Question Number 210729 by peter frank last updated on 18/Aug/24 Answered by Spillover last updated on 18/Aug/24 Answered by Spillover last updated on 18/Aug/24 $${R}=\mathrm{3}{k}\Omega+\mathrm{1}{k}\Omega+\mathrm{2}{k}\Omega=\mathrm{6}{k}\Omega=\mathrm{6000}\Omega…
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Question Number 130658 by Study last updated on 27/Jan/21 Commented by Study last updated on 28/Jan/21 $${solve}! \\ $$ Answered by Ar Brandon last updated…
Question Number 58203 by Umar last updated on 19/Apr/19 $$\mathrm{A}\:\mathrm{battery}\:\mathrm{can}\:\mathrm{supply}\:\mathrm{current}\:\mathrm{of}\:\mathrm{1}.\mathrm{2A}\: \\ $$$$\mathrm{and}\:\mathrm{0}.\mathrm{4A}\:\mathrm{through}\:\mathrm{4}\Omega\:\mathrm{and}\:\mathrm{14}\Omega\:\:\mathrm{respectively}. \\ $$$$\mathrm{Calculate}\:\mathrm{the}\:\mathrm{internal}\:\mathrm{resistance}\:\mathrm{of}\:\mathrm{the}\:\mathrm{battery} \\ $$ Answered by mr W last updated on 19/Apr/19 $${let}\:{X}={internal}\:{resistance}\:{of}\:{battery}…
Question Number 57525 by Umar last updated on 06/Apr/19 Answered by tanmay.chaudhury50@gmail.com last updated on 07/Apr/19 $${c}=\frac{{q}}{{v}}=\frac{\mathrm{10}×\mathrm{10}^{−\mathrm{6}} }{\mathrm{10}}=\mathrm{10}^{−\mathrm{6}} {F} \\ $$$${v}=\frac{{q}}{{c}}=\frac{\mathrm{100}×\mathrm{10}^{−\mathrm{6}} }{\mathrm{10}^{−\mathrm{6}} }=\mathrm{100}\:{volt} \\ $$…
Question Number 57462 by Umar last updated on 04/Apr/19 $$\mathrm{Two}\:\mathrm{conductors}\:\mathrm{has}\:\mathrm{total}\:\mathrm{charge}\:\mathrm{of} \\ $$$$+\mathrm{10}.\mathrm{0}\mu\mathrm{C}\:\mathrm{and}\:−\mathrm{10}\mu\mathrm{C}\:\mathrm{with}\:\mathrm{10volt}\: \\ $$$$\mathrm{between}\:\mathrm{them}. \\ $$$$\:\left(\mathrm{a}\right)\:\mathrm{Determine}\:\mathrm{the}\:\mathrm{capacitance}\:\mathrm{between}\:\mathrm{them} \\ $$$$\:\left(\mathrm{b}\right)\:\mathrm{what}\:\mathrm{is}\:\mathrm{the}\:\mathrm{p}.\mathrm{d}\:\mathrm{between}\:\mathrm{the}\:\mathrm{two} \\ $$$$\:\:\:\:\:\:\:\:\:\mathrm{condoctors}\:\mathrm{if}\:\mathrm{the}\:\mathrm{charge}\:\mathrm{on}\:\mathrm{each} \\ $$$$\:\:\:\:\:\:\:\:\:\:\mathrm{are}\:\mathrm{increased}\:\mathrm{to}\:+\mathrm{100}\mu\mathrm{C}\:\mathrm{and}\: \\ $$$$\:\:\:\:\:\:\:\:\:\:\:−\mathrm{100}\mu\mathrm{C}\:\mathrm{respectively}\:? \\…
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Question Number 55970 by necx1 last updated on 07/Mar/19 Answered by tanmay.chaudhury50@gmail.com last updated on 07/Mar/19 $$\mathrm{10}\mu{F}\:{and}\:\mathrm{10}\mu{F}\:{are}\:{parallel} \\ $$$${so}\:\mathrm{10}+\mathrm{10}=\mathrm{20}\mu{F} \\ $$$$\mathrm{15}\mu{F}\:{and}\:\mathrm{5}\mu{F}\:{are}\:{parallel} \\ $$$${so}\:\mathrm{15}+\mathrm{5}=\mathrm{20}\mu{F} \\ $$$${now}\:{this}\:\mathrm{20}\mu{F}\:{and}\:\mathrm{20}\mu{F}\:{are}\:{series}…
Question Number 51728 by aseerimad last updated on 30/Dec/18 Commented by aseerimad last updated on 30/Dec/18 please help! Commented by tanmay.chaudhury50@gmail.com last updated on 30/Dec/18 Commented…
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