Question Number 185647 by Mingma last updated on 24/Jan/23 Answered by mahdipoor last updated on 24/Jan/23 $${secx}+{tan}^{\mathrm{3}} {x}.{cscx}=\frac{\mathrm{1}}{{cosx}}+\frac{{sin}^{\mathrm{2}} {x}}{{cos}^{\mathrm{3}} {x}}=\frac{{cos}^{\mathrm{2}} {x}+{sin}^{\mathrm{2}} {x}}{{cos}^{\mathrm{3}} {x}}= \\ $$$$\frac{\mathrm{1}}{{cos}^{\mathrm{3}}…
Question Number 54563 by 951172235v last updated on 06/Feb/19 $$\mathrm{If}\:\frac{\mathrm{sin}\:^{\mathrm{3}} \alpha}{\mathrm{sin}\:\beta}\:+\:\frac{\mathrm{cos}\:^{\mathrm{3}} \alpha}{\mathrm{cos}\:\beta}\:=\:\mathrm{1}\:\mathrm{show}\:\mathrm{that} \\ $$$$\mathrm{sin}\:\mathrm{2}\alpha+\mathrm{2sin}\:\left(\alpha+\beta\right)=\mathrm{0} \\ $$ Commented by tanmay.chaudhury50@gmail.com last updated on 06/Feb/19 $$\frac{{sin}^{\mathrm{3}} \alpha}{{sin}\beta}+\frac{{cos}^{\mathrm{3}}…
Question Number 54537 by hsbebeb last updated on 05/Feb/19 $${tan}^{\mathrm{2}} \mathrm{20}+{tan}^{\mathrm{2}} \mathrm{40}+{tan}^{\mathrm{2}} \mathrm{80}=\mathrm{33}\:\:\: \\ $$$$\left({please}\:{solve}\:{this}\:{and}\:{i}\:{want}\:{to}\:{know}\:\right. \\ $$$$\left.{that}\:{which}\:{standard}\:{that}\:{question}\:{belongs}?\right) \\ $$$${help}\:{needed} \\ $$ Commented by tanmay.chaudhury50@gmail.com last…
Question Number 54536 by 951172235v last updated on 05/Feb/19 $$\mathrm{If}\:\mathrm{A},\mathrm{B},\mathrm{C}\:\mathrm{are}\:\mathrm{angles}\:\mathrm{of}\:\mathrm{a}\:\mathrm{triangle}\:\mathrm{show}\:\mathrm{that} \\ $$$$\mathrm{tan}^{−\mathrm{1}} \left(\mathrm{cot}\:\mathrm{Acot}\:\mathrm{B}\right)+\mathrm{tan}^{−\mathrm{1}} \left(\mathrm{cot}\:\mathrm{Bcot}\:\mathrm{C}\right)+\mathrm{tan}^{−\mathrm{1}} \left(\mathrm{cot}\:\mathrm{Ccot}\:\mathrm{A}\right) \\ $$$$=\:\mathrm{tan}^{−\mathrm{1}} \left\{\mathrm{1}+\frac{\mathrm{8cos}\:\mathrm{Acos}\:\mathrm{Bcos}\:\mathrm{C}}{\mathrm{sin}\:^{\mathrm{2}} \mathrm{2A}+\mathrm{sin}\:^{\mathrm{2}} \mathrm{2B}+\mathrm{sin}\:^{\mathrm{2}} \mathrm{2C}}\right\} \\ $$ Answered by…
Question Number 185597 by Rupesh123 last updated on 24/Jan/23 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 120029 by Ar Brandon last updated on 28/Oct/20 $$\mathrm{Montrer}\:\mathrm{que}\:\forall\mathrm{x}\in\mathbb{R} \\ $$$$\mathrm{cos}\left(\mathrm{sinx}\right)>\mathrm{sin}\left(\mathrm{cosx}\right) \\ $$ Commented by soumyasaha last updated on 29/Oct/20 $$\:\:\:\:\pi/\mathrm{2}\:\approx\:\mathrm{1}.\mathrm{57}\:\:\:\mathrm{and}\:\sqrt{\mathrm{2}}\:\approx\:\mathrm{1}.\mathrm{41} \\ $$$$\:\:\therefore\:\sqrt{\mathrm{2}}\:<\:\pi/\mathrm{2}…
Question Number 54480 by 951172235v last updated on 04/Feb/19 $$\mathrm{show}\:\mathrm{that} \\ $$$$\mathrm{tan}\:\alpha\:+\mathrm{tan}\:\left(\alpha+\frac{\mathrm{2}\overset{−} {\Lambda}}{\mathrm{5}}\right)\:+\mathrm{tan}\:\left(\alpha+\frac{\mathrm{4}\overset{−} {\Lambda}}{\mathrm{5}}\right)\:+\mathrm{tan}\:\left(\alpha+\frac{\mathrm{6}\overset{−} {\Lambda}}{\mathrm{5}}\right)\:+\:\mathrm{tan}\:\left(\alpha+\frac{\mathrm{8}\overset{−} {\Lambda}}{\mathrm{5}}\right)\:=\:\mathrm{5tan}\:\mathrm{5}\alpha \\ $$ Answered by tanmay.chaudhury50@gmail.com last updated on 05/Feb/19…
Question Number 54472 by Tawa1 last updated on 04/Feb/19 $$\mathrm{If}\:\mathrm{A},\:\mathrm{B},\:\mathrm{C}\:\:\mathrm{are}\:\mathrm{angle}\:\mathrm{of}\:\mathrm{a}\:\mathrm{triangle},\:\:\mathrm{show}\:\mathrm{that} \\ $$$$\:\:\:\mathrm{tanA}\:+\:\mathrm{tanB}\:+\:\mathrm{tanC}\:\:=\:\:\mathrm{tanA}\:\mathrm{tanB}\:\mathrm{tanC} \\ $$ Answered by math1967 last updated on 04/Feb/19 $${A}+{B}+{C}=\pi \\ $$$$\Rightarrow{A}+{B}=\pi−{C} \\…
Question Number 185523 by Rupesh123 last updated on 23/Jan/23 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 185511 by mathlove last updated on 23/Jan/23 Answered by Frix last updated on 23/Jan/23 $$\frac{\mathrm{1}}{\mathrm{2}−\sqrt{\mathrm{3}}}=\mathrm{2}+\sqrt{\mathrm{3}}={t} \\ $$$${t}^{−\mathrm{cos}\:{x}} ={t}^{\mathrm{sin}\:{x}} \\ $$$$−\mathrm{cos}\:{x}\:=\mathrm{sin}\:{x} \\ $$$$\frac{\mathrm{cos}\:{x}}{\mathrm{sin}\:{x}}=−\mathrm{1} \\…