Category: Trigonometry

Question Number 46472 by peter frank last updated on 27/Oct/18 Answered by tanmay.chaudhury50@gmail.com last updated on 27/Oct/18 $${(asin\theta +bcos\theta )}^2=c^2$$$${a}^{\mathrm{2}} {sin}^{\mathrm{2}} \theta+{b}^{\mathrm{2}} {cos}^{\mathrm{2}} \theta+\mathrm{2}{absin}\theta{cos}\theta={c}^{\mathrm{2}}…

Question Number 177507 by peter frank last updated on 06/Oct/22 $$\mathrm{The}\mathrm{angle}\mathrm{of}\mathrm{elevetion}\mathrm{of}\mathrm{the}$$$$\mathrm{top}\mathrm{of}\mathrm{a}\mathrm{tower}\mathrm{from}\mathrm{a}\mathrm{point}$$$$\mathrm{A}\mathrm{in}\mathrm{the}\mathrm{north}\mathrm{is}\alpha \mathrm{and}\mathrm{the}$$$$\mathrm{angle}\mathrm{of}\mathrm{the}\mathrm{top}\mathrm{of}\mathrm{the}\mathrm{tower}$$$$\mathrm{from}\mathrm{the}\mathrm{point}\mathrm{B}\mathrm{in}\mathrm{the}\mathrm{east}\mathrm{of}\mathrm{the}\mathrm{point}$$$$\mathrm{A}\mathrm{is}\beta .\mathrm{prove}\mathrm{that}\mathrm{the}\mathrm{height}$$$$\mathrm{of}\mathrm{the}\mathrm{tower}\mathrm{is}$$$$\frac{\mathrm{ABsin}\:\alpha\mathrm{sin}\:\mathrm{B}}{\:\sqrt{\mathrm{sin}\:^{\mathrm{2}}…

Question Number 46277 by rahul 19 last updated on 23/Oct/18 Commented by rahul 19 last updated on 23/Oct/18 $$thisispossibleonlywhensin3x=1$$$$andsin7x=1\dots \dots$$$$\dots ..$$…

Question Number 111725 by Aina Samuel Temidayo last updated on 04/Sep/20 $$\mathrm{Find}\mathrm{the}\mathrm{positive}\mathrm{integer}\mathrm{n}\mathrm{such}\mathrm{that}$$$${\tan }^{-1}\left(\frac{1}{3}\right)+{\tan }^{-1}\left(\frac{1}{4}\right)+{\tan }^{-1}\left(\frac{1}{5}\right)+{\tan }^{-1}\left(\frac{1}{\mathrm{n}}\right)=\frac{\pi }{4}$$ Answered by $@y@m last updated…

Question Number 111426 by weltr last updated on 03/Sep/20 Answered by Dwaipayan Shikari last updated on 03/Sep/20 $$4({sin}^6\alpha +{cos}^6\alpha )-3{cos}^{2}2\alpha$$$$=\mathrm{4}\left({sin}^{\mathrm{2}} \alpha+{cos}^{\mathrm{2}} \alpha\right)^{\mathrm{3}}…