Question Number 9970 by Tawakalitu ayo mi last updated on 19/Jan/17 Answered by mrW1 last updated on 19/Jan/17 $${the}\:{result}\:{is}\:{a}\:{zero}\:{vector}\:{or}\:{null}\:{vector}\:\left(\overset{\rightarrow} {\mathrm{0}}\right). \\ $$$${a}\:{zero}\:{or}\:{null}\:{vector}\:{has}\:{no}\:{magnitude}. \\ $$ Commented…
Question Number 9836 by tawakalitu last updated on 06/Jan/17 $$\mathrm{Prove}\:\mathrm{that}. \\ $$$$\mid\mathrm{z}_{\mathrm{1}} \:+\:\mathrm{z}_{\mathrm{2}} \mid\:\leqslant\:\mid\mathrm{z}_{\mathrm{1}} \mid\:\mid\mathrm{z}_{\mathrm{2}} \mid \\ $$ Commented by FilupSmith last updated on 07/Jan/17…
Question Number 9756 by tawakalitu last updated on 31/Dec/16 $$\mathrm{What}\:\mathrm{is}\:\mathrm{the}\:\mathrm{equation}\:\mathrm{of}\:\mathrm{the}\:\mathrm{straight}\:\mathrm{line}\: \\ $$$$\mathrm{passing}\:\mathrm{through}\:\mathrm{the}\:\mathrm{point}\:\hat {\mathrm{i}}−\:\mathrm{2},\:\mathrm{k}\:\mathrm{and} \\ $$$$\mathrm{3k}\:−\:\mathrm{2j}.\:\mathrm{Find}\:\mathrm{where}\:\mathrm{the}\:\mathrm{line}\:\mathrm{cut}\:\mathrm{the}\:\mathrm{plane} \\ $$$$\mathrm{through}\:\mathrm{the}\:\mathrm{origin}\:\mathrm{and}\:\mathrm{the}\:\mathrm{point}\:\mathrm{4j}\:\mathrm{and}\:\mathrm{2}\hat {\mathrm{i}}+\:\mathrm{k} \\ $$ Terms of Service Privacy Policy…
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Question Number 9715 by tawakalitu last updated on 28/Dec/16 $$\mathrm{Vector}\:\overset{\rightarrow} {\mathrm{A}}\:\mathrm{of}\:\mathrm{magnitude}\:\mathrm{20}\:\mathrm{unit},\:\mathrm{lies}\:\mathrm{in}\:\mathrm{the}\: \\ $$$$\mathrm{direction}\:\mathrm{45}°\mathrm{S}\:\mathrm{of}\:\mathrm{E}\:\mathrm{while}\:\mathrm{vector}\:\overset{\rightarrow} {\mathrm{B}}\:\mathrm{of}\:\mathrm{magnitude} \\ $$$$\mathrm{30}\:\mathrm{units}\:\mathrm{in}\:\mathrm{the}\:\mathrm{direction}\:\mathrm{60}°\mathrm{W}\:\mathrm{of}\:\mathrm{N}. \\ $$$$\mathrm{calculate}\:\mathrm{the}\:\mathrm{scaler}\:\mathrm{product}\:\:\overset{\rightarrow} {\mathrm{A}}\centerdot\overset{\rightarrow} {\mathrm{B}} \\ $$ Answered by sandy_suhendra…
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Question Number 140690 by liberty last updated on 11/May/21 $$\:\mathrm{Vector}\: \\ $$$$\mathrm{let}\:\mathcal{L}_{\mathrm{1}} =\:\mathrm{AC}\:\mathrm{where}\:\mathrm{A}=\left(\mathrm{2},−\mathrm{1},\mathrm{3}\right)\:\mathrm{and} \\ $$$$\mathrm{C}=\left(\mathrm{1},\mathrm{0},−\mathrm{5}\right)\mathrm{and}\:\mathrm{let}\:\mathcal{L}_{\mathrm{2}} =\:\mathrm{BD}\:\mathrm{where} \\ $$$$\mathrm{B}=\left(\mathrm{1},\mathrm{3},\mathrm{0}\right)\:\mathrm{and}\:\mathrm{D}=\left(\mathrm{3},−\mathrm{4},\mathrm{1}\right).\:\mathrm{Determine} \\ $$$$\mathrm{the}\:\mathrm{distance}\:\mathrm{between}\:\mathcal{L}_{\mathrm{1}} \:\mathrm{and}\:\mathcal{L}_{\mathrm{2}} . \\ $$ Answered…
Find-the-coordinates-of-2-0-when-the-axes-are-rotated-counterclockwise-through-the-angle-arcsin-4-5-
Question Number 140666 by john_santu last updated on 11/May/21 $${Find}\:{the}\:{coordinates}\:{of}\:\left(−\mathrm{2},\mathrm{0}\right)\: \\ $$$${when}\:{the}\:{axes}\:{are}\:{rotated}\:{counterclockwise} \\ $$$${through}\:{the}\:{angle}\:\mathrm{arcsin}\:\frac{\mathrm{4}}{\mathrm{5}}. \\ $$ Answered by bemath last updated on 11/May/21 $$\begin{cases}{\mathrm{x}'=\mathrm{x}\:\mathrm{cos}\:\theta−\mathrm{ysin}\:\theta}\\{\mathrm{y}'=\mathrm{xsin}\:\theta+\mathrm{ycos}\:\theta}\end{cases} \\…
Question Number 9553 by tawakalitu last updated on 14/Dec/16 $$\mathrm{Find}\::\:\:\:\mathrm{u}\centerdot\mathrm{v} \\ $$$$\left(\mathrm{i}\right)\:\:\:\mathrm{f}\left(\mathrm{z}\right)\:=\:\mid\mathrm{z}\mid^{\mathrm{2}} \\ $$$$\left(\mathrm{ii}\right)\:\:\mathrm{f}\left(\mathrm{z}\right)\:=\:\mathrm{z}\:+\:\frac{\mathrm{1}}{\mathrm{z}} \\ $$ Commented by geovane10math last updated on 14/Dec/16 $${z}\:\mathrm{is}\:\mathrm{complex}\:? \\…
Question Number 140502 by benjo_mathlover last updated on 08/May/21 $$\mathrm{If}\:\mathrm{three}\:\mathrm{vector}\:\overset{\rightarrow} {\mathrm{a}}\:,\:\overset{\rightarrow} {\mathrm{b}}\:\mathrm{and}\:\overset{\rightarrow} {\mathrm{c}}\:\mathrm{are}\: \\ $$$$\mathrm{such}\:\mathrm{that}\:\overset{\rightarrow} {\mathrm{a}}\:\neq\:\mathrm{0}\:\mathrm{and}\:\overset{\rightarrow} {\mathrm{a}}×\overset{\rightarrow} {\mathrm{b}}\:=\:\mathrm{2}\left(\overset{\rightarrow} {\mathrm{a}}×\overset{\rightarrow} {\mathrm{c}}\right) \\ $$$$,\mid\overset{\rightarrow} {\mathrm{a}}\mid\:=\:\mid\overset{\rightarrow} {\mathrm{c}}\mid\:=\:\mathrm{1}\:,\:\mid\overset{\rightarrow} {\mathrm{b}}\mid\:=\:\mathrm{4}\:\mathrm{and}\:\mathrm{the}\:…