Question Number 52470 by ajfour last updated on 08/Jan/19 Commented by ajfour last updated on 08/Jan/19 $${Find}\:{r}\:{in}\:{terms}\:{of}\:{a},{b},{c}. \\ $$$$\left({OD}\:{is}\:{vertical}\right). \\ $$ Answered by mr W…
Question Number 183293 by neinhaltsieger369 last updated on 24/Dec/22 $$\: \\ $$$$\:\mathrm{Help}! \\ $$$$\: \\ $$$$\:\mathrm{A}\:\mathrm{beam}\:\mathrm{being}\:\mathrm{lifted}\:\mathrm{by}\:\mathrm{two}\:\mathrm{forces}\:\mathrm{where}\: \\ $$$$\:\mathrm{F1makes}\:\mathrm{an}\:\mathrm{angle}\:\mathrm{of}\:\mathrm{23}°\:\mathrm{degrees}\:\mathrm{with}\:\mathrm{the}\:\mathrm{y} \\ $$$$\:\mathrm{axis}\:\mathrm{acts}\:\mathrm{in}\:\mathrm{the}\:\mathrm{second}\:\mathrm{quadrant}\:\mathrm{F2}\:\mathrm{acts}\:\mathrm{in} \\ $$$$\:\mathrm{the}\:\mathrm{first}\:\mathrm{quadrant}\:\mathrm{making}\:\mathrm{an}\:\mathrm{angle}\:\mathrm{of}\:\mathrm{32}° \\ $$$$\:\mathrm{degrees}\:\mathrm{with}\:\mathrm{the}\:\mathrm{y}\:\mathrm{axis}\:\mathrm{and}\:\mathrm{the}\:\mathrm{resultant} \\…
Question Number 183165 by universe last updated on 21/Dec/22 Answered by mr W last updated on 22/Dec/22 Commented by mr W last updated on 21/Dec/22…
Question Number 117543 by bemath last updated on 12/Oct/20 $$\mathrm{If}\:\mathrm{vector}\:\overset{\rightarrow} {\mathrm{a}}+\overset{\rightarrow} {\mathrm{b}}+\overset{\rightarrow} {\mathrm{c}}=\mathrm{0} \\ $$$$\mid\overset{\rightarrow} {\mathrm{a}}\mid=\mathrm{7},\:\mid\overset{\rightarrow} {\mathrm{b}}\mid=\mathrm{3}\:\mathrm{and}\:\mid\overset{\rightarrow} {\mathrm{c}}\mid=\mathrm{5} \\ $$$$\mathrm{find}\:\mathrm{the}\:\mathrm{angle}\:\mathrm{vector}\:\overset{\rightarrow} {\mathrm{a}}\:\mathrm{and}\:\overset{\rightarrow} {\mathrm{c}}\:? \\ $$ Answered…
Question Number 117191 by Lordose last updated on 10/Oct/20 $$\int\mathrm{sin}^{\frac{\mathrm{3}}{\mathrm{2}}} \left(\mathrm{x}\right)\mathrm{dx} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 51535 by ajfour last updated on 28/Dec/18 Commented by ajfour last updated on 28/Dec/18 $${If}\:{BC}\:{be}\:{parallel}\:{to}\:{x}-{axis},\:{find} \\ $$$${coordinates}\:{of}\:{A}. \\ $$ Answered by mr W…
Question Number 51520 by Tawa1 last updated on 27/Dec/18 Commented by Tawa1 last updated on 27/Dec/18 $$\mathrm{Thanks}\:\mathrm{but}\:\mathrm{no}\:\mathrm{idea} \\ $$ Answered by tanmay.chaudhury50@gmail.com last updated on…
Question Number 182438 by neinhaltsieger369 last updated on 09/Dec/22 $$\: \\ $$$$\:\left[\boldsymbol{\mathrm{Help}}\:\:\boldsymbol{\mathrm{me}}!\right] \\ $$$$\: \\ $$$$\:\boldsymbol{\mathrm{The}}\:\:\boldsymbol{\mathrm{rate}}\:\:\boldsymbol{\mathrm{of}}\:\:\boldsymbol{\mathrm{change}}\:\:\boldsymbol{\mathrm{of}}\:\:\boldsymbol{\mathrm{w}}\:\:=\:\:\boldsymbol{\mathrm{x}}^{\mathrm{3}} \boldsymbol{\mathrm{y}}^{\mathrm{2}} \boldsymbol{\mathrm{z}}\:\:+\:\boldsymbol{\mathrm{y}}^{\mathrm{3}} \boldsymbol{\mathrm{z}}^{\mathrm{2}} \:−\:\boldsymbol{\mathrm{xz}}^{\mathrm{4}} \:\:\boldsymbol{\mathrm{at}}\:\:\boldsymbol{\mathrm{the}}\:\:\boldsymbol{\mathrm{point}}\:\:\boldsymbol{\mathrm{Q}}\left(\mathrm{0},\:\mathrm{1},\:\mathrm{2}\right) \\ $$$$\:\boldsymbol{\mathrm{in}}\:\:\boldsymbol{\mathrm{the}}\:\:\boldsymbol{\mathrm{direction}}\:\:\overset{\rightarrow} {\boldsymbol{\mathrm{V}}}\:\:=\:\:\mathrm{2}\boldsymbol{\mathrm{i}}\:\:+\:\:\boldsymbol{\mathrm{j}}\:\:+\:\:\mathrm{2}\boldsymbol{\mathrm{k}}\:\:\boldsymbol{\mathrm{is}}: \\…
Question Number 182348 by mathlove last updated on 08/Dec/22 $$\int_{\mathrm{0}} ^{\mathrm{2}} \int_{\mathrm{0}} ^{\mathrm{3}} \int_{\mathrm{0}} ^{\mathrm{4}} {e}^{{x}+{y}+{z}} {dx}\:{dy}\:{dz}=? \\ $$ Answered by CrispyXYZ last updated on…
Question Number 51263 by Tawa1 last updated on 25/Dec/18 $$\mathrm{If}\:\:\mathrm{P}\:=\:\mathrm{2}\:+\:\mathrm{j3}\:\mathrm{and}\:\mathrm{Q}\:=\:\mathrm{2}\:−\:\mathrm{j3}\:\mathrm{and}\:\mathrm{R}\:=\:\mathrm{j1} \\ $$$$\mathrm{Show}\:\mathrm{that}\:\:\mathrm{angle}\:\:\mathrm{PRQ}\:\mathrm{is}\:\mathrm{right}\:\mathrm{angle} \\ $$ Answered by tanmay.chaudhury50@gmail.com last updated on 25/Dec/18 $${P}\left(\mathrm{2},\mathrm{3}\right)\:\:\:{Q}\left(\mathrm{2},−\mathrm{3}\right)\:\:\:{R}\left(\mathrm{0},\mathrm{1}\right) \\ $$$${PQ}=\mathrm{6}\:\:\:\:{QR}=\sqrt{\mathrm{2}^{\mathrm{2}} +\left(−\mathrm{4}\right)^{\mathrm{2}}…