Category: Trigonometry

Question Number 211609 by MATHEMATICSAM last updated on 14/Sep/24 $$\mathrm{Prove}\mathrm{that},\mathrm{in}\mathrm{a}\mathrm{triangle}\mathrm{the}\mathrm{ratios}\mathrm{of}\mathrm{the}$$$$\mathrm{sides}\mathrm{and}\mathrm{the}\mathrm{sine}\mathrm{of}\mathrm{the}\mathrm{opposite}\mathrm{angles}$$$$\mathrm{are}\mathrm{equal}.\mathrm{Also}\mathrm{prove}\mathrm{that}\mathrm{each}\mathrm{ratio}\mathrm{is}$$$$\mathrm{equal}\mathrm{to}\mathrm{the}\mathrm{diameter}\mathrm{of}\mathrm{the}\mathrm{circum}\mathrm{circle}$$$$\mathrm{of}\mathrm{the}\mathrm{triangle}.$$ Answered by Frix last updated…

Question Number 211496 by RojaTaniya last updated on 11/Sep/24 Answered by som(math1967) last updated on 11/Sep/24 $$\frac{1}{2}(2sin20sin40+2sin20sin60+2sin20sin80)$$$$=\frac{1}{2}(cos20-cos60+cos40-cos80+cos60-cos100)$$$$\frac{1}{2}(cos20+cos40-cos80+cos80)$$$$=\frac{1}{2}\times 2cos30cos10$$$$={sin}\mathrm{60}{sin}\mathrm{80}…

Question Number 211345 by a.lgnaoui last updated on 06/Sep/24 $$\mathrm{E}\mathbf{valuer}:\frac{\mathbf{R}}{\mathbf{r}1+\mathbf{r}2}$$ Commented by a.lgnaoui last updated on 06/Sep/24 Terms of Service Privacy Policy Contact:…

Question Number 211115 by Durganand last updated on 28/Aug/24 Answered by som(math1967) last updated on 28/Aug/24 $$tanA+2tan2A+\frac{4}{tan2.2A}$$$$=tanA+2tan2A+\frac{4(1-{tan}^{2}2A)}{2tan2A}$$$$={tanA}+\frac{\mathrm{2}{tan}^{\mathrm{2}} \mathrm{2}{A}+\mathrm{2}−\mathrm{2}{tan}^{\mathrm{2}} \mathrm{2}{A}}{{tan}\mathrm{2}{A}}\: \…

Question Number 210926 by maths_plus last updated on 22/Aug/24 $$\mathrm{valeur}\mathrm{de}:$$$${\tan }^2\left(\frac{\pi }{7}\right)+{\tan }^2\left(\frac{2\pi }{7}\right)+{\tan }^2\left(\frac{3\pi }{7}\right)=???$$ Commented by mr W last updated on 22/Aug/24…