Category: Trigonometry

Question Number 176092 by a.lgnaoui last updated on 12/Sep/22 $$\mathrm{\angle }AOBtriangleequilareraldecote\mathit{a}$$$$(A;\mathrm{B}):\mathrm{c}e\mathrm{ntres}\mathrm{de}\mathrm{cercles}\mathrm{de}\mathrm{rayon}\mathbf{r}$$$$\mathit{\theta }=\measuredangle GOH\mathrm{EF}={\mathit{a}}_0$$$$Determinerlairedelespacedelimitepar$$$$\mathbf{AFOEBHG}commeilestmarquesurlimageci-joint$$$$enfonctionde:\mathit{a},\mathit{r},{\mathit{a}}_{0}et\mathit{\theta }$$ Commented by…

Question Number 175961 by pete last updated on 10/Sep/22 $$\mathrm{Given}\mathrm{that}\frac{{2\tan 15}^0}{1+{\tan }^2{15}^0}={\sin 30}^0,\mathrm{find}{\tan 15}^0$$$$\mathrm{leaving}\mathrm{the}\mathrm{answer}\mathrm{in}\mathrm{surd}\mathrm{form}\left(\mathrm{radicals}\right)$$ Answered by BaliramKumar last updated on 10/Sep/22…

Question Number 175904 by BaliramKumar last updated on 09/Sep/22 $$$$$$\mathrm{If}1+sinx+{sin}^{2}x+{sin}^{3}x+\dots \dots ..\mathrm{\infty }=4+2\sqrt{3},$$$$x=?$$ Commented by infinityaction last updated on 09/Sep/22…

Question Number 175756 by mnjuly1970 last updated on 06/Sep/22 Commented by mr W last updated on 06/Sep/22 $$ithinkforanytypeoftriangle,$$$$\frac{r}{R}ismaximumwhenA=B=C=60°.$$ Answered by mr…

Question Number 175637 by mnjuly1970 last updated on 04/Sep/22 Answered by behi834171 last updated on 04/Sep/22 $$\mathit{I}.$$$${\mathit{r}}_{\mathit{a}}=\mathit{p}.\mathit{t}\mathit{g}\frac{\mathit{A}}{2}=\mathit{p}.\frac{\sqrt{\frac{(\mathit{p}-\mathit{b})(\mathit{p}-\mathit{c})}{\mathit{b}\mathit{c}}}}{\sqrt{\frac{\mathit{p}(\mathit{p}-\mathit{a})}{\mathit{b}\mathit{c}}}}=\sqrt{\frac{\mathit{p}(\mathit{p}-\mathit{b})(\mathit{p}-\mathit{c})}{(\mathit{p}-\mathit{a})}}=$$$$=\frac{\mathit{S}}{\mathit{p}-\mathit{a}}\mathit{a}\mathit{n}\mathit{d}\mathit{s}\mathit{o}\mathit{o}\mathit{n}\dots .$$$$\Rightarrow\Sigma\boldsymbol{{r}}_{\boldsymbol{{a}}} =\boldsymbol{{S}}.\Sigma\left(\frac{\mathrm{1}}{\boldsymbol{{p}}−\boldsymbol{{a}}}\right)=\boldsymbol{{S}}.\frac{\Sigma\left(\boldsymbol{{p}}−\boldsymbol{{b}}\right)\left(\boldsymbol{{p}}−\boldsymbol{{c}}\right)}{\Pi\left(\boldsymbol{{p}}−\boldsymbol{{a}}\right)}=…