Question Number 188589 by Rupesh123 last updated on 03/Mar/23 Commented by universe last updated on 03/Mar/23 $${Question}\:{no}\:\mathrm{188339} \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 57474 by malwaan last updated on 05/Apr/19 $$\mathrm{prove}\: \\ $$$$\boldsymbol{{sin}}\mathrm{18}×\boldsymbol{{cos}}\mathrm{36}=\frac{\mathrm{1}}{\mathrm{4}} \\ $$ Commented by Abdo msup. last updated on 05/Apr/19 $$\mathrm{18}\rightarrow{x} \\ $$$$\mathrm{180}\rightarrow\pi\:\Rightarrow\mathrm{180}{x}\:=\mathrm{18}\pi\:\Rightarrow{x}\:=\frac{\pi}{\mathrm{10}}\:\Rightarrow\mathrm{36}\:=\frac{\pi}{\mathrm{5}}…
Question Number 57469 by olalekan2 last updated on 05/Apr/19 $$\frac{\mathrm{4}{tan}\mathrm{75}}{\mathrm{1}−{tan}^{\mathrm{2}} \mathrm{75}}=\frac{\mathrm{1}}{{cos}\mathrm{150}}\: \\ $$$${find}\:{tan}\mathrm{75}\:{in}\:{surd}\:{form} \\ $$ Commented by kaivan.ahmadi last updated on 05/Apr/19 $${if}\:{you}\:{want}\:{to}\:{find}\:{tv}\mathrm{75} \\ $$$${you}\:{can}\:{solve}:…
Question Number 188475 by cortano12 last updated on 02/Mar/23 $$\:\:\mathrm{sin}\:\left(\frac{\pi}{\mathrm{2}}\left(\mathrm{4x}+\sqrt{\mathrm{x}}\:\right)\right)\mathrm{cos}\:\left(\pi\left(\mathrm{x}+\mathrm{7}\sqrt{\mathrm{x}}\right)\right)=\mathrm{1} \\ $$$$\:\mathrm{x}=? \\ $$ Answered by Frix last updated on 02/Mar/23 $$\mathrm{sin}\:\alpha\:\mathrm{sin}\:\beta\:=\mathrm{1} \\ $$$$\Leftrightarrow \\…
Question Number 57383 by Tinkutara last updated on 03/Apr/19 Commented by Tinkutara last updated on 03/Apr/19 B part Answered by tanmay.chaudhury50@gmail.com last updated on 03/Apr/19 $${cos}^{−\mathrm{1}}…
Question Number 57373 by gunawan last updated on 03/Apr/19 $$\mathrm{tan}\:\mathrm{1}°+\mathrm{tan}\:\mathrm{5}°+\mathrm{tan}\:\mathrm{9}°+\ldots+\mathrm{tan}\:\mathrm{177}°=… \\ $$ Commented by mr W last updated on 03/Apr/19 $$=\mathrm{45} \\ $$ Answered by…
Question Number 188376 by Rupesh123 last updated on 28/Feb/23 Answered by Frix last updated on 28/Feb/23 $$\mathrm{sin}\:\frac{\mathrm{3}\pi}{\mathrm{7}}\:\mathrm{sin}\:\frac{\mathrm{2}\pi}{\mathrm{7}}\:\mathrm{sin}\:\frac{\pi}{\mathrm{7}}\:= \\ $$$$=\frac{\mathrm{1}}{\mathrm{4}}\left(\mathrm{sin}\:\frac{\mathrm{3}\pi}{\mathrm{7}}\:+\mathrm{sin}\:\frac{\mathrm{2}\pi}{\mathrm{7}}\:−\mathrm{sin}\:\frac{\pi}{\mathrm{7}}\right) \\ $$$$\left(\mathrm{sin}\:\frac{\mathrm{3}\pi}{\mathrm{7}}\:\mathrm{sin}\:\frac{\mathrm{2}\pi}{\mathrm{7}}\:\mathrm{sin}\:\frac{\pi}{\mathrm{7}}\right)^{\mathrm{3}} = \\ $$$$=\frac{\mathrm{7}}{\mathrm{256}}\left(\mathrm{sin}\:\frac{\mathrm{3}\pi}{\mathrm{7}}\:+\mathrm{sin}\:\frac{\mathrm{2}\pi}{\mathrm{7}}\:−\mathrm{sin}\:\frac{\pi}{\mathrm{7}}\right) \\…
Question Number 57269 by rahul 19 last updated on 01/Apr/19 $${If}\:{A}>\mathrm{0},{B}>\mathrm{0},\:{and}\:{A}+{B}=\frac{\pi}{\mathrm{3}}\:,\:{then} \\ $$$${maximum}\:{value}\:{of}\:{tanAtanB}\:{is}\:? \\ $$ Commented by rahul 19 last updated on 01/Apr/19 $${Any}\:{short}\:{method}\:? \\…
Question Number 188281 by mathlove last updated on 27/Feb/23 $$\left.\mathrm{1}\right)\:\:\frac{\mathrm{18}{log}\mathrm{10000}+\sqrt{\mathrm{43}{x}}}{\mathrm{12}} \\ $$$$\left.\mathrm{2}\right)\:\frac{\sqrt{\mathrm{43}{x}}}{\mathrm{18}{log}\mathrm{1000}} \\ $$$$\left.\mathrm{3}\right)\:\:\mathrm{18}{log}\mathrm{10000}+\sqrt{\mathrm{43}{x}}\:\:\: \\ $$$$\left.\mathrm{4}\right)\:\:\:\frac{\mathrm{18}{log}\mathrm{10000}}{\:\sqrt{\mathrm{43}{x}}} \\ $$$$\left.\mathrm{5}\right)\:\:\:{log}\left({sinx}\right)+{sin}\left({log}\mathrm{100}\right) \\ $$$$\left.\mathrm{6}\right)\:\:\:{log}\left({sinx}\right)+\mathrm{12} \\ $$$$\left.\mathrm{7}\right)\:\:\:\sqrt{{x}^{\mathrm{2}} −{x}+\mathrm{90}} \\ $$$$\left.\mathrm{8}\right)\:\:{log}\left({sin}\frac{\pi}{\mathrm{4}}\right)+\frac{\mathrm{1}}{\:\sqrt{\mathrm{5}}}…
Question Number 188209 by Rupesh123 last updated on 26/Feb/23 Answered by Ezzat last updated on 26/Feb/23 $$\left(\mathrm{2}\:{R}\:{sinB}\:\right)^{\mathrm{2}} .{sin}^{\mathrm{2}} \left({A}\right)−\left(\:\mathrm{2}\:{R}\:{sinA}\right)^{\mathrm{2}} \:{sin}^{\mathrm{2}} {B}\:=\mathrm{48}\:−{a}^{\mathrm{2}} \\ $$$$\mathrm{4}\:{R}^{\mathrm{2}} \:{sin}^{\mathrm{2}} {B}\:.{sin}^{\mathrm{2}}…