Question Number 109955 by toa last updated on 26/Aug/20 $$\mathrm{what}\:\mathrm{is}\:\mathrm{the}\:\mathrm{minimal}\:\mathrm{period}\:\mathrm{of}\:\mathrm{cosx}+\mathrm{cos3x} \\ $$ Answered by mathmax by abdo last updated on 26/Aug/20 $$\mathrm{2}\pi \\ $$ Commented…
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Question Number 109910 by bemath last updated on 26/Aug/20 Commented by qwerty111 last updated on 26/Aug/20 Commented by qwerty111 last updated on 26/Aug/20 $$\boldsymbol{{Shuni}}\:\:\boldsymbol{{soddalashtirib}}\:\:\boldsymbol{{qo}}'\boldsymbol{{ying}}\:\:\boldsymbol{{chiqadi}}.\boldsymbol{{Siz}}\:\:\boldsymbol{{o}}'\boldsymbol{{zbekmisiz}}\:? \\…
Question Number 109820 by moses ogwuch last updated on 25/Aug/20 $${tan}^{\mathrm{2}} {x}+{tan}^{\mathrm{2}} \mathrm{2}{x}+{tan}^{\mathrm{2}} \mathrm{4}{x}=\mathrm{33} \\ $$$${find}\:{x}\:\:\:\left({show}\:{full}\:{solution}\:{please}\right) \\ $$ Commented by Sarah85 last updated on 25/Aug/20…
Question Number 109818 by Study last updated on 25/Aug/20 $${tanx}+{tan}\mathrm{2}{x}=\mathrm{1} \\ $$$${find}\:{the}\:{general}\:{solution} \\ $$ Commented by Dwaipayan Shikari last updated on 25/Aug/20 $${x}={k}\pi+\frac{\mathrm{261}}{\mathrm{720}}\pi\:\:\left({approximately}\right)\:\:\left({k}\in\mathbb{Z}\right) \\ $$…
Question Number 109715 by bobhans last updated on 25/Aug/20 $$\begin{cases}{\mathrm{sin}\:\mathrm{2}{x}+\mathrm{sin}\:\mathrm{2}{y}=\frac{\mathrm{5}}{\mathrm{4}}}\\{\mathrm{cos}\:\left({x}−{y}\right)=\mathrm{2sin}\:\left({x}+{y}\right)}\end{cases}{where}\:\mathrm{0}<{x},{y}<\frac{\pi}{\mathrm{2}} \\ $$$$\:\:\:\:\:\mathrm{cos}\:^{\mathrm{2}} \left({x}+{y}\right)\:=\:? \\ $$$$\:\:\:\:\:\:\bigtriangleup\frac{\flat{o}\flat}{{hans}}\bigtriangledown \\ $$ Answered by nimnim last updated on 25/Aug/20 $$\Rightarrow\mathrm{2sin}\left({x}+{y}\right)\mathrm{cos}\left({x}−{y}\right)=\frac{\mathrm{5}}{\mathrm{4}}…
Question Number 44172 by rahul 19 last updated on 22/Sep/18 $${The}\:{number}\:{of}\:{solutions}\:{of}\:{the}\:{equation} \\ $$$$\mathrm{cos}^{−\mathrm{1}} \frac{{x}^{\mathrm{2}} −\mathrm{1}}{{x}^{\mathrm{2}} +\mathrm{1}}\:+\:\mathrm{sin}^{−\mathrm{1}} \frac{\mathrm{2}{x}}{{x}^{\mathrm{2}} +\mathrm{1}}\:+\mathrm{tan}^{−\mathrm{1}} \frac{\mathrm{2}{x}}{{x}^{\mathrm{2}} −\mathrm{1}}=\frac{\mathrm{2}\pi}{\mathrm{3}}. \\ $$ Commented by tanmay.chaudhury50@gmail.com…
Question Number 44159 by rahul 19 last updated on 22/Sep/18 $${If}\:\mathrm{sin}^{−\mathrm{1}} {x}\:+\:\mathrm{sin}^{−\mathrm{1}} {y}\:+\:\mathrm{sin}^{−\mathrm{1}} \boldsymbol{{z}}\:=\pi\: \\ $$$${prove}\:{that}\:: \\ $$$$\left.{a}\right)\:{x}\sqrt{\mathrm{1}−{x}^{\mathrm{2}} }\:+\:{y}\sqrt{\mathrm{1}−{y}^{\mathrm{2}} }\:+\boldsymbol{{z}}\sqrt{\mathrm{1}−\boldsymbol{{z}}^{\mathrm{2}} }=\:\mathrm{2}{xy}\boldsymbol{{z}} \\ $$$$\left.{b}\right)\:{x}^{\mathrm{4}} +{y}^{\mathrm{4}} +\boldsymbol{{z}}^{\mathrm{4}}…
Question Number 44097 by peter frank last updated on 21/Sep/18 Answered by tanmay.chaudhury50@gmail.com last updated on 22/Sep/18 $${y}=\frac{\mathrm{2}\theta}{\mathrm{1}+\theta^{\mathrm{2}} } \\ $$$${let} \\ $$$${tanh}^{−\mathrm{1}} {y}={p} \\…