Category: Trigonometry

Question Number 120789 by abdelsalamalmukasabe last updated on 02/Nov/20 Terms of Service Privacy Policy Contact: info@tinkutara.com

Question Number 55141 by 0201011563081 last updated on 18/Feb/19 $$provethefollowingidentities$$$$$$$$a.\frac{\sin \theta }{1+\cos 2\theta }=\tan \theta$$$$b.\frac{1-\cos 2\theta -\sin \theta }{\sin 2\theta -\cos \theta }=\tan \theta$$$$c.\frac{\cos (x+y)+\sin (x-y)}{\cos 2y\cos 2x}=\frac{1}{\cos (x+y)\sin (y-x)}$$ Commented by math1967 last updated…

Question Number 120614 by TANMAY PANACEA last updated on 01/Nov/20 $$Trigonometry$$ Commented by TANMAY PANACEA last updated on 01/Nov/20 Commented by TANMAY PANACEA…

Question Number 186125 by Mingma last updated on 01/Feb/23 Answered by som(math1967) last updated on 01/Feb/23 $$let{2}^{sin\alpha }=3^{sin\beta }=5^{sin\theta }=k$$$$\Rightarrow{k}^{\frac{\mathrm{1}}{{sin}\alpha}} =\mathrm{2}\Rightarrow{k}^{{cosec}\alpha} =\mathrm{2} \…

Question Number 120551 by bobhans last updated on 01/Nov/20 $$\frac{1}{\sqrt{3}-\tan \mathrm{x}}-\frac{1}{\sqrt{3}+\tan \mathrm{x}}=\sin 2\mathrm{x}$$ Answered by john santu last updated on 01/Nov/20 $$recallthat\sin 2x=\frac{2\tan x}{1+\tan {}^{2}x}$$$$\Leftrightarrow\:\frac{\mathrm{1}}{\:\sqrt{\mathrm{3}}−\mathrm{tan}\:{x}}−\frac{\mathrm{1}}{\:\sqrt{\mathrm{3}}+\mathrm{tan}\:{x}}\:=\:\frac{\mathrm{2tan}\:{x}}{\mathrm{1}+\mathrm{tan}\:^{\mathrm{2}} {x}}…