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Question Number 102587 by 1549442205 last updated on 10/Jul/20 $$\mathrm{Prove}\:\mathrm{that} \\ $$$$\mathrm{cot7}.\mathrm{5}°=\sqrt{\mathrm{2}}+\sqrt{\mathrm{3}}+\sqrt{\mathrm{4}}+\sqrt{\mathrm{6}} \\ $$ Commented by PRITHWISH SEN 2 last updated on 10/Jul/20 $$\mathrm{a}\:\mathrm{different}\:\mathrm{approach} \\…
Question Number 102390 by Dwaipayan Shikari last updated on 08/Jul/20 $${asin}\theta+{bcos}\theta={c} \\ $$$${acosec}\theta+{bsec}\theta={c} \\ $$$$ \\ $$$${prove}\:{that}\:\:\:\:{sin}\mathrm{2}\theta=\frac{\mathrm{2}{ab}}{{c}^{\mathrm{2}} −{a}^{\mathrm{2}} −{b}^{\mathrm{2}} } \\ $$ Commented by PRITHWISH…
Question Number 102190 by dw last updated on 07/Jul/20 $${Find}\:{the}\:{value}\:{of}\:\:{x}\:\centerdot\centerdot\left[{Trigonometric}\:{Subs}.\right] \\ $$$${x}−\frac{{x}}{\:\sqrt{\mathrm{1}−{x}^{\mathrm{2}} }}=\frac{\mathrm{91}}{\mathrm{60}} \\ $$ Answered by bemath last updated on 07/Jul/20 $$\frac{{x}\left(\sqrt{\mathrm{1}−{x}^{\mathrm{2}} }−\mathrm{1}\right)}{\:\sqrt{\mathrm{1}−{x}^{\mathrm{2}} }}\:=\:\frac{\mathrm{91}}{\mathrm{60}}…
Question Number 102177 by dw last updated on 07/Jul/20 Commented by Rasheed.Sindhi last updated on 07/Jul/20 $${ac}+{bd}=\mathrm{0}\Rightarrow{d}=−\frac{{ac}}{{b}} \\ $$$${c}^{\mathrm{2}} +{d}^{\mathrm{2}} ={c}^{\mathrm{2}} +\left(−\frac{{ac}}{{b}}\right)^{\mathrm{2}} =\mathrm{1} \\ $$$$\:\:\:\:\:\:\:\:\:\:\Rightarrow{b}^{\mathrm{2}}…
Question Number 167594 by infinityaction last updated on 20/Mar/22 Answered by som(math1967) last updated on 20/Mar/22 $${cosx}+{cosy}+{cosz}={pcos}\left({x}+{y}+{z}\right) \\ $$$${cosxcos}\left({x}+{y}+{z}\right)+{cosycos}\left({x}+{y}+{z}\right) \\ $$$$+{coszcos}\left({x}+{y}+{z}\right)={pcos}^{\mathrm{2}} \left({x}+{y}+{z}\right) \\ $$$$\left………{case}\:\:{i}\right) \\…
Question Number 102015 by bemath last updated on 06/Jul/20 $${how}\:{many}\:{rotational}\:{symetry}\:\:{triangle} \\ $$$${isosceles}\:? \\ $$$$\mathrm{1}\:{or}\:\mathrm{0}?? \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 101994 by bemath last updated on 06/Jul/20 Commented by Rasheed.Sindhi last updated on 06/Jul/20 $$\mathrm{5}×\mathrm{4}^{\mathrm{2}} ×\mathrm{6}^{\mathrm{3}} ×\mathrm{6}^{\mathrm{4}} =\mathrm{22394880} \\ $$ Answered by john…
Question Number 167512 by MikeH last updated on 18/Mar/22 $$\int_{\mathrm{0}} ^{{r}} \sqrt{{r}^{\mathrm{2}} −{x}^{\mathrm{2}} }\:{dx} \\ $$ Commented by mr W last updated on 18/Mar/22 $$={area}\:{of}\:{a}\:{quater}\:{circle}=\frac{\pi{r}^{\mathrm{2}}…
Question Number 167501 by cortano1 last updated on 18/Mar/22 $$\:\:\:\:\:\:\frac{\mathrm{tan}\:^{\mathrm{2}} \frac{\pi}{\mathrm{7}}+\mathrm{tan}\:^{\mathrm{2}} \frac{\mathrm{2}\pi}{\mathrm{7}}+\mathrm{tan}\:^{\mathrm{2}} \frac{\mathrm{3}\pi}{\mathrm{7}}}{\mathrm{cot}\:^{\mathrm{2}} \frac{\pi}{\mathrm{7}}+\mathrm{cot}\:^{\mathrm{2}} \frac{\mathrm{2}\pi}{\mathrm{7}}+\mathrm{cot}\:^{\mathrm{2}} \frac{\mathrm{3}\pi}{\mathrm{7}}}\:=? \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com