Question Number 24569 by ajfour last updated on 21/Nov/17 Commented by ajfour last updated on 21/Nov/17 $${In}\:{a}\:{gravity}\:{free}\:{cubical}\:{box},\:{a} \\ $$$${ball}\:{bounces}\:{elastically}.\:{If}\:{it}\:{be} \\ $$$${projected}\:{from}\:{origin}\:{O}\:{towards} \\ $$$${A}\left(\mathrm{4},\:\mathrm{13},\:\mathrm{16}\right),\:{a}\:{point}\:{on}\:{the}\:{roof} \\ $$$${plane}\:{then}\:{find}\:{the}\:{second}\:{and}…
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Question Number 89033 by M±th+et£s last updated on 14/Apr/20 Answered by ajfour last updated on 15/Apr/20 $${let}\:{center}\:{of}\:{square}\:{be}\:{origin}. \\ $$$${eq}.\:{of}\:{left}\:{circle}: \\ $$$$\left({x}+\frac{{r}}{\mathrm{2}}\right)^{\mathrm{2}} +{y}^{\mathrm{2}} ={r}^{\mathrm{2}} \\ $$$${let}\:{side}\:{of}\:{square}=\mathrm{2}{s}…
Question Number 23442 by chernoaguero@gmail.com last updated on 30/Oct/17 $$\mathrm{Find}\:\mathrm{a}\:\mathrm{unit}\:\mathrm{vector}\:\mathrm{which}\:\mathrm{is}\:\mathrm{perpendicula} \\ $$$$\mathrm{to}\:\mathrm{a}\:\mathrm{vector}\:\mathrm{A}\left(\mathrm{3coma5coma1}\right) \\ $$$$ \\ $$$$\mathrm{Sorry}\:\mathrm{for}\:\mathrm{writing}\:\mathrm{coma}\:\mathrm{cuz}\:\mathrm{i}\:\mathrm{dnt}\:\mathrm{see}\:\mathrm{a}\:\mathrm{key}\:\mathrm{for}\:\mathrm{it} \\ $$ Commented by $@ty@m last updated on 31/Oct/17…
Question Number 88860 by M±th+et£s last updated on 13/Apr/20 Commented by M±th+et£s last updated on 13/Apr/20 $${find}\:{the}\:{blue}\:{area}\: \\ $$ Commented by mahdi last updated on…
Question Number 88756 by mathocean1 last updated on 12/Apr/20 $$\mathrm{E}\:\mathrm{is}\:\mathrm{reported}\:\mathrm{in}\:\left(\overset{\rightarrow} {\mathrm{i}};\overset{\rightarrow} {\mathrm{j}}\right)\:\mathrm{base}. \\ $$$$\overset{\rightarrow} {\mathrm{e}}_{\mathrm{1}} =\mathrm{2}\overset{\rightarrow} {\mathrm{i}}+\mathrm{3}\overset{\rightarrow} {\mathrm{j}}\:;\:\:\:\overset{\rightarrow} {\mathrm{e}}_{\mathrm{2}} =\overset{\rightarrow} {\mathrm{i}}−\mathrm{2}\overset{\rightarrow} {\mathrm{j}}\:\mathrm{and}\:\:\:\overset{\rightarrow} {\mathrm{e}}_{\mathrm{3}} =\mathrm{4}\overset{\rightarrow} {\mathrm{i}}−\mathrm{5}\overset{\rightarrow}…
Question Number 88214 by M±th+et£s last updated on 09/Apr/20 Answered by ajfour last updated on 09/Apr/20 $${AB}={t}\:\:,\:\:{radius}={r}\:,\:{AD}={DC}={b} \\ $$$${upper}\:{section}\:{of}\:{OB}={c} \\ $$$${t}^{\mathrm{2}} =\mathrm{2}{b}^{\mathrm{2}} \:\:\:;\:\:\:\mathrm{tan}\:\alpha=\frac{{r}}{{t}+{r}} \\ $$$$\frac{\sqrt{{r}^{\mathrm{2}}…
Question Number 87759 by M±th+et£s last updated on 06/Apr/20 Commented by mr W last updated on 06/Apr/20 $$\Delta{DEC}\sim\Delta{ECF}\sim\Delta{PFE} \\ $$$$\frac{{r}_{{z}} }{{EF}}=\frac{{r}_{{y}} }{{FC}}=\frac{{r}_{{x}} }{{CE}}={k},\:{say} \\ $$$$\Rightarrow{CE}=\frac{{r}_{{x}}…
Question Number 87682 by john santu last updated on 05/Apr/20 $$\mathrm{what}\:\mathrm{is}\:\bigtriangledown^{\mathrm{2}} \left(\frac{\mathrm{1}}{\overset{\rightarrow} {\mathrm{r}}}\right)\:\mathrm{if}\: \\ $$$$\overset{\rightarrow} {\bigtriangledown}\:=\:\hat {\mathrm{i}}\:\frac{\partial}{\partial\mathrm{x}}+\hat {\mathrm{j}}\frac{\partial}{\partial\mathrm{y}}+\hat {\mathrm{k}}\:\frac{\partial}{\partial\mathrm{z}} \\ $$$$\mathrm{and}\:\overset{\rightarrow} {\mathrm{r}}\:=\:\hat {\mathrm{i}x}\:+\:\hat {\mathrm{j}y}\:+\:\hat {\mathrm{k}z}\:…
Question Number 87508 by M±th+et£s last updated on 04/Apr/20 Commented by M±th+et£s last updated on 04/Apr/20 $${ABCD}\:{is}\:{parallelogram} \\ $$$${find}\:{the}\:{area}\:{of}\:{the}\:{green}\:{triangle} \\ $$ Terms of Service Privacy…