Category: Trigonometry

Question Number 57469 by olalekan2 last updated on 05/Apr/19 $$\frac{4tan75}{1-{tan}^{2}75}=\frac{1}{cos150}$$$$findtan75insurdform$$ Commented by kaivan.ahmadi last updated on 05/Apr/19 $$ifyouwanttofindtv75$$$${you}\:{can}\:{solve}:…

Question Number 57383 by Tinkutara last updated on 03/Apr/19 Commented by Tinkutara last updated on 03/Apr/19 B part Answered by tanmay.chaudhury50@gmail.com last updated on 03/Apr/19 $${cos}^{−\mathrm{1}}…

Question Number 188376 by Rupesh123 last updated on 28/Feb/23 Answered by Frix last updated on 28/Feb/23 $$\sin \frac{3\pi }{7}\sin \frac{2\pi }{7}\sin \frac{\pi }{7}=$$$$=\frac{1}{4}(\sin \frac{3\pi }{7}+\sin \frac{2\pi }{7}-\sin \frac{\pi }{7})$$$${\left(\sin \frac{3\pi }{7}\sin \frac{2\pi }{7}\sin \frac{\pi }{7}\right)}^3=$$$$=\frac{\mathrm{7}}{\mathrm{256}}\left(\mathrm{sin}\:\frac{\mathrm{3}\pi}{\mathrm{7}}\:+\mathrm{sin}\:\frac{\mathrm{2}\pi}{\mathrm{7}}\:−\mathrm{sin}\:\frac{\pi}{\mathrm{7}}\right) \…

Question Number 188281 by mathlove last updated on 27/Feb/23 $$1)\frac{18log10000+\sqrt{43x}}{12}$$$$2)\frac{\sqrt{43x}}{18log1000}$$$$3)18log10000+\sqrt{43x}$$$$4)\frac{18log10000}{\sqrt{43x}}$$$$5)log\left(sinx\right)+sin\left(log100\right)$$$$6)log\left(sinx\right)+12$$$$7)\sqrt{x^2-x+90}$$$$\left.\mathrm{8}\right)\:\:{log}\left({sin}\frac{\pi}{\mathrm{4}}\right)+\frac{\mathrm{1}}{\:\sqrt{\mathrm{5}}}…

Question Number 188128 by Rupesh123 last updated on 26/Feb/23 Answered by mr W last updated on 26/Feb/23 $$WLG,assumea⩽b⩽c.$$$$\cos C=\frac{a^2+b^2-c^2}{2ab}$$$$\mathrm{2}{b}×\mathrm{cos}\:{C}=\frac{{a}^{\mathrm{2}}…