Question Number 41606 by psyche-ace last updated on 10/Aug/18 $$\mathrm{4}\boldsymbol{\mathrm{x}}^{\mathrm{4}} +\mathrm{16}\boldsymbol{\mathrm{x}}^{\mathrm{3}} +\mathrm{24}\boldsymbol{\mathrm{x}}^{\mathrm{2}} −\mathrm{9}\boldsymbol{\mathrm{x}}−\mathrm{1}=\mathrm{0} \\ $$$$\boldsymbol{\mathrm{using}}\:\boldsymbol{\mathrm{any}}\:\boldsymbol{\mathrm{method}}.\:\boldsymbol{\mathrm{find}}\:\:\boldsymbol{\mathrm{real}}\:\boldsymbol{\mathrm{value}}\:\boldsymbol{\mathrm{of}}\:\:\boldsymbol{\mathrm{x}}\:\:\boldsymbol{\mathrm{that}}\:\boldsymbol{\mathrm{satisfy}}\:\boldsymbol{\mathrm{the}}\:\boldsymbol{\mathrm{polynomial}} \\ $$ Answered by MJS last updated on 10/Aug/18 $${f}\left({x}\right)={x}^{\mathrm{4}}…
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Question Number 105904 by bemath last updated on 01/Aug/20 $$\int\:\frac{\mathrm{sin}\:{x}}{\mathrm{5}−\mathrm{sin}\:\mathrm{2}{x}}\:{dx}\:? \\ $$ Answered by bemath last updated on 01/Aug/20 Commented by Her_Majesty last updated on…
Question Number 171033 by cortano1 last updated on 06/Jun/22 $$\:\:\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\:\frac{\mathrm{1}}{{x}}\:\left[\:\sqrt[{\mathrm{3}}]{\frac{\mathrm{1}−\sqrt{\mathrm{1}−{x}}}{\:\sqrt{\mathrm{1}+{x}}−\mathrm{1}}\:}−\mathrm{1}\:\right]=? \\ $$ Commented by greougoury555 last updated on 07/Jun/22 $$\:\sqrt[{\mathrm{3}}]{\frac{\left(\mathrm{1}−\sqrt{\mathrm{1}−{x}}\right)\left(\mathrm{1}+\sqrt{\mathrm{1}−{x}}\right)}{\mathrm{1}+\sqrt{\mathrm{1}−{x}}}.\frac{\sqrt{\mathrm{1}+{x}}+\mathrm{1}}{\left(\sqrt{\mathrm{1}+{x}}−\mathrm{1}\right)\left(\sqrt{\mathrm{1}+{x}}+\mathrm{1}\right)}} \\ $$$$=\:\sqrt[{\mathrm{3}}]{\frac{{x}\left(\sqrt{\mathrm{1}+{x}}+\mathrm{1}\right)}{{x}\left(\mathrm{1}+\sqrt{\mathrm{1}−{x}}\right)}}\:=\:\sqrt[{\mathrm{3}}]{\frac{\sqrt{\mathrm{1}+{x}}+\mathrm{1}}{\mathrm{1}+\sqrt{\mathrm{1}−{x}}}\:} \\ $$$${L}=\underset{{x}\rightarrow\mathrm{0}}…
Question Number 170079 by depressiveshrek last updated on 16/May/22 $$\mid\overset{\rightarrow} {{a}}\mid=\mathrm{1} \\ $$$$\mid\overset{\rightarrow} {{b}}\mid=\mathrm{2} \\ $$$$\sphericalangle\left(\overset{\rightarrow} {{a}},\:\overset{\rightarrow} {{b}}\right)=\frac{\pi}{\mathrm{3}} \\ $$$$\mid\overset{\rightarrow} {{a}}+\overset{\rightarrow} {{b}}\mid=? \\ $$ Answered…
Question Number 169885 by depressiveshrek last updated on 11/May/22 $$\mid\overset{\rightarrow} {{a}}\mid=\mathrm{13} \\ $$$$\mid\overset{\rightarrow} {{b}}\mid=\mathrm{19} \\ $$$$\mid\overset{\rightarrow} {{a}}+\overset{\rightarrow} {{b}}\mid=\mathrm{24} \\ $$$$\mid\overset{\rightarrow} {{a}}−\overset{\rightarrow} {{b}}\mid=? \\ $$ Answered…
Question Number 169640 by MikeH last updated on 05/May/22 $$\int\mathrm{cos}\left({x}^{\mathrm{7}} \right){dx}\:= \\ $$ Commented by mkam last updated on 05/May/22 $$ \\ $$$$=\:\int\:\Sigma\:\left(−\mathrm{1}\right)^{{n}} \:×\:\frac{{x}^{\mathrm{14}{n}} }{\left(\mathrm{2}{n}\right)!}\:{dx}\:=\:\Sigma\:\frac{\left(−\mathrm{1}\right)^{{n}}…
Question Number 104035 by ajfour last updated on 19/Jul/20 $${Find}\:{the}\:{image}\:{of}\:{point}\:\overset{\rightarrow} {{OP}}\:=\:\bar {{p}}\:\:{in} \\ $$$${the}\:{line}\:\:\bar {{r}}=\bar {{a}}+\lambda\bar {{b}}\:. \\ $$ Answered by mr W last updated…
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Question Number 168977 by MikeH last updated on 23/Apr/22 $$\mathrm{check}\:\mathrm{that}\:\mathrm{the}\:\mathrm{function} \\ $$$${u}\left({x},{t}\right)\:=\:\mathrm{exp}\left\{−\frac{{n}^{\mathrm{2}} \alpha^{\mathrm{2}} \pi^{\mathrm{2}} }{{L}^{\mathrm{2}} }{t}\right\}\:\mathrm{sin}\frac{{n}\pi{x}}{{L}} \\ $$$${n}\:=\:\mathrm{1},\mathrm{2},…\:\mathrm{satisfy}\:\mathrm{the}\:\mathrm{heat}\:\mathrm{equation} \\ $$$$\boldsymbol{\mathrm{heat}}\:\boldsymbol{\mathrm{equation}} \\ $$$$\alpha^{\mathrm{2}} \frac{\partial^{\mathrm{2}} {u}}{\partial{x}^{\mathrm{2}} }\:=\:\frac{\partial{u}}{\partial{t}},\:\mathrm{0}\:<\:{x}\:<\:{L}…