Category: Vector

Question Number 78458 by kaivan.ahmadi last updated on 17/Jan/20 $$if{I}_n={\int }_0^{\frac{\pi }{4}}{tan}^{n}xdxand{I}_n=a_n+b_n{I}_{n-2}thenfind{a}_{10}$$ Commented by kaivan.ahmadi last updated…

Question Number 78316 by mathocean1 last updated on 15/Jan/20 $$\mathrm{the}\mathrm{circle}\mathrm{represents}\mathrm{a}\mathrm{farm}\mathrm{where}$$$$\left(\mathrm{LK}\right)\mathrm{is}\mathrm{symetric}\mathrm{axe}\mathrm{of}\mathrm{circle}\mathrm{such}$$$$\mathrm{as}\mathrm{\forall }\mathrm{M}\mathrm{of}\mathrm{this}\mathrm{circle}\mathrm{verifying}$$$${\mathrm{ML}}^2-{4\mathrm{MK}}^2=0\mathrm{with}\mathrm{LK}=150\mathrm{m}.$$$$\mathrm{calculate}\mathrm{the}\mathrm{radius}\mathrm{of}\mathrm{circle}.$$$$\mathrm{please}\mathrm{help}\mathrm{me}\dots$$ Commented…

Question Number 78060 by aliesam last updated on 13/Jan/20 Commented by aliesam last updated on 13/Jan/20 $$thetriangleisequilateral$$ Answered by ajfour last updated on…

Question Number 77745 by mathocean1 last updated on 09/Jan/20 $$\mathrm{ABC}\mathrm{is}\mathrm{any}\mathrm{triangle}.$$$${\mathrm{C}}^{\prime }.{\mathrm{B}}^{\prime }.{\mathrm{A}}^{\prime }\mathrm{are}\mathrm{respectively}\mathrm{middles}$$$$\mathrm{of}\left[\mathrm{AB}\right].\left[\mathrm{AC}\right]\mathrm{and}\left[\mathrm{BC}\right].$$$$\mathrm{we}\mathrm{suppose}\mathrm{that}$$$$\mathrm{AB}=\mathrm{c}\mathrm{AC}=\mathrm{b}\mathrm{BC}=\mathrm{a}.$$$$\left.\mathrm{1}\right)\:\overset{\rightarrow\:} {\mathrm{u}}=\mathrm{a}^{\mathrm{2}} \mathrm{B}\overset{\rightarrow} {\mathrm{C}}+\mathrm{b}^{\mathrm{2}\:} \overset{\rightarrow} {\mathrm{C}A}+\mathrm{c}^{\mathrm{2}}…

Question Number 143127 by liberty last updated on 10/Jun/21 Answered by EDWIN88 last updated on 11/Jun/21 $$\mathrm{Let}\{\begin{array}{l}\overrightarrow{\mathrm{a}}=\mathrm{QR}=(1,3,-1)\\ \overrightarrow{\mathrm{b}}=\mathrm{QS}=(-3,2,3)\\ \overrightarrow{\mathrm{c}}=\mathrm{QP}=(0,3,3)\end{array}$$$$\mathrm{distance}\mathrm{d}\mathrm{from}\mathrm{P}\mathrm{to}\mathrm{plane}\mathrm{is}$$$$\:\:\:\:\:\:\:\:\:\mathrm{d}\:=\:\frac{\mid\overset{\rightarrow} {\mathrm{a}}.\left(\overset{\rightarrow}…