Category: Vector

Question Number 26374 by tawa tawa last updated on 24/Dec/17 $$\mathrm{show}\mathrm{that}\mathrm{if}\arg \left(\frac{{\mathrm{z}}_1+{\mathrm{z}}_2}{{\mathrm{z}}_1-{\mathrm{z}}_2}\right)=\frac{\pi }{2}\mathrm{then}\mid {\mathrm{z}}_1\mid =\mid {\mathrm{z}}_2\mid$$ Answered by Rasheed.Sindhi last updated on…

Question Number 25245 by adityapratap2585@gmail.com last updated on 06/Dec/17 $$\mathrm{yadi}\mathrm{kisi}\mathrm{equilatter}\mathrm{triangle}\mathrm{ke}$$$$\mathrm{parivrit}\mathrm{aur}\mathrm{antahvrit}\mathrm{ke}\mathrm{areas}\mathrm{ka}$$$$\mathrm{difference}{44\mathrm{cm}}^2\mathrm{hai}\mathrm{to}\mathrm{triangle}\mathrm{ka}$$$$\mathrm{area}\mathrm{kya}\mathrm{hoga}?$$ Answered by $@ty@m last updated on…

Question Number 90468 by ar247 last updated on 23/Apr/20 Commented by ar247 last updated on 23/Apr/20 $$helpmeplease.stapbystap$$ Terms of Service Privacy Policy Contact:…

Question Number 24569 by ajfour last updated on 21/Nov/17 Commented by ajfour last updated on 21/Nov/17 $$Inagravityfreecubicalbox,a$$$$ballbounceselastically.Ifitbe$$$$projectedfromoriginOtowards$$$$A(4,13,16),apointontheroof$$$${plane}\:{then}\:{find}\:{the}\:{second}\:{and}…

Question Number 89033 by M±th+et£s last updated on 14/Apr/20 Answered by ajfour last updated on 15/Apr/20 $$letcenterofsquarebeorigin.$$$$eq.ofleftcircle:$$$${(x+\frac{r}{2})}^2+y^2=r^2$$$${let}\:{side}\:{of}\:{square}=\mathrm{2}{s}…