Question Number 337 by Vishal Bhardwaj last updated on 25/Jan/15 $$\int\left(\sqrt{{cotx}}+\sqrt{{tanx}}\right)\:{dx} \\ $$ Answered by prakash jain last updated on 22/Dec/14 $$\int\sqrt{\mathrm{cot}\:{x}}{dx}+\int\sqrt{\mathrm{tan}\:{x}}{dx} \\ $$$$\mathrm{Please}\:\mathrm{see}\:\mathrm{answer}\:\mathrm{to}\:\mathrm{Q119}\:\mathrm{for}\:\mathrm{integration} \\…
Question Number 225 by 123456 last updated on 25/Jan/15 $$\boldsymbol{\mathrm{u}}=\mathrm{2}\boldsymbol{\mathrm{i}}+\mathrm{3}\boldsymbol{\mathrm{j}}+\mathrm{5}\boldsymbol{\mathrm{k}} \\ $$$$\boldsymbol{\mathrm{v}}=\mathrm{3}\boldsymbol{\mathrm{i}}+\mathrm{2}\boldsymbol{\mathrm{j}}−\mathrm{5}\boldsymbol{\mathrm{k}} \\ $$$$\boldsymbol{\mathrm{w}}=−\mathrm{2}\boldsymbol{\mathrm{i}}+\mathrm{3}\boldsymbol{\mathrm{j}}+\boldsymbol{\mathrm{k}} \\ $$$$\mathrm{find} \\ $$$$\boldsymbol{\mathrm{u}}\centerdot\left(\boldsymbol{\mathrm{v}}×\boldsymbol{\mathrm{w}}\right)+\left(\boldsymbol{\mathrm{u}}×\boldsymbol{\mathrm{v}}\right)\centerdot\left(\boldsymbol{\mathrm{u}}×\boldsymbol{\mathrm{w}}\right) \\ $$ Answered by mreddy last updated…
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Question Number 78458 by kaivan.ahmadi last updated on 17/Jan/20 $${if}\:{I}_{{n}} =\int_{\mathrm{0}} ^{\frac{\pi}{\mathrm{4}}} {tan}^{{n}} {xdx}\:{and}\:{I}_{{n}} ={a}_{{n}} +{b}_{{n}} {I}_{{n}−\mathrm{2}} \:{then}\:{find}\:{a}_{\mathrm{10}} \\ $$ Commented by kaivan.ahmadi last updated…
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Question Number 78316 by mathocean1 last updated on 15/Jan/20 $$\mathrm{the}\:\mathrm{circle}\:\mathrm{represents}\:\mathrm{a}\:\mathrm{farm}\:\mathrm{where} \\ $$$$\left(\mathrm{LK}\right)\:\mathrm{is}\:\mathrm{symetric}\:\mathrm{axe}\:\mathrm{of}\:\mathrm{circle}\:\mathrm{such} \\ $$$$\mathrm{as}\:\forall\:\mathrm{M}\:\mathrm{of}\:\mathrm{this}\:\mathrm{circle}\:\mathrm{verifying} \\ $$$$\mathrm{ML}^{\mathrm{2}} −\mathrm{4MK}^{\mathrm{2}} =\mathrm{0}\:\:\mathrm{with}\:\mathrm{LK}=\mathrm{150m}. \\ $$$$\mathrm{calculate}\:\mathrm{the}\:\mathrm{radius}\:\mathrm{of}\:\mathrm{circle}. \\ $$$$\mathrm{please}\:\mathrm{help}\:\mathrm{me}… \\ $$ Commented…
Question Number 12752 by tawa last updated on 30/Apr/17 $$\mathrm{Let}\:\mathrm{V}\:\mathrm{and}\:\mathrm{W}\:\mathrm{be}\:\mathrm{4}\:\mathrm{dimensional}\:\mathrm{subspaces}\:\mathrm{of}\:\mathrm{a}\:\mathrm{7}\:\mathrm{dimensional}\:\mathrm{vector}\:\mathrm{space}\:\mathrm{X}. \\ $$$$\mathrm{Which}\:\mathrm{of}\:\mathrm{the}\:\mathrm{following}\:\mathrm{CANNOT}\:\mathrm{be}\:\mathrm{the}\:\mathrm{dimension}\:\mathrm{of}\:\mathrm{the}\:\mathrm{subspace}\:\mathrm{V}\cap\mathrm{W}. \\ $$$$\left(\mathrm{A}\right)\:\mathrm{0}\:\left(\mathrm{B}\right)\:\mathrm{1}\:\left(\mathrm{C}\right)\:\mathrm{2}\:\left(\mathrm{D}\right)\:\mathrm{3}\:\left(\mathrm{E}\right)\:\mathrm{4} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 78060 by aliesam last updated on 13/Jan/20 Commented by aliesam last updated on 13/Jan/20 $${the}\:{triangle}\:{is}\:{equilateral} \\ $$ Answered by ajfour last updated on…
Question Number 12442 by tawa last updated on 22/Apr/17 $$\mathrm{Solve}:\:\:\:\mathrm{z}^{\mathrm{4}} \:=\:−\:\mathrm{16} \\ $$ Answered by ajfour last updated on 22/Apr/17 $${z}^{\mathrm{4}} =\mathrm{2}^{\mathrm{4}} {e}^{{i}\left(\pi+\mathrm{2}{k}\pi\right)} \\ $$$${z}=\mathrm{2}{e}^{{i}\left(\frac{\pi}{\mathrm{4}}+\frac{\mathrm{2}{k}\pi}{\mathrm{4}}\:\right)}…
Question Number 77745 by mathocean1 last updated on 09/Jan/20 $$\mathrm{ABC}\:\mathrm{is}\:\mathrm{any}\:\mathrm{triangle}. \\ $$$$\mathrm{C}'\:.\:\mathrm{B}'\:\:.\mathrm{A}'\:\:\mathrm{are}\:\mathrm{respectively}\:\mathrm{middles} \\ $$$$\mathrm{of}\:\left[\mathrm{AB}\right]\:.\:\left[\mathrm{AC}\right]\:\:\mathrm{and}\:\:\left[\mathrm{BC}\right]. \\ $$$$\mathrm{we}\:\mathrm{suppose}\:\mathrm{that}\: \\ $$$$\mathrm{AB}=\mathrm{c}\:\:\:\mathrm{AC}=\mathrm{b}\:\:\:\:\mathrm{BC}=\mathrm{a}. \\ $$$$\left.\mathrm{1}\right)\:\overset{\rightarrow\:} {\mathrm{u}}=\mathrm{a}^{\mathrm{2}} \mathrm{B}\overset{\rightarrow} {\mathrm{C}}+\mathrm{b}^{\mathrm{2}\:} \overset{\rightarrow} {\mathrm{C}A}+\mathrm{c}^{\mathrm{2}}…