Category: Trigonometry

Question Number 120551 by bobhans last updated on 01/Nov/20 $$\frac{1}{\sqrt{3}-\tan \mathrm{x}}-\frac{1}{\sqrt{3}+\tan \mathrm{x}}=\sin 2\mathrm{x}$$ Answered by john santu last updated on 01/Nov/20 $$recallthat\sin 2x=\frac{2\tan x}{1+\tan {}^{2}x}$$$$\Leftrightarrow\:\frac{\mathrm{1}}{\:\sqrt{\mathrm{3}}−\mathrm{tan}\:{x}}−\frac{\mathrm{1}}{\:\sqrt{\mathrm{3}}+\mathrm{tan}\:{x}}\:=\:\frac{\mathrm{2tan}\:{x}}{\mathrm{1}+\mathrm{tan}\:^{\mathrm{2}} {x}}…

Question Number 185960 by Michaelfaraday last updated on 30/Jan/23 $$solve:$$$$\text{Missing left or extra right}$$$$findx$$ Answered by Frix last updated on 30/Jan/23 $$\mathrm{We}\:\mathrm{can}\:\mathrm{only}\:\mathrm{approximate}.…

Question Number 185861 by cortano1 last updated on 29/Jan/23 $$\cos \left(\frac{2\pi }{13}\right)+\cos \left(\frac{6\pi }{13}\right)+\cos \left(\frac{8\pi }{13}\right)=?$$ Commented by Frix last updated on 29/Jan/23 $$\frac{-1+\sqrt{13}}{4}$$ Commented by cortano1…

Question Number 185821 by Rupesh123 last updated on 28/Jan/23 Answered by qaz last updated on 28/Jan/23 $$5\arctan \frac{1}{7}+2\arctan \frac{3}{79}=5Arg(7+i)+2Arg(79+3i)$$$$=Arg[{(7+i)}^5\cdot {(79+3i)}^2]=Arg\left[78125000(1+i)\right]$$$$=\arctan \frac{78125000}{78125000}=\frac{\pi }{4}$$…

Question Number 54721 by 951172235v last updated on 09/Feb/19 $$\mathrm{Show}\mathrm{that}$$$$\frac{\mathrm{\Sigma }\left\{\sin 2\mathrm{xtan}(\mathrm{y}-\mathrm{z})\cos {}^2(\mathrm{y}+\mathrm{z})\right\}}{\mathrm{\Sigma }\left\{\cos 2\mathrm{xtan}(\mathrm{y}-\mathrm{z})\sin {}^2(\mathrm{y}+\mathrm{z})\right\}}=\tan 2\mathrm{xtan}2\mathrm{ytan}2\mathrm{z}$$ Terms of Service Privacy Policy Contact: info@tinkutara.com