Question Number 93299 by Rio Michael last updated on 12/May/20 $$\mathrm{find}\:\mathrm{a}\:\mathrm{reduction}\:\mathrm{formulae}\:\mathrm{for}\:{I}_{{n}} \:=\:\int_{−\mathrm{1}} ^{\mathrm{0}} {x}^{{n}} \left(\mathrm{1}\:+\:{x}\right)^{\mathrm{2}} \:{dx} \\ $$ Commented by mathmax by abdo last updated…
Question Number 93249 by 1549442205 last updated on 12/May/20 $${calculate}\int_{\mathrm{0}} ^{\frac{\Pi}{\mathrm{2}}\:} \frac{{dx}}{\mathrm{2}+{cos}\mathrm{2}{x}} \\ $$ Commented by 1549442205 last updated on 12/May/20 $${Calculate}\:{its}\:{value}? \\ $$ Commented…
Question Number 27673 by ajfour last updated on 12/Jan/18 Commented by ajfour last updated on 12/Jan/18 $${Find}\:{vector}\:{eq}.\:{of}\:{blue}\:{line}\:{in} \\ $$$${given}\:{plane}\:{that}\:{makes}\:\:{a}\:{minimum} \\ $$$${angle}\:{with}\:{the}\:{given}\:{red}\:{line}. \\ $$ Terms of…
Question Number 27651 by Joel578 last updated on 12/Jan/18 $$\mathrm{A}\:\mathrm{positive}\:\mathrm{number}\:\mathrm{has}\:\mathrm{8}\:\mathrm{distinct}\:\mathrm{divisors} \\ $$$$\mathrm{Lets}\:\mathrm{say}\:{a},\:{b},\:{c},\:{d},\:{e},\:{f},\:{g}\:\mathrm{and}\:{h} \\ $$$$\mathrm{Given}\:\:{a}\:.\:{b}\:.\:{c}\:.\:{d}\:.\:{e}\:.\:{f}\:.\:{g}\:.\:{h}\:=\:\mathrm{3111696} \\ $$$$\mathrm{Find}\:\mathrm{that}\:\mathrm{number} \\ $$ Commented by Joel578 last updated on 12/Jan/18…
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Question Number 158081 by Eric002 last updated on 30/Oct/21 $${determine}\:{the}\:{angle}\:{between}\:{two}\:{vectors} \\ $$$${A}=\mathrm{4}{ax}+{ay}−\mathrm{3}{az}\:\:{and}\:\:{B}=\mathrm{2}{ax}+\mathrm{4}{ay}−\mathrm{3}{az} \\ $$ Answered by ajfour last updated on 30/Oct/21 $$\mathrm{cos}\:\theta=\frac{\mathrm{4}\left(\mathrm{2}\right)+\mathrm{1}\left(\mathrm{4}\right)−\mathrm{3}\left(−\mathrm{3}\right)}{\:\sqrt{\mathrm{4}^{\mathrm{2}} +\mathrm{1}^{\mathrm{2}} +\left(−\mathrm{3}\right)^{\mathrm{2}} }\sqrt{\mathrm{2}^{\mathrm{2}}…
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Question Number 92521 by hovero clinton last updated on 07/May/20 Commented by hovero clinton last updated on 07/May/20 $${my}\:{post}\:{here}\:{never}\: \\ $$$${get}\:{answers}\:{y}?? \\ $$ Commented by…
Question Number 92235 by ~blr237~ last updated on 05/May/20 $${let}\:\:\mathrm{0}<{p}<\mathrm{1}\:\:{and}\:\:{x}>\mathrm{0} \\ $$$${prove}\:{that}\:\:\:\:{x}^{\mathrm{2}} \leqslant\:\left(\mathrm{1}−{p}\right)\left(\:\:\:^{\left(\mathrm{1}−{p}\right)} \sqrt{{x}}\:\right)\:+{p}\:\left(\:^{{p}} \sqrt{{x}}\right) \\ $$$$ \\ $$$$ \\ $$ Terms of Service Privacy…