Question Number 18907 by Nayon last updated on 01/Aug/17 $${Why}\:{Does}\: \\ $$$$\overset{\rightarrow} {{A}}.\overset{\rightarrow} {{B}}={ABCos}\theta?\: \\ $$ Commented by Nayon last updated on 01/Aug/17 $${Mr}.{w}\mathrm{1}\:{pls}\:{explain} \\…
Question Number 18908 by Nayon last updated on 01/Aug/17 $${Why}\:{Does} \\ $$$$\mid\overset{\rightarrow} {{A}}×\overset{\rightarrow} {{B}}\mid={ABSin}\theta\:? \\ $$ Commented by mrW1 last updated on 02/Aug/17 $$\mathrm{You}\:\mathrm{can}\:\mathrm{not}\:\mathrm{ask}\:\mathrm{why}\:\mathrm{to}\:\mathrm{a}\:\mathrm{definition}. \\…
Question Number 84296 by M±th+et£s last updated on 11/Mar/20 Commented by M±th+et£s last updated on 11/Mar/20 $${prove}\:{that}\:{m}\left(\angle{ADE}\right)=\mathrm{90}° \\ $$$$ \\ $$ Terms of Service Privacy…
Question Number 84275 by john santu last updated on 11/Mar/20 $$\left(\boldsymbol{\mathrm{a}}.\boldsymbol{\mathrm{c}}\right)\boldsymbol{\mathrm{b}}−\left(\boldsymbol{\mathrm{a}}.\boldsymbol{\mathrm{b}}\right)\boldsymbol{\mathrm{c}}\:=\:\boldsymbol{\mathrm{a}}×\left(\boldsymbol{\mathrm{c}}×\boldsymbol{\mathrm{b}}\right)\:? \\ $$ Commented by mr W last updated on 11/Mar/20 $$−\left(\boldsymbol{\mathrm{a}}.\boldsymbol{\mathrm{c}}\right)\boldsymbol{\mathrm{b}}+\left(\boldsymbol{\mathrm{a}}.\boldsymbol{\mathrm{b}}\right)\boldsymbol{\mathrm{c}}\:=\:\boldsymbol{\mathrm{a}}×\left(\boldsymbol{\mathrm{c}}×\boldsymbol{\mathrm{b}}\right) \\ $$$$\left(\boldsymbol{\mathrm{a}}.\boldsymbol{\mathrm{c}}\right)\boldsymbol{\mathrm{b}}−\left(\boldsymbol{\mathrm{a}}.\boldsymbol{\mathrm{b}}\right)\boldsymbol{\mathrm{c}}\:=\:\boldsymbol{\mathrm{a}}×\left(\boldsymbol{{b}}×\boldsymbol{{c}}\right) \\…
Question Number 18377 by tawa tawa last updated on 19/Jul/17 $$\mathrm{Suppose}\:\mathrm{one}\:\mathrm{is}\:\mathrm{given}\:\mathrm{two}\:\mathrm{vector}\:\mathrm{field}\:\mathrm{A}\:\mathrm{and}\:\mathrm{B}\:\mathrm{in}\:\mathrm{region}\:\mathrm{of}\:\mathrm{space}\:\mathrm{such}\:\mathrm{that}, \\ $$$$\mathrm{A}\left(\mathrm{x},\mathrm{y},\mathrm{z}\right)\:=\:\mathrm{4xi}\:+\:\mathrm{zj}\:+\:\mathrm{y}^{\mathrm{2}} \mathrm{z}^{\mathrm{2}} \mathrm{k} \\ $$$$\mathrm{B}\left(\mathrm{x},\mathrm{y},\mathrm{z}\right)\:=\:\mathrm{yi}\:+\mathrm{3j}\:−\:\mathrm{yzk} \\ $$$$\mathrm{Find}:\:\:\:\mathrm{C}\left(\mathrm{x},\mathrm{y},\mathrm{z}\right)\:\mathrm{if}\:\mathrm{C}\:=\:\mathrm{A}\:\wedge\:\mathrm{B} \\ $$$$\mathrm{Also}\:\mathrm{prove}\:\mathrm{that},\:\:\mathrm{C}\left(\mathrm{x},\mathrm{y},\mathrm{z}\right)\:\mathrm{is}\:\mathrm{perpendicular}\:\mathrm{to}\:\mathrm{A}\left(\mathrm{x},\mathrm{y},\mathrm{z}\right) \\ $$ Terms of…
