Question Number 36548 by rahul 19 last updated on 03/Jun/18 Answered by tanmay.chaudhury50@gmail.com last updated on 03/Jun/18 $${Q}=\frac{{kA}\left(\theta_{\mathrm{2}} −\theta_{\mathrm{1}} \right){t}}{{l}}=\frac{{i}^{\mathrm{2}} {Rt}}{{J}}=\frac{\left({V}\right)^{\mathrm{2}} {t}}{{R}\:{J}} \\ $$$${A}=\left(\mathrm{40}−\mathrm{2}×\mathrm{0}.\mathrm{1}\right)^{\mathrm{2}} =\mathrm{1584}.\mathrm{04}{cm}^{\mathrm{2}}…
Question Number 36529 by rahul 19 last updated on 03/Jun/18 $$\mathrm{A}\:\mathrm{fuse}\:\mathrm{with}\:\mathrm{a}\:\mathrm{circular}\:\mathrm{cross}−\mathrm{sectional} \\ $$$$\mathrm{radius}\:\mathrm{of}\:\mathrm{0}.\mathrm{15}\:\mathrm{mm}\:\mathrm{blows}\:\mathrm{at}\:\mathrm{15A}.\:\mathrm{What} \\ $$$$\mathrm{should}\:\mathrm{be}\:\mathrm{the}\:\mathrm{radius}\:\mathrm{of}\:\mathrm{the}\:\mathrm{cross}\:\mathrm{section} \\ $$$$\mathrm{of}\:\mathrm{a}\:\mathrm{fuse}\:\mathrm{made}\:\mathrm{of}\:\mathrm{same}\:\mathrm{material}\:\mathrm{that} \\ $$$$\mathrm{blows}\:\mathrm{at}\:\mathrm{30A}? \\ $$ Answered by tanmay.chaudhury50@gmail.com last…
Question Number 36279 by Cheyboy last updated on 31/May/18 $${Consider}\:{a}\:{particle}\:{in}\:{a}\: \\ $$$${uniformly}\:{charge}\:{electric}\:{field}, \\ $$$${if}\:{the}\:{particle}\:{has}\:{a}\:{charge}\:{of}\:\mathrm{2}{C} \\ $$$${and}\:{is}\:{place}\:\mathrm{3}{m}\:{away}\:{from}\:{the} \\ $$$${charge}\:{plate}. \\ $$$$\boldsymbol{{calculate}}\:\boldsymbol{{the}}\:\boldsymbol{{work}}\:\boldsymbol{{needed}}\:\boldsymbol{{to}} \\ $$$$\boldsymbol{{move}}\:\boldsymbol{{the}}\:\mathrm{2}\boldsymbol{{C}}\:\boldsymbol{{particle}}\:\boldsymbol{{to}}\:\boldsymbol{{a}} \\ $$$$\boldsymbol{{distance}}\:\boldsymbol{{of}}\:\mathrm{1}\boldsymbol{{m}}\:\boldsymbol{{from}}\:\boldsymbol{{the}}\: \\…
Question Number 36227 by Cheyboy last updated on 30/May/18 $$\mathrm{1}×\mathrm{10}^{\mathrm{7}\:} {electrons}\:{pass}\:{through}\:{a}\: \\ $$$${conductor}\:{in}\:\mathrm{1}.\mathrm{0}\mu{s}.{Find}\:{the}\: \\ $$$${current}\:{in}\:{Amperes}\:{flowing} \\ $$$${through}\:{the}\:{conductor}. \\ $$$${electronic}\:{charge}=\mathrm{1}.\mathrm{6}×\mathrm{10}^{−\mathrm{19}} {C} \\ $$ Answered by tanmay.chaudhury50@gmail.com…
Question Number 36140 by Cheyboy last updated on 29/May/18 Commented by Cheyboy last updated on 29/May/18 $${Find}\:{the}\:{current}\:{and}\:{voltage}\:{of} \\ $$$${the}\:{letters}\:{A}\:{to}\:{L} \\ $$$$ \\ $$ Answered by…
Question Number 35507 by ajfour last updated on 19/May/18 Commented by ajfour last updated on 19/May/18 $${Solution}\:{to}\:{Q}.\mathrm{35502} \\ $$ Commented by rahul 19 last updated…
Question Number 35502 by rahul 19 last updated on 19/May/18 Commented by rahul 19 last updated on 19/May/18 $${Ans}.\:{is}\:\mathrm{2}\Omega. \\ $$ Commented by rahul 19…
Question Number 35496 by ajfour last updated on 19/May/18 Commented by ajfour last updated on 19/May/18 $${Solution}\:{to}\:{Q}.\mathrm{35493} \\ $$ Answered by ajfour last updated on…
Question Number 35493 by ajfour last updated on 19/May/18 Commented by ajfour last updated on 19/May/18 $${If}\:{switch}\:{S}\:{is}\:{closed}\:{at}\:{t}=\mathrm{0},\:{find} \\ $$$${charge}\:{on}\:{capacitor}\:{as}\:{a}\:{function} \\ $$$${of}\:{time}. \\ $$ Commented by…
Question Number 34954 by ajfour last updated on 13/May/18 Commented by ajfour last updated on 13/May/18 $${Find}\:{resistance}\:{of}\:{a}\:{cylindrical} \\ $$$${conductor}\:{of}\:{radius}\:\boldsymbol{{b}}\:{and}\:{thickness} \\ $$$$\boldsymbol{{t}}\:{with}\:{a}\:{concentric}\:{hole}\:{of}\:{radius} \\ $$$$\boldsymbol{{a}},\:{across}\:{its}\:{inner}\:{and}\:{outer} \\ $$$${surfaces}.\left({conductivity}\:\:{given}\:\sigma\:\right)\:.…