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Category: Trigonometry

Question-40231

Question Number 40231 by Raj Singh last updated on 17/Jul/18 Answered by tanmay.chaudhury50@gmail.com last updated on 17/Jul/18 cosAsinA+1cosA+sinA1a=sinAb=cosAa2+b2=1$$\frac{\left({b}−{a}+\mathrm{1}\right)\left({b}+{a}+\mathrm{1}\right)}{\left({b}+{a}−\mathrm{1}\right)\left({b}+{a}+\mathrm{1}\right)} \

find-General-solution-cot-x-cot-2x-cot3x-0-

Question Number 105619 by bobhans last updated on 30/Jul/20 findGeneralsolutioncotx+cot2x+cot3x=0 Answered by bemath last updated on 30/Jul/20 $$\Leftrightarrow\mathrm{cot}\:\left({x}\right)+\frac{\mathrm{cot}\:^{\mathrm{2}} \left({x}\right)−\mathrm{1}}{\mathrm{2cot}\:\left({x}\right)}+\frac{\mathrm{3cot}\:\left({x}\right)−\mathrm{cot}\:^{\mathrm{3}} \left({x}\right)}{\mathrm{1}−\mathrm{3cot}\:^{\mathrm{2}} \left({x}\right)}=\:\mathrm{0}…