{arctan}\:\left(\frac{−\mathrm{3}+\mathrm{3}}{\mathrm{1}−\left(−\mathrm{3}\right)\left(\mathrm{3}\right)}\right) \\…
Question Number 191901 by mehdee42 last updated on 03/May/23 $${if}\:\:\mathrm{0}<\theta<\mathrm{45}^{\mathrm{0}} \:\:{which}\:{is}\:{bigger}\:? \\ $$$$\mathrm{2}{tan}\theta\:\:{or}\:\:{tan}\mathrm{2}\theta \\ $$ Answered by mr W last updated on 03/May/23 Commented by…
Question Number 60814 by Forkum Michael Choungong last updated on 26/May/19 $${find}\:{x}\:{given}\:{that} \\ $$$$\mathrm{9}^{{sin}^{\mathrm{2}} {x}} +\mathrm{9}^{{cos}^{\mathrm{2}} {x}} =\mathrm{2}\: \\ $$$$ \\ $$ Answered by $@ty@m…
Question Number 191804 by Shlock last updated on 30/Apr/23 Commented by Shlock last updated on 30/Apr/23 x=? Commented by AST last updated on 30/Apr/23 $${It}\:{follows}\:{from}\:{sin}^{\mathrm{2}}…
Question Number 126148 by Study last updated on 17/Dec/20 $${A},{B},{C}\:{and}\:{D}\:{are}\:{angles}\:{of}\:{tetragon} \\ $$$${if}\:{A}+{D}=\mathrm{240}^{°\:} \:,\:\:\:{C}+{D}=\mathrm{200}{g} \\ $$$${B}+{D}=\frac{\mathrm{2}\pi}{\mathrm{3}}\:\:\:,\:{find}\:{D}=??? \\ $$ Answered by mahdipoor last updated on 17/Dec/20 $${A}+{B}+{C}+{D}=\mathrm{360}^{°}…
Question Number 60536 by hovea cw last updated on 21/May/19 $$\mathrm{cosx}=\mathrm{sin3x} \\ $$$$\mathrm{find}\:\mathrm{x}\:\mathrm{with}\:\mathrm{solution}\:\: \\ $$$$\mathrm{pllllllz} \\ $$ Answered by mr W last updated on 21/May/19…
Question Number 191597 by Linton last updated on 26/Apr/23 $${Prove} \\ $$$$ \\ $$$$\mathrm{H}_{{x}} \:\rightarrow\:\mathrm{cot}\:\left(\:\mathrm{x}\:\right)\: \\ $$$$\mathrm{x}!\rightarrow\:\:\mathrm{sin}\:\left(\:\mathrm{x}\:\right) \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 126005 by bramlexs22 last updated on 16/Dec/20 $$\:\:{Find}\:{all}\:{solution}\:\mathrm{7cos}\:\left(\mathrm{3}{x}\right)−\mathrm{1}=\:\mathrm{3}\: \\ $$$${for}\:{x}\:{over}\:{the}\:{interval}\:\left[\:\mathrm{0},\mathrm{2}\pi\:\right]\: \\ $$ Commented by liberty last updated on 16/Dec/20 $$\:\mathrm{7}\:\mathrm{cos}\:\left(\mathrm{3}{x}\right)=\mathrm{4}\:\Rightarrow\mathrm{cos}\:\left(\mathrm{3}{x}\right)=\frac{\mathrm{4}}{\mathrm{7}}\: \\ $$$$\:\mathrm{3}{x}\:=\:\mathrm{cos}^{−\mathrm{1}} \left(\frac{\mathrm{4}}{\mathrm{7}}\right)\:=\:\mathrm{0}.\mathrm{963}…
Question Number 125993 by bramlexs22 last updated on 16/Dec/20 $${Determine}\:{the}\:{amplitudo},\:{the} \\ $$$${period}\:,\:{the}\:{phase}\:{shift}\:{and}\:{the} \\ $$$${midline}\:{of}\:{the}\:{function}\: \\ $$$${f}\left({x}\right)\:=\:\frac{\mathrm{1}}{\mathrm{2}}−\mathrm{sin}\:\left(\frac{\mathrm{1}}{\mathrm{2}}{x}+\frac{\pi}{\mathrm{2}}\right) \\ $$ Answered by liberty last updated on 16/Dec/20…
Question Number 191477 by Spillover last updated on 24/Apr/23 $$\mathrm{Prove}\:\mathrm{that} \\ $$$$ \\ $$$$\frac{\mathrm{tan}\:\mathrm{y}+\mathrm{sec}\:\mathrm{y}−\mathrm{1}}{\mathrm{tan}\:\mathrm{y}−\mathrm{sec}\:\mathrm{y}+\mathrm{1}}=\mathrm{tan}\:\mathrm{y}+\mathrm{sec}\:\mathrm{y} \\ $$$$ \\ $$ Answered by ARUNG_Brandon_MBU last updated on 24/Apr/23…