Category: Trigonometry

Question Number 185732 by Rupesh123 last updated on 26/Jan/23 Answered by witcher3 last updated on 26/Jan/23 $$\mathrm{tg}\left(\mathrm{a}\right)-\mathrm{tg}\left(\mathrm{b}\right)=\frac{\sin (\mathrm{a}-\mathrm{b})}{\cos \left(\mathrm{a}\right)\cos \left(\mathrm{b}\right)}$$$$\mathrm{tg}\left(50\right)-\mathrm{tg}\left(40\right)=\frac{\sin \left(10\right)}{\cos \left(40\right)\cos \left(50\right)}$$$$\iff \frac{\cos \left(10\right)}{\cos \left(40\right)\cos \left(50\right)}=\frac{\cos \left(10\right)}{\cos \left(40\right)\sin \left(40\right)}=2\frac{\cos \left(10\right)}{2\cos \left(40\right)\sin \left(40\right)}$$$$=\frac{2\cos \left(10\right)}{\sin \left(80\right)}=2$$…

Question Number 54626 by Aditya789 last updated on 08/Feb/19 $$\frac{1+\mathrm{sinx}+\mathrm{cox}}{1+\mathrm{sinx}-\mathrm{cosx}}=\frac{1-\mathrm{cosx}}{1+\mathrm{cosx}}$$ Answered by tanmay.chaudhury50@gmail.com last updated on 08/Feb/19 $$LHS$$$$\frac{\mathrm{2}{cos}^{\mathrm{2}} \frac{{x}}{\mathrm{2}}+\mathrm{2}{sin}\frac{{x}}{\mathrm{2}}{cos}\frac{{x}}{\mathrm{2}}}{\mathrm{2}{sin}^{\mathrm{2}} \frac{{x}}{\mathrm{2}}+\mathrm{2}{sin}\frac{{x}}{\mathrm{2}}{cos}\frac{{x}}{\mathrm{2}}} \…

Question Number 185647 by Mingma last updated on 24/Jan/23 Answered by mahdipoor last updated on 24/Jan/23 $$secx+{tan}^{3}x.cscx=\frac{1}{cosx}+\frac{{sin}^{2}x}{{cos}^{3}x}=\frac{{cos}^{2}x+{sin}^{2}x}{{cos}^{3}x}=$$$$\frac{\mathrm{1}}{{cos}^{\mathrm{3}}…

Question Number 54537 by hsbebeb last updated on 05/Feb/19 $${tan}^{2}20+{tan}^{2}40+{tan}^{2}80=33$$$$(pleasesolvethisandiwanttoknow$$$$thatwhichstandardthatquestionbelongs?)$$$$helpneeded$$ Commented by tanmay.chaudhury50@gmail.com last…

Question Number 185597 by Rupesh123 last updated on 24/Jan/23 Terms of Service Privacy Policy Contact: info@tinkutara.com