Question Number 6820 by Tawakalitu. last updated on 29/Jul/16 $${The}\:{position}\:{vector}\:{of}\:{the}\:{point}\:{P}\:\:{at}\:{time}\:{t}\:{is}\:{given}\:{by}\: \\ $$$$\left(\alpha{tant}\right){i}\:+\:\left(\alpha{sect}\right){k}\:{where}\:\alpha\:{is}\:{positive}\:{constant}\:{and} \\ $$$$\mathrm{0}\leqslant{t}\leqslant\frac{\Pi}{\mathrm{2}}.\:\:{Show}\:{that}\:{the}\:{velocity}\:{and}\:{acceleration}\:{of}\:{P}\:\:{when} \\ $$$${t}\:=\:\mathrm{0}\:{are}\:{at}\:{right}\:{angle}\:{to}\:{each}\:{other}.\:{If}\:{A}\:{is}\:{the}\:{point}\:{with}\: \\ $$$${position}\:{vector}\:\alpha{j},\:{obtain}\:{the}\:{vector}\:{equation}\:{for}\:{the}\:{straight}\: \\ $$$${line}\:{AP}\:{at}\:{time}\:{t}.\:\:{If}\:{the}\:{point}\:{Q}\:{divides}\:{AP}\:\:{internally}\:{in}\:{the} \\ $$$${ratio}\:\left({cost}\right)\::\:\left(\mathrm{1}\:−\:{cost}\right).\:{Show}\:{that}\:{the}\:{acceleration}\:{of}\:{the}\:{point} \\ $$$${Q}\:{is}\:{constant}\:{in}\:{magnitude}\:{and}\:{is}\:{always}\:{directed}\:{towards}\:{a}\: \\…
Question Number 6778 by Tawakalitu. last updated on 24/Jul/16 $${If}\:{two}\:{forces}\:{P}\:{and}\:{Q}\:{acting}\:{at}\:\mathrm{0}\:{are}\:{represented}\:{by}\:{line}\:{OA} \\ $$$${and}\:{OB}\:{with}\:\phi\:{being}\:{the}\:{angle}\:{between}\:{the}\:{two}\:{forces}\:. \\ $$$${find}\:{their}\:{resultant}\:{in}\:{R}\:{in}\:{terms}\:{of}\:{P} \\ $$ Commented by prakash jain last updated on 25/Jul/16 $$\mathrm{By}\:\mathrm{cosine}\:\mathrm{rule}…
Question Number 6458 by sanusihammed last updated on 27/Jun/16 $${Find}\:{the}\:{curl}\:{of}\:{A} \\ $$$${if}\:{A}\:=\:\mathrm{3}{n}^{\mathrm{2}} {yi}\:−\:{yz}^{\mathrm{2}} {j}\:−\:{nzk} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 71986 by rajesh4661kumar@gmail.com last updated on 23/Oct/19 Answered by mind is power last updated on 23/Oct/19 $$\mathrm{not}\:\mathrm{unique}\:\mathrm{angle} \\ $$$$\mathrm{XY}=\left\{\left(\mathrm{x},\mathrm{y},\mathrm{z}\right)\in\mathbb{R}^{\mathrm{3}} :\mathrm{z}=\mathrm{0}\right\} \\ $$$$\mathrm{angle}\:\mathrm{between}\:\mathrm{vecror}\:\mathrm{and}\:\mathrm{plane}\:\mathrm{is}\:\mathrm{not}\:\mathrm{defind}\: \\…
Question Number 6374 by sanusihammed last updated on 25/Jun/16 $${Show}\:{that} \\ $$$$\overset{−} {{a}}\:×\:\left({b}\:×\:{c}\right)\:=\:\left(\overset{−} {{a}}\:.\:\overset{−} {{c}}\right)\overset{−} {{b}}\:\:−\:\:\left(\overset{−} {{a}}\:.\:\overset{−} {{b}}\right)\overset{−} {{c}} \\ $$ Commented by FilupSmith last…
Question Number 6321 by sanusihammed last updated on 23/Jun/16 $${Determine}\:\in\:{and}\:{N}\:{by}\:{using}\:{vector}\:{such}\:{that}\:{point}\:\left(−\mathrm{1},\mathrm{3},\mathrm{2}\right), \\ $$$$\left(−\mathrm{4},−\mathrm{2},−\mathrm{2}\right)\:{and}\:\left(\mathrm{5},\in,{N}\right)\:{lies}\:{on}\:{a}\:{straight}\:{line} \\ $$$$ \\ $$ Answered by nburiburu last updated on 23/Jun/16 $${let}'{s}\:{find}\:{the}\:{line}: \\…
Question Number 136300 by liberty last updated on 20/Mar/21 $${Let}\:{vector}\:\overset{\rightarrow} {{a}}\:,\:\overset{\rightarrow} {{b}}\:{and}\:\overset{\rightarrow} {{c}}\:{such}\:{that} \\ $$$$\mid\overset{\rightarrow} {{a}}\mid=\mid\overset{\rightarrow} {{b}}\mid=\frac{\mid\overset{\rightarrow} {{c}}\mid}{\mathrm{2}}\:{and}\:\overset{\rightarrow} {{a}}×\left(\overset{\rightarrow} {{a}}×\overset{\rightarrow} {{c}}\right)+\overset{\rightarrow} {{b}}=\mathrm{0} \\ $$$${find}\:{the}\:{acute}\:{angle}\:{between}\:\overset{\rightarrow} {{a}}\:{and}\:\overset{\rightarrow}…
Question Number 135965 by liberty last updated on 17/Mar/21 $${Vector} \\ $$Three vectors satisfy a.b = b.c = c.a = -1 and a + b…
Question Number 135821 by mnjuly1970 last updated on 16/Mar/21 $$\:\:\:\:\:\:\:\:\:\:\:\:\:….{nice}\:\:\:…..\:\:\:{calculus}….\: \\ $$$$\:\:\:\:{prove}\:{that}\::: \\ $$$$\:\:\:\:\boldsymbol{\phi}=\int_{\mathrm{0}} ^{\:\mathrm{1}} \left(\frac{{ln}\left(\mathrm{1}−{x}\right)}{\mathrm{1}−\sqrt{\mathrm{1}−{x}}}\right){dx}=\mathrm{4}\left(\mathrm{1}−\zeta\left(\mathrm{2}\right)\right) \\ $$$$ \\ $$ Answered by mathmax by abdo…
Question Number 135790 by benjo_mathlover last updated on 16/Mar/21 $${Find}\:{the}\:{component}\:{form}\:{of} \\ $$$${the}\:{vector}\:{that}\:{reprecents}\:{the} \\ $$$${velocity}\:{of}\:{an}\:{airplane}\:{descending} \\ $$$${at}\:{speed}\:{of}\:\mathrm{150}\:{miles}\:{per}\:{hour} \\ $$$${at}\:{angle}\:\mathrm{20}°\:{below}\:{the}\:{horizontal} \\ $$ Terms of Service Privacy Policy…