Question Number 127566 by Ar Brandon last updated on 30/Dec/20 Answered by bramlexs22 last updated on 30/Dec/20 $$\left(\overset{\rightarrow} {\mathrm{a}}+\overset{\rightarrow} {\mathrm{b}}\right)×\left(\overset{\rightarrow} {\mathrm{a}}−\overset{\rightarrow} {\mathrm{b}}\right)=\overset{\rightarrow} {\mathrm{a}}×\overset{\rightarrow} {\mathrm{a}}−\overset{\rightarrow} {\mathrm{a}}×\overset{\rightarrow}…
Question Number 127568 by Ar Brandon last updated on 30/Dec/20 Commented by bramlexs22 last updated on 30/Dec/20 $$\mathrm{R}_{\mathrm{max}} \:=\:\sqrt{\mid\overset{\rightarrow} {\mathrm{a}}\mid^{\mathrm{2}} +\mid\overset{\rightarrow} {\mathrm{b}}\mid^{\mathrm{2}} +\mathrm{2}\mid\overset{\rightarrow} {\mathrm{a}}\mid\mid\overset{\rightarrow} {\mathrm{b}}\mid}\:…
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Question Number 126786 by Ar Brandon last updated on 24/Dec/20 Answered by Olaf last updated on 26/Dec/20
Question Number 126778 by Ar Brandon last updated on 24/Dec/20 Answered by Dwaipayan Shikari last updated on 24/Dec/20 $$\sqrt{\left(\overset{\rightarrow} {{A}}_{\mathrm{1}} \right)^{\mathrm{2}} +\left(\overset{\rightarrow} {{A}}_{\mathrm{2}} \right)^{\mathrm{2}} +\mathrm{2}\mid\overset{\rightarrow}…
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