Question Number 14821 by Tinkutara last updated on 04/Jun/17 $$\mathrm{A}\:\mathrm{room}\:\mathrm{has}\:\mathrm{dimensions}\:\mathrm{3}\:\mathrm{m}\:×\:\mathrm{4}\:\mathrm{m}\:×\:\mathrm{5}\:\mathrm{m}. \\ $$$$\mathrm{A}\:\mathrm{fly}\:\mathrm{starting}\:\mathrm{at}\:\mathrm{one}\:\mathrm{corner}\:\mathrm{ends}\:\mathrm{up}\:\mathrm{at} \\ $$$$\mathrm{the}\:\mathrm{diametrically}\:\mathrm{opposite}\:\mathrm{corner}.\:\mathrm{If} \\ $$$$\mathrm{the}\:\mathrm{fly}\:\mathrm{were}\:\mathrm{to}\:\mathrm{walks},\:\mathrm{what}\:\mathrm{is}\:\mathrm{the}\:\mathrm{length} \\ $$$$\mathrm{of}\:\mathrm{the}\:\mathrm{shortest}\:\mathrm{path}\:\mathrm{it}\:\mathrm{can}\:\mathrm{take}? \\ $$ Answered by ajfour last updated…
Question Number 80237 by M±th+et£s last updated on 01/Feb/20 Commented by M±th+et£s last updated on 01/Feb/20 $${if}\:{ABCDEFG}\:{is}\:{a}\:{heptagon}\:{and}\:{AB}=\mathrm{1} \\ $$$${HIJKLM}\:{is}\:{hexagon}\: \\ $$$${than}\:{find}\:{HI} \\ $$ Commented by…
Question Number 14660 by 1kanika# last updated on 03/Jun/17 Commented by prakash jain last updated on 04/Jun/17 $$\mathrm{Can}\:\mathrm{u}\:\mathrm{use}\:\mathrm{camscanner}\:\mathrm{to}\:\mathrm{post} \\ $$$$\mathrm{pictures}\:\mathrm{of}\:\mathrm{printed}\:\mathrm{material}. \\ $$ Commented by 1kanika#…
Question Number 80119 by M±th+et£s last updated on 31/Jan/20 Answered by key of knowledge last updated on 31/Jan/20 $$\hat {\mathrm{C}}=\mathrm{108}\Rightarrow\mathrm{CD}=\mathrm{CB}\Rightarrow\mathrm{C}\hat {\mathrm{B}D}=\mathrm{36} \\ $$$$\mathrm{D}\hat {\mathrm{B}F}=\mathrm{F}\hat {\mathrm{B}A}=\frac{\mathrm{108}−\mathrm{36}}{\mathrm{2}}=\mathrm{36}…
Question Number 14587 by tawa tawa last updated on 02/Jun/17 $$\mathrm{Determine}\:\mathrm{the}\:\mathrm{roots}\:\mathrm{of}\:\mathrm{the}\:\mathrm{equation}\:\:\mathrm{x}^{\mathrm{3}} \:+\:\mathrm{64}\:=\:\mathrm{0}\:\:\mathrm{in}\:\mathrm{the}\:\mathrm{polar}\:\mathrm{form}\:\:\mathrm{a}\:+\:\mathrm{jb}, \\ $$$$\mathrm{Where}\:\:\mathrm{a}\:\:\mathrm{and}\:\:\mathrm{b}\:\:\mathrm{are}\:\mathrm{real}. \\ $$ Answered by mrW1 last updated on 03/Jun/17 $${x}={r}\left(\mathrm{cos}\:\theta+{i}\:\mathrm{sin}\:\theta\right) \\…
Question Number 79731 by M±th+et£s last updated on 27/Jan/20 Commented by M±th+et£s last updated on 27/Jan/20 $${AH}:{HC}=\mathrm{4}:\mathrm{3} \\ $$$${BG}:{GC}=\mathrm{5}:\mathrm{9} \\ $$$${find}\:{AF}:{FB} \\ $$ Commented by…
Question Number 14011 by Ruth1 last updated on 26/May/17 $$\mathrm{simplify}:\:\:\frac{\mathrm{4}\:−\:\mathrm{j5}}{\mathrm{1}\:+\:\mathrm{j2}} \\ $$ Commented by tawa tawa last updated on 26/May/17 $$\mathrm{Multiply}\:\mathrm{by}\:\mathrm{the}\:\mathrm{conjugate}\:\mathrm{both}\:\mathrm{numerator}\:\mathrm{and}\:\mathrm{denominator} \\ $$$$\frac{\left(\mathrm{4}\:−\:\mathrm{j5}\right)}{\left(\mathrm{1}\:+\:\mathrm{j2}\right)}\:×\:\frac{\left(\mathrm{1}\:−\:\mathrm{j2}\right)}{\left(\mathrm{1}\:−\:\mathrm{j2}\right)} \\ $$$$=\:\frac{\mathrm{4}\:−\:\mathrm{j8}\:−\:\mathrm{j5}\:+\:\mathrm{10j}^{\mathrm{2}}…
Question Number 13982 by tawa tawa last updated on 26/May/17 $$\mathrm{Find}\:\mathrm{the}\:\mathrm{root}\:\mathrm{of}\:\mathrm{the}\:\mathrm{equation} \\ $$$$\mathrm{z}^{\mathrm{2}} \:−\:\mathrm{8}\left(\mathrm{1}\:−\:\mathrm{i}\right)\mathrm{z}\:+\:\mathrm{63}\:−\:\mathrm{16i}\:=\:\mathrm{0} \\ $$ Answered by ajfour last updated on 26/May/17 $${let}\:{z}={x}+{iy} \\…
Question Number 79515 by TawaTawa last updated on 25/Jan/20 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 13942 by FilupS last updated on 25/May/17 $$\mathrm{for}\:\:\boldsymbol{{v}}=\begin{bmatrix}{{y}}\\{{x}}\end{bmatrix},\:\:\:\:\boldsymbol{{v}}\in\mathbb{R}^{\mathrm{2}} \\ $$$$\boldsymbol{{v}}\:\mathrm{has}\:\mathrm{basis}\:\mathrm{vectors}\:\hat {{i}}\:\mathrm{and}\:\hat {{j}} \\ $$$$\: \\ $$$$\mathrm{Assume}\:\mathrm{we}\:\mathrm{apply}\:\mathrm{a}\:\mathrm{basis}\:\mathrm{transform}\:\mathrm{to} \\ $$$$\mathrm{obtain}\:\mathrm{new}\:\mathrm{basis}\:\mathrm{vectors}\:\hat {{i}}'\:\mathrm{and}\:\hat {{j}}' \\ $$$$\: \\…