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Category: Trigonometry

A-motorist-travelled-from-A-to-B-This-is-a-distance-of-142km-at-an-average-speed-of-60kmhr-1-He-spent-5-2hours-in-B-and-then-returned-to-A-at-an-average-speed-of-80kmh-1-a-At-what-time-did-t

Question Number 45085 by Necxx last updated on 08/Oct/18 $${A}\:{motorist}\:{travelled}\:{from}\:{A}\:{to}\:{B}. \\ $$$${This}\:{is}\:{a}\:{distance}\:{of}\:\mathrm{142}{km}\:{at}\:{an} \\ $$$${average}\:{speed}\:{of}\:\mathrm{60}{kmhr}^{−\mathrm{1}} .{He} \\ $$$${spent}\:\mathrm{5}/\mathrm{2}{hours}\:{in}\:{B}\:{and}\:{then} \\ $$$${returned}\:{to}\:{A}\:{at}\:{an}\:{average}\:{speed} \\ $$$${of}\:\mathrm{80}{kmh}^{−\mathrm{1}} . \\ $$$$\left.{a}\right){At}\:{what}\:{time}\:{did}\:{the}\:{man}\:{arrive} \\…

in-AB-C-prove-that-sin-2A-sin-2B-sin-2C-cos-A-2-cos-B-2-cos-C-2-

Question Number 176140 by mnjuly1970 last updated on 13/Sep/22 $$ \\ $$$$\:\:\:{in}\:{A}\overset{\Delta} {{B}C}\:,\:{prove}\:{that}: \\ $$$$\:\:{sin}\left(\mathrm{2}{A}\right)+{sin}\left(\mathrm{2}{B}\right)+{sin}\left(\mathrm{2}{C}\right)\: \\ $$$$\leqslant{cos}\:\left(\frac{{A}}{\mathrm{2}}\right)\:+\:{cos}\:\left(\frac{{B}}{\mathrm{2}}\right)+{cos}\left(\frac{{C}}{\mathrm{2}}\right) \\ $$$$ \\ $$ Terms of Service Privacy…

AOB-triangle-equilareral-de-cote-a-A-B-centres-de-cercles-de-rayon-r-GOH-EF-a-0-Determiner-l-aire-de-l-espace-delimite-par-AFOEBHG-comme-il-est-marque-sur-l-image-ci-joint-en-fonct

Question Number 176092 by a.lgnaoui last updated on 12/Sep/22 $$\angle{AOB}\:\:\:{triangle}\:{equilareral}\:{de}\:{cote}\:\boldsymbol{{a}} \\ $$$$\left({A};\mathrm{B}\right)\::\:\mathrm{c}{e}\mathrm{ntres}\:\mathrm{de}\:\mathrm{cercles}\:\mathrm{de}\:\mathrm{rayon}\:\boldsymbol{\mathrm{r}} \\ $$$$\boldsymbol{\theta}\:=\measuredangle\:\:{GOH}\:\:\:\mathrm{EF}=\boldsymbol{{a}}_{\mathrm{0}} \\ $$$${Determiner}\:{l}\:{aire}\:{de}\:{l}\:{espace}\:{delimite}\:{par} \\ $$$$\:\:\boldsymbol{\mathrm{AFOEBHG}}\:{comme}\:{il}\:{est}\:{marque}\:{sur}\:{l}\:{image}\:{ci}−{joint}\: \\ $$$${en}\:{fonction}\:{de}:\:\boldsymbol{{a}},\boldsymbol{{r}},\boldsymbol{{a}}_{\mathrm{0}} \:{et}\:\boldsymbol{\theta} \\ $$ Commented by…

solve-3-sin2x-2cos-2-x-3-1-sin2x-2sin-2-x-28-

Question Number 44920 by peter frank last updated on 06/Oct/18 $$\boldsymbol{\mathrm{solve}}.\mathrm{3}^{\boldsymbol{\mathrm{sin}}\mathrm{2}\boldsymbol{\mathrm{x}}+\mathrm{2}\boldsymbol{\mathrm{cos}}^{\mathrm{2}} \boldsymbol{\mathrm{x}}} +\mathrm{3}^{\mathrm{1}−\boldsymbol{\mathrm{sin}}\mathrm{2}\boldsymbol{\mathrm{x}}+\mathrm{2}\boldsymbol{\mathrm{sin}}^{\mathrm{2}} \boldsymbol{\mathrm{x}}} =\mathrm{28} \\ $$ Answered by ajfour last updated on 06/Oct/18 $$\mathrm{3}^{\mathrm{sin}\:\mathrm{2}{x}+\mathrm{2cos}\:^{\mathrm{2}}…

Given-that-2tan15-0-1-tan-2-15-0-sin30-0-find-tan15-0-leaving-the-answer-in-surd-form-radicals-

Question Number 175961 by pete last updated on 10/Sep/22 $$\mathrm{Given}\:\mathrm{that}\:\frac{\mathrm{2tan15}^{\mathrm{0}} }{\mathrm{1}+\mathrm{tan}^{\mathrm{2}} \mathrm{15}^{\mathrm{0}} }=\mathrm{sin30}^{\mathrm{0}} ,\:\mathrm{find}\:\mathrm{tan15}^{\mathrm{0}} \\ $$$$\mathrm{leaving}\:\mathrm{the}\:\mathrm{answer}\:\mathrm{in}\:\mathrm{surd}\:\mathrm{form}\:\left(\mathrm{radicals}\right) \\ $$ Answered by BaliramKumar last updated on 10/Sep/22…

cos-5x-a-cos-5-x-b-cos-4-x-c-cos-3-x-d-cos-2-x-e-cos-x-f-a-b-c-d-e-f-

Question Number 175650 by mnjuly1970 last updated on 04/Sep/22 $$\: \\ $$$$ \\ $$$${cos}\left(\mathrm{5}{x}\right)=\:{a}.{cos}^{\:\mathrm{5}} \left({x}\right)+{b}.{cos}^{\:\mathrm{4}} \left({x}\right)+{c}.{cos}^{\mathrm{3}} \left({x}\right)+\:{d}.{cos}^{\:\mathrm{2}} \left({x}\right)+{e}.{cos}\left({x}\right)+{f} \\ $$$$\:\:\:\:\:\:{a}\:,\:{b}\:,\:{c}\:,\:{d}\:,\:{e}\:,\:{f}\:=? \\ $$$$ \\ $$$$ \\…