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Category: Electrostatics

Question-59703

Question Number 59703 by ranusahu last updated on 13/May/19 Answered by ajfour last updated on 13/May/19 $$\mathrm{2kx}_{\mathrm{0}} =\frac{\mathrm{Qq}}{\mathrm{2}\pi^{\mathrm{2}} \epsilon_{\mathrm{0}} \mathrm{a}^{\mathrm{2}} } \\ $$$$\mathrm{x}_{\mathrm{0}} =\frac{\mathrm{Qq}}{\mathrm{4}\pi^{\mathrm{2}} \epsilon_{\mathrm{0}}…

Question-57783

Question Number 57783 by Tinkutara last updated on 11/Apr/19 Answered by ajfour last updated on 12/Apr/19 $$\mathrm{at}\:\mathrm{B}\:\mathrm{b}'\mathrm{coz}\:\:\frac{\partial\mathrm{V}}{\partial\mathrm{r}}\:\mathrm{seem}\:\mathrm{greatest}\:\mathrm{there}. \\ $$ Commented by Tinkutara last updated on…

2-plane-parallel-conducting-plates-are-held-horizontal-one-above-the-other-in-a-vacuum-Electrons-having-a-speed-of-6-10-6-m-s-and-moves-normally-to-the-plates-enter-the-region-between-them-through-a-h

Question Number 55431 by necx1 last updated on 24/Feb/19 $$\mathrm{2}\:{plane}\:{parallel}\:{conducting}\:{plates}\:{are} \\ $$$${held}\:{horizontal},{one}\:{above}\:{the}\:{other}\:{in} \\ $$$${a}\:{vacuum}.{Electrons}\:{having}\:{a}\:{speed}\:{of} \\ $$$$\mathrm{6}×\mathrm{10}^{\mathrm{6}} {m}/{s}\:{and}\:{moves}\:{normally}\:{to}\:{the} \\ $$$${plates}\:{enter}\:{the}\:{region}\:{between}\:{them} \\ $$$${through}\:{a}\:{hole}\:{in}\:{the}\:{lower}\:{plate}\:{which} \\ $$$${is}\:{earthed}.{What}\:{potential}\:{must}\:{be} \\ $$$${applied}\:{to}\:{the}\:{other}\:{plate}\:{so}\:{that}\:{the}…

Question-52222

Question Number 52222 by Umar last updated on 04/Jan/19 Answered by peter frank last updated on 04/Jan/19 $$\left.{a}\right)\:\:\:{E}=\frac{{v}}{{d}} \\ $$$${E}=\frac{\mathrm{150}}{\mathrm{6}×\mathrm{10}^{−\mathrm{3}} }=\mathrm{25000}{V}/{m} \\ $$$${a}=\frac{{eE}}{{m}} \\ $$$${a}=\frac{\left(\mathrm{1}.\mathrm{6}×\mathrm{10}^{−\mathrm{19}}…