Question Number 18284 by tawa tawa last updated on 18/Jul/17 $$\mathrm{If}\:\mathrm{k}\:\mathrm{is}\:\mathrm{any}\:\mathrm{possible}\:\mathrm{number}.\:\mathrm{what}\:\mathrm{is}\:\mathrm{the}\:\mathrm{size}\:\mathrm{of}\:\mathrm{angle}\:\mathrm{between}\:\mathrm{the}\:\mathrm{vectors} \\ $$$$\mathrm{a}\left(\mathrm{K},\:\mathrm{k}\right)\:\mathrm{and}\:\mathrm{b}\left(−\:\mathrm{3},\:\mathrm{4}\right) \\ $$ Answered by Arnab Maiti last updated on 18/Jul/17 $$\mathrm{let}\:\overset{\rightarrow} {\mathrm{A}}=\mathrm{K}\hat…
Question Number 18094 by Tinkutara last updated on 15/Jul/17 $$\overset{\rightarrow} {{A}},\:\overset{\rightarrow} {{B}}\:\mathrm{and}\:\overset{\rightarrow} {{C}}\:\mathrm{are}\:\mathrm{three}\:\mathrm{non}-\mathrm{collinear}, \\ $$$$\mathrm{non}\:\mathrm{co}-\mathrm{planar}\:\mathrm{vectors}.\:\mathrm{What}\:\mathrm{can}\:\mathrm{you} \\ $$$$\mathrm{say}\:\mathrm{about}\:\mathrm{direction}\:\mathrm{of}\:\overset{\rightarrow} {{A}}×\left(\overset{\rightarrow} {{B}}×\overset{\rightarrow} {{C}}\right)? \\ $$ Commented by ajfour…
Question Number 83556 by M±th+et£s last updated on 03/Mar/20 $${find}\:{the}\:{value}\:{of}\:\:\left({b}\right)\:{wich}\:{makes}\:{the} \\ $$$${line}\:{y}={b}\:{divide}\:{the}\:{tow}\:{funtions}\:{into} \\ $$$${tow}\:{equal}\:{parts} \\ $$$$ \\ $$$$\left.\mathrm{1}\right)\:{f}\left({x}\right)=\mathrm{9}−{x}^{\mathrm{2}} \:,\:{g}\left({x}\right)=\mathrm{0} \\ $$$$ \\ $$$$\left.\mathrm{2}\right){f}\left({x}\right)=\mathrm{9}−\mid{x}\mid\:,\:{g}\left({x}\right)=\mathrm{0} \\ $$…
Question Number 17959 by tawa tawa last updated on 13/Jul/17 Answered by alex041103 last updated on 13/Jul/17 $${Because}\:{j}=\sqrt{−\mathrm{1}}={i}\:{we}\:{can}\:{use} \\ $$$${Euler}'{s}\:{formula} \\ $$$${e}^{{ix}} ={cos}\:{x}\:+\:{isin}\:{x} \\ $$$${z}={e}^{\mathrm{1}+{i}\frac{\pi}{\mathrm{2}}}…
Question Number 83293 by ~blr237~ last updated on 29/Feb/20 $${Let}\:\:{A}\begin{pmatrix}{−\mathrm{2}}\\{−\mathrm{1}}\end{pmatrix}\:\:,{B}\begin{pmatrix}{\mathrm{1}}\\{\mathrm{3}}\end{pmatrix}\:,\:{C}\begin{pmatrix}{−\mathrm{10}}\\{\:\mathrm{5}}\end{pmatrix}\:{three}\:{given}\:{points}\:{in}\:{the}\:{brand}\:\left({O},{I},{J}\right)\:{such}\:{as}\:{OI}={OJ}\:{and}\:\left({OI}\right)\bot\left({OJ}\right) \\ $$$$\:{D}\:{is}\:{a}\:{point}\:{such}\:{as}\:{AD}={AC}+\mathrm{2}\:\:{and}\:\:{CD}=\mathrm{2}\: \\ $$$${Prove}\:{correctly}\:{that}\:\:{BD}=\mathrm{13}\:.{Can}\:{you}\:{find}\:{the}\:{coordinate}\:{of}\:{D}? \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com