Category: Trigonometry

Question Number 209560 by MM42 last updated on 15/Jul/24 $$InthetriangleABC;cos(B-C)=\frac{1}{3}$$$$Showthat:\frac{1-3cos(B+C)}{6sinBcosC}=tanC$$$$$$ Answered by Spillover last updated on 14/Jul/24 $$\:\:\frac{\mathrm{1}−\mathrm{3}×\frac{\mathrm{1}}{\mathrm{3}}}{\mathrm{6}{sinBcosC}}={tanC} \…

Question Number 209458 by SonGoku last updated on 10/Jul/24 Commented by SonGoku last updated on 10/Jul/24 $$\mathrm{l}=?$$$$\mathrm{BC}=\mathrm{l}+200\mathrm{m}$$$$\mathrm{B}\widehat{\mathrm{A}C}=120°$$$$\mathrm{A}\hat {\mathrm{B}C}\:=\:\mathrm{38}°\mathrm{12}'\mathrm{48}''…

Question Number 209211 by SonGoku last updated on 03/Jul/24 Commented by A5T last updated on 03/Jul/24 $$AC=\sqrt{{AB}^2+{BC}^2-2AB\times BCcos123}\approx 74.738$$ Terms of Service Privacy…

Question Number 209115 by alcohol last updated on 02/Jul/24 Terms of Service Privacy Policy Contact: info@tinkutara.com

Question Number 208755 by efronzo1 last updated on 22/Jun/24 Answered by mr W last updated on 22/Jun/24 Commented by mr W last updated on 22/Jun/24…