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Question Number 51535 by ajfour last updated on 28/Dec/18 Commented by ajfour last updated on 28/Dec/18 $${If}\:{BC}\:{be}\:{parallel}\:{to}\:{x}-{axis},\:{find} \\ $$$${coordinates}\:{of}\:{A}. \\ $$ Answered by mr W…
Question Number 51520 by Tawa1 last updated on 27/Dec/18 Commented by Tawa1 last updated on 27/Dec/18 $$\mathrm{Thanks}\:\mathrm{but}\:\mathrm{no}\:\mathrm{idea} \\ $$ Answered by tanmay.chaudhury50@gmail.com last updated on…
Question Number 182438 by neinhaltsieger369 last updated on 09/Dec/22 $$\: \\ $$$$\:\left[\boldsymbol{\mathrm{Help}}\:\:\boldsymbol{\mathrm{me}}!\right] \\ $$$$\: \\ $$$$\:\boldsymbol{\mathrm{The}}\:\:\boldsymbol{\mathrm{rate}}\:\:\boldsymbol{\mathrm{of}}\:\:\boldsymbol{\mathrm{change}}\:\:\boldsymbol{\mathrm{of}}\:\:\boldsymbol{\mathrm{w}}\:\:=\:\:\boldsymbol{\mathrm{x}}^{\mathrm{3}} \boldsymbol{\mathrm{y}}^{\mathrm{2}} \boldsymbol{\mathrm{z}}\:\:+\:\boldsymbol{\mathrm{y}}^{\mathrm{3}} \boldsymbol{\mathrm{z}}^{\mathrm{2}} \:−\:\boldsymbol{\mathrm{xz}}^{\mathrm{4}} \:\:\boldsymbol{\mathrm{at}}\:\:\boldsymbol{\mathrm{the}}\:\:\boldsymbol{\mathrm{point}}\:\:\boldsymbol{\mathrm{Q}}\left(\mathrm{0},\:\mathrm{1},\:\mathrm{2}\right) \\ $$$$\:\boldsymbol{\mathrm{in}}\:\:\boldsymbol{\mathrm{the}}\:\:\boldsymbol{\mathrm{direction}}\:\:\overset{\rightarrow} {\boldsymbol{\mathrm{V}}}\:\:=\:\:\mathrm{2}\boldsymbol{\mathrm{i}}\:\:+\:\:\boldsymbol{\mathrm{j}}\:\:+\:\:\mathrm{2}\boldsymbol{\mathrm{k}}\:\:\boldsymbol{\mathrm{is}}: \\…
Question Number 182348 by mathlove last updated on 08/Dec/22 $$\int_{\mathrm{0}} ^{\mathrm{2}} \int_{\mathrm{0}} ^{\mathrm{3}} \int_{\mathrm{0}} ^{\mathrm{4}} {e}^{{x}+{y}+{z}} {dx}\:{dy}\:{dz}=? \\ $$ Answered by CrispyXYZ last updated on…
Question Number 51263 by Tawa1 last updated on 25/Dec/18 $$\mathrm{If}\:\:\mathrm{P}\:=\:\mathrm{2}\:+\:\mathrm{j3}\:\mathrm{and}\:\mathrm{Q}\:=\:\mathrm{2}\:−\:\mathrm{j3}\:\mathrm{and}\:\mathrm{R}\:=\:\mathrm{j1} \\ $$$$\mathrm{Show}\:\mathrm{that}\:\:\mathrm{angle}\:\:\mathrm{PRQ}\:\mathrm{is}\:\mathrm{right}\:\mathrm{angle} \\ $$ Answered by tanmay.chaudhury50@gmail.com last updated on 25/Dec/18 $${P}\left(\mathrm{2},\mathrm{3}\right)\:\:\:{Q}\left(\mathrm{2},−\mathrm{3}\right)\:\:\:{R}\left(\mathrm{0},\mathrm{1}\right) \\ $$$${PQ}=\mathrm{6}\:\:\:\:{QR}=\sqrt{\mathrm{2}^{\mathrm{2}} +\left(−\mathrm{4}\right)^{\mathrm{2}}…
Question Number 50755 by ajfour last updated on 19/Dec/18 Commented by ajfour last updated on 19/Dec/18 $${Find}\:{the}\:{angle}\:{between}\:{the}\:{two} \\ $$$${triangular}\:\left({coloured}\right)\:{planes}. \\ $$ Answered by mr W…
Question Number 181730 by neinhaltsieger369 last updated on 29/Nov/22 Commented by neinhaltsieger369 last updated on 29/Nov/22 $$\:\boldsymbol{\mathrm{Help}}\:-\:\boldsymbol{\mathrm{me}}! \\ $$ Commented by mr W last updated…
Question Number 181707 by amin96 last updated on 28/Nov/22 $$\boldsymbol{{if}}\:\:\:\:\:\mathrm{2}\boldsymbol{{x}}+\frac{\mathrm{1}}{\:\sqrt{\boldsymbol{{x}}}}=\frac{\mathrm{1}}{\mathrm{2}} \\ $$$$\boldsymbol{{find}}\:\boldsymbol{{the}}\:\boldsymbol{{value}}\:\:\:\mathrm{8}\boldsymbol{{x}}+\frac{\mathrm{1}}{\:\sqrt{\boldsymbol{{x}}}}=? \\ $$ Answered by mr W last updated on 29/Nov/22 $${t}=\sqrt{{x}}>\mathrm{0} \\ $$$${f}\left({t}\right)=\mathrm{2}{t}^{\mathrm{2}}…
Question Number 50576 by Tinkutara last updated on 17/Dec/18 Commented by Tinkutara last updated on 19/Dec/18 please help Terms of Service Privacy Policy Contact: info@tinkutara.com