Category: Vector

Question Number 15352 by Tinkutara last updated on 09/Jun/17 $$\mathrm{Let}\overrightarrow{a}=\stackrel{\wedge }{i}+4\stackrel{\wedge }{j}+2\stackrel{\wedge }{k},\overrightarrow{b}=3\stackrel{\wedge }{i}-2\stackrel{\wedge }{j}+7\stackrel{\wedge }{k}$$$$\mathrm{and}\:\overset{\rightarrow} {{c}}\:=\:\mathrm{2}\overset{\wedge} {{i}}\:−\:\overset{\wedge} {{j}}\:+\:\mathrm{4}\overset{\wedge} {{k}}\:.\:\mathrm{Find}\:\mathrm{a}\:\mathrm{vector}\:\overset{\rightarrow} {{d}}…

Question Number 146403 by gsk2684 last updated on 13/Jul/21 $$letf(x,y)=\frac{x^5{y}^2}{10}thenfind$$$$D_{u}f(-5,-3)inthedirectionof$$$$thevector<0,-2>?$$ Commented by gsk2684 last updated on…

Question Number 146315 by mnjuly1970 last updated on 12/Jul/21 Answered by Olaf_Thorendsen last updated on 13/Jul/21 $$\sqrt{\frac{x(x+5)}{x+2}}+\sqrt{x+3}=\frac{\sqrt{16x+32}}{x+2}$$$$\sqrt{\frac{x(x+5)}{x+2}}+\sqrt{x+3}=\frac{4}{\sqrt{x+2}}$$$$\sqrt{x(x+5)}+\sqrt{(x+3)(x+2)}=4$$$$\mathrm{Let}u=x+\frac{5}{2}$$$$\sqrt{\left({u}−\frac{\mathrm{5}}{\mathrm{2}}\right)\left({u}+\frac{\mathrm{5}}{\mathrm{2}}\right)}+\sqrt{\left({u}+\frac{\mathrm{1}}{\mathrm{2}}\right)\left({u}−\frac{\mathrm{1}}{\mathrm{2}}\right)}\:=\:\mathrm{4}…

Question Number 15202 by tawa tawa last updated on 08/Jun/17 $$\mathrm{if}\mathrm{z}=\mathrm{x}+\mathrm{jy},\mathrm{find}\mathrm{the}\mathrm{equations}\mathrm{of}\mathrm{the}\mathrm{two}\mathrm{loci}\mathrm{defined}\mathrm{by}:$$$$\left(\mathrm{a}\right)\mid \mathrm{z}-4\mid =3$$$$\left(\mathrm{b}\right)\arg (\mathrm{z}+2)=\frac{\pi }{6}$$ Terms of Service Privacy Policy Contact: info@tinkutara.com

Question Number 80642 by naaz last updated on 05/Feb/20 $$$$ Terms of Service Privacy Policy Contact: info@tinkutara.com