Question Number 90632 by awlia last updated on 25/Apr/20 Answered by ajfour last updated on 25/Apr/20 $$−{i}\left(\mathrm{10}\Omega\right)+\mathrm{10}{V}−\mathrm{2}{i}\left(\mathrm{5}\Omega\right)+\mathrm{5}{V}=\mathrm{0} \\ $$$$\left({for}\:{the}\:{left}\:{loop}\:{or}\:{right}\:{loop}\right) \\ $$$$\Rightarrow\:\:\mathrm{3}{i}=\frac{\mathrm{15}{V}}{\mathrm{15}\Omega}\:=\:\mathrm{1}{A} \\ $$$${current}\:{in}\:\mathrm{5}\Omega\:{is}\:=\:\mathrm{2}{i}\:=\:\frac{\mathrm{2}}{\mathrm{3}}{A}. \\ $$…
Question Number 155893 by n0y0n last updated on 05/Oct/21 $$\: \\ $$$$\:\:\mathrm{Two}\:\mathrm{Spheres}\:\mathrm{are}\:\mathrm{charged}\:\mathrm{by}\:+\mathrm{3}\mu\mathrm{C}\:\mathrm{and} \\ $$$$−\mathrm{3}\mu\mathrm{C}\:\mathrm{respectively}.\mathrm{The}\:\mathrm{charges}\:\mathrm{are}\: \\ $$$$\:\:\mathrm{equally}\:\mathrm{distributed}\:\mathrm{in}\:\mathrm{the}\:\mathrm{serface}\:\mathrm{of}\:\mathrm{the}\: \\ $$$$\:\:\mathrm{sphere}\:.\mathrm{The}\:\mathrm{distance}\:\mathrm{between}\:\mathrm{two}\: \\ $$$$\:\:\mathrm{spheres}\:\mathrm{is}\:\mathrm{100cm}\:.\:\mathrm{Now}\:\mathrm{if}\:\mathrm{we}\:\mathrm{Connect} \\ $$$$\:\:\mathrm{these}\:\mathrm{two}\:\mathrm{spheres}\:\mathrm{with}\:\mathrm{a}\:\mathrm{conducting}\: \\ $$$$\:\:\mathrm{wire}\:, \\…
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Question Number 154226 by mathocean1 last updated on 15/Sep/21 $${Given}\:{i}\left({t}\right)=\mathrm{25}{cos}\left(\omega{t}\right)\:; \\ $$$${u}\left({t}\right)=\mathrm{50}\left[\mathrm{1}+\left(\omega{t}\right)^{\frac{\mathrm{2}}{\mathrm{2}!}} +\left(\omega{t}\right)^{\frac{\mathrm{4}}{\mathrm{4}!}} +\left(\omega{t}\right)^{\frac{\mathrm{6}}{\mathrm{6}!}} +…\right]\:. \\ $$$$\frac{\mathrm{1}}{{T}}\underset{\mathrm{0}} {\overset{{T}} {\int}}{u}\left({t}\right)×{i}\left({t}\right){dt}=??? \\ $$$${choose}\:{the}\:{correct}\:{answer}: \\ $$$${a}.\:\mathrm{225} \\ $$$${b}.\:\mathrm{425}…
Question Number 88270 by Rio Michael last updated on 09/Apr/20 Commented by Rio Michael last updated on 09/Apr/20 $$\mathrm{Given}\:\mathrm{the}\:\mathrm{circuit}\:\mathrm{above}\:\mathrm{containing}\:\mathrm{two}\:\mathrm{cells}\:\mathrm{X}\:\mathrm{and}\:\mathrm{Y} \\ $$$$\mathrm{of}\:\mathrm{emf}\:\mathrm{6}\:\mathrm{V}\:,\mathrm{8}\:\mathrm{V}\:,\:\mathrm{2}\:\Omega\:\mathrm{and}\:\mathrm{4}\Omega\:\mathrm{of}\:\mathrm{emf}\:\mathrm{and}\:\mathrm{internal}\:\mathrm{resistance} \\ $$$$\mathrm{respectively}.\:\mathrm{find}\:\mathrm{the}\:\mathrm{terminal}\:\mathrm{pd}\:\mathrm{of}\:\mathrm{X}\:\mathrm{and}\:\mathrm{Y}\:\mathrm{if}\:\mathrm{both}\: \\ $$$$\mathrm{cells}\:\mathrm{are}\:\mathrm{connected}\:\mathrm{to}\:\mathrm{a}\:\mathrm{10}\Omega\:\mathrm{resistor}.…
Question Number 84845 by Rio Michael last updated on 16/Mar/20 Commented by Rio Michael last updated on 16/Mar/20 $$\mathrm{The}\:\mathrm{circuit}\:\mathrm{above}\:\mathrm{shows}\:\mathrm{how}\:\mathrm{resistors}\:\mathrm{and}\:\mathrm{cells}\:\mathrm{can}\:\mathrm{be}\:\mathrm{connected} \\ $$$$\mathrm{given}\:\mathrm{that}\:{a},{b}\:\mathrm{and}\:{c}\:\mathrm{represent}\:\mathrm{currents}.\:\mathrm{Using}\:\mathrm{kirchoffs}\:\mathrm{laws}, \\ $$$$\left.\mathrm{a}\right)\:\mathrm{find}\:\mathrm{the}\:\mathrm{values}\:\mathrm{of}\:{a},{b}\:\mathrm{and}\:{c}.\:\left[\mathrm{these}\:\mathrm{are}\:\mathrm{not}\:\mathrm{usual}\:\mathrm{symbols}\right] \\ $$$$\left.\mathrm{b}\right)\:\mathrm{Calculate}\:\mathrm{the}\:\mathrm{pd}\:\left(\mathrm{potential}\:\mathrm{difference}\right)\:\mathrm{between}\:\mathrm{A}\:\mathrm{and}\:\mathrm{B}.…
Question Number 147554 by jlewis last updated on 21/Jul/21 $$\mathrm{A}\:\mathrm{toroid}\:\mathrm{core}\:\mathrm{has}\:\mathrm{N}=\mathrm{1200}\:\mathrm{turns}, \\ $$$$\mathrm{length}\:\mathrm{L}=\mathrm{80cm},\mathrm{cross}-\mathrm{section}\:\mathrm{area} \\ $$$$\mathrm{A}=\mathrm{60cm}^{\mathrm{2}} ,\mathrm{current}\:\mathrm{I}=\mathrm{1}.\mathrm{5A}. \\ $$$$\:\:\mathrm{Compute}\:\mathrm{B}\:\mathrm{and}\:\mathrm{H}.\mathrm{Assume}\:\mathrm{an} \\ $$$$\:\mathrm{empty}\:\mathrm{core} \\ $$ Answered by Olaf_Thorendsen last…
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