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Category: Trigonometry

tan193-k-cos167-

Question Number 164760 by mathlove last updated on 21/Jan/22 $${tan}\mathrm{193}={k} \\ $$$${cos}\mathrm{167}=? \\ $$ Answered by blackmamba last updated on 21/Jan/22 $$\:\mathrm{tan}\:\left(\mathrm{193}°\right)=\mathrm{tan}\:\left(\mathrm{180}°+\mathrm{13}°\right)=\:{k}\: \\ $$$$\:\Rightarrow\mathrm{tan}\:\mathrm{13}°\:={k} \\…

cos-2-3-sin-pi-2-3sin-2-7pi-2-2cos-5pi-

Question Number 164757 by mathlove last updated on 21/Jan/22 $$\mathrm{cos}\:\alpha=\frac{\mathrm{2}}{\mathrm{3}} \\ $$$${sin}\left(\frac{\pi}{\mathrm{2}}+\alpha\right)−\mathrm{3}{sin}^{\mathrm{2}} \left(\frac{\mathrm{7}\pi}{\mathrm{2}}+\alpha\right)−\mathrm{2}{cos}\left(\mathrm{5}\pi+\alpha\right)=? \\ $$ Commented by blackmamba last updated on 21/Jan/22 $$\Rightarrow=\mathrm{cos}\:\alpha−\mathrm{3cos}\:^{\mathrm{2}} \alpha+\mathrm{2cos}\:\alpha \\…

tan22-2-5-sin112-sin202-cos-68-

Question Number 164758 by mathlove last updated on 21/Jan/22 $${tan}\mathrm{22}=\frac{\mathrm{2}}{\mathrm{5}} \\ $$$$\frac{{sin}\mathrm{112}+{sin}\mathrm{202}}{{cos}\left(−\mathrm{68}\right)}=? \\ $$ Answered by Rasheed.Sindhi last updated on 21/Jan/22 $$\frac{\mathrm{sin}\:\mathrm{112}+\mathrm{sin}\:\mathrm{202}}{\mathrm{cos}\:\left(−\mathrm{68}\right)} \\ $$$$=\frac{\mathrm{sin}\left(\mathrm{90}+\mathrm{22}\right)+\mathrm{sin}\left(\mathrm{180}+\mathrm{22}\right)}{\:\mathrm{cos}\left(\mathrm{22}−\mathrm{90}\right)} \\…

tan3x-5tanx-x-

Question Number 164720 by mathlove last updated on 21/Jan/22 $${tan}\mathrm{3}{x}=\mathrm{5}{tanx} \\ $$$${x}=? \\ $$ Answered by leonhard77 last updated on 21/Jan/22 $$\:\mathrm{tan}\:\mathrm{3}{x}=\frac{\mathrm{3tan}\:{x}−\mathrm{tan}\:^{\mathrm{3}} {x}}{\mathrm{1}−\mathrm{3tan}\:^{\mathrm{2}} {x}}\:=\:\mathrm{5tan}\:{x} \\…

Min-f-x-cos-2x-3-sin-2x-2-3-cos-x-2sin-x-is-

Question Number 164606 by cortano1 last updated on 19/Jan/22 $$\:{Min}\:{f}\left({x}\right)=\:\mathrm{cos}\:\mathrm{2}{x}\:+\sqrt{\mathrm{3}}\:\mathrm{sin}\:\mathrm{2}{x}\:−\mathrm{2}\sqrt{\mathrm{3}}\:\mathrm{cos}\:{x}−\mathrm{2sin}\:{x} \\ $$$$\:{is}\:… \\ $$ Answered by bobhans last updated on 19/Jan/22 $$\:\mathrm{f}\left(\mathrm{x}\right)=\:\mathrm{cos}\:\mathrm{2x}\:+\:\sqrt{\mathrm{3}}\:\mathrm{sin}\:\mathrm{2x}\:−\mathrm{2}\sqrt{\mathrm{3}}\:\mathrm{cos}\:\mathrm{x}−\mathrm{2sin}\:\mathrm{x}\: \\ $$$$\:\mathrm{set}\:\vartheta\:=\mathrm{sin}\:\mathrm{x}+\sqrt{\mathrm{3}}\:\mathrm{cos}\:\mathrm{x}\Rightarrow\vartheta^{\mathrm{2}} \:=\mathrm{sin}\:^{\mathrm{2}}…

Find-the-tangent-at-the-poles-for-the-polar-equation-r-a-sin-2-

Question Number 98988 by Rio Michael last updated on 17/Jun/20 $$\mathrm{Find}\:\mathrm{the}\:\mathrm{tangent}\:\mathrm{at}\:\mathrm{the}\:\mathrm{poles}\:\mathrm{for}\:\mathrm{the}\:\mathrm{polar} \\ $$$$\mathrm{equation}\:{r}\:=\:{a}\:\mathrm{sin}\:\mathrm{2}\theta. \\ $$ Answered by mr W last updated on 17/Jun/20 $${x}={r}\:\mathrm{cos}\:\theta={a}\:\mathrm{sin}\:\mathrm{2}\theta\:\mathrm{cos}\:\theta \\…