Question Number 40711 by Necxx last updated on 26/Jul/18 $${Two}\:{point}\:{charges},{q}_{\mathrm{1}} =\mathrm{0}.\mathrm{4}\mu{C}\:{and} \\ $$$${q}_{\mathrm{2}} =−\mathrm{0}.\mathrm{3}\mu{C}\:{are}\:{placed}\:{at}\:\mathrm{10}{cm} \\ $$$${apart}.{Calculate}\: \\ $$$$\left({a}\right){the}\:{potential}\:{at}\:{point}\:{A}\:{which}\:{is} \\ $$$${midway}\:{between}\:{them},{and} \\ $$$$\left({b}\right){point}\:{B}\:{which}\:{is}\:\mathrm{6}{cm}\:{from}\:{q}_{\mathrm{1}} \\ $$$${and}\:\mathrm{8}{cm}\:{from}\:{q}_{\mathrm{2}} \\…
Question Number 40700 by Necxx last updated on 26/Jul/18 $${A}\:{charge}\:{q}_{\mathrm{1}} =\mathrm{2}.\mathrm{0}×\mathrm{10}^{−\mathrm{9}} {C}\:{is}\:{placed} \\ $$$${at}\:{the}\:{point},\left({x}=\mathrm{0},{y}=\mathrm{4}{cm}\right)\:{and} \\ $$$${another}\:{charge},{q}_{\mathrm{2}} =−\mathrm{3}.\mathrm{0}×\mathrm{10}^{−\mathrm{9}} {C} \\ $$$${is}\:{located}\:{at}\:{the}\:{point},\left({x}=\mathrm{3}{cm},{y}=\mathrm{4}{cm}\right). \\ $$$${If}\:{a}\:{third}\:{charge},{q}_{\mathrm{3}} =\mathrm{4}.\mathrm{0}×\mathrm{10}^{−\mathrm{9}} {C} \\…
Question Number 40699 by Necxx last updated on 26/Jul/18 $${Two}\:{point}\:{charges}\:{q}_{\mathrm{1}} =\mathrm{1}.\mathrm{5}×\mathrm{10}^{−\mathrm{9}} {C} \\ $$$${and}\:{q}_{\mathrm{2}} =\mathrm{3}.\mathrm{0}×\mathrm{10}^{−\mathrm{9}} {C}\:{are}\:{seperated} \\ $$$${by}\:{a}\:{distance}\:{of}\:\mathrm{200}{cm}.{Calculate} \\ $$$${the}\:{point}\:{at}\:{which}\:{the}\:{total}\:{electric} \\ $$$${field}\:{is}\:{zero}. \\ $$ Answered…
Question Number 39794 by NECx last updated on 11/Jul/18 $${Two}\:{charged}\:{concentric}\:{spheres} \\ $$$${have}\:{radii}\:{of}\:\mathrm{10}{cm}\:{and}\:\mathrm{18}{cm}.{The} \\ $$$${charge}\:{on}\:{the}\:{inner}\:{sphere}\:{is} \\ $$$$\mathrm{6}.\mathrm{0}×\mathrm{10}^{−\mathrm{8}} {C}\:{and}\:{that}\:{on}\:{the}\:{outer} \\ $$$${sphere}\:{is}\:\mathrm{2}.\mathrm{0}×\mathrm{10}^{−\mathrm{8}} {C}.{Find}\:{the} \\ $$$${electric}\:{field}\:\left({i}\right){at}\:{r}=\mathrm{12}{cm}\:{and} \\ $$$$\left({ii}\right){at}\:{r}=\mathrm{25}{cm} \\…
Question Number 39792 by NECx last updated on 11/Jul/18 $${A}\:{positive}\:{charge}\:{of}\:{magnigude} \\ $$$$\mathrm{2}.\mathrm{5}\mu{C}\:{is}\:{at}\:{the}\:{centre}\:{of}\:{an}\:{uncharged} \\ $$$${spherical}\:{conducting}\:{shell}\:{of}\:{inner} \\ $$$${radius}\:\mathrm{60}{cm}\:{and}\:{an}\:{outer}\:{radius} \\ $$$${of}\:\mathrm{90}{cm}. \\ $$$$\left({i}\right){find}\:{the}\:{charge}\:{densities}\:{on}\:{thd} \\ $$$${inner}\:{and}\:{outer}\:{surfaces}\:{of}\:{the} \\ $$$${shell}\:{and}\:{the}\:{total}\:{charge}\:{on}\:{each} \\…
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Question Number 39623 by NECx last updated on 08/Jul/18 $${Two}\:{equal}\:{charges}\:{q}_{\mathrm{1}} ={q}_{\mathrm{2}\:} =−\mathrm{6}\mu{C} \\ $$$${are}\:{on}\:{the}\:{y}−{axis}\:{at}\:{y}_{\mathrm{1}} =\mathrm{3}{cm}\:{and} \\ $$$${y}_{\mathrm{2}} =−\mathrm{3}{cm}. \\ $$$$\left.{i}\right){What}\:{is}\:{the}\:{magnitude}\:{and} \\ $$$${direction}\:{of}\:{the}\:{electric}\:{field}\:{on}\:{the} \\ $$$${x}−{axis}\:{at}\:{x}=\:\mathrm{4}{cm}, \\…
Question Number 39622 by NECx last updated on 08/Jul/18 $${Two}\:{charges}\:{Q}_{\mathrm{0}} \:{and}\:\mathrm{3}{Q}_{\mathrm{0}} \:{are}\:{at}\:{l} \\ $$$${distance}\:{apart}.{These}\:{two}\:{charges} \\ $$$${are}\:{free}\:{to}\:{move}\:{but}\:{do}\:{not}\:{because} \\ $$$${is}\:{a}\:{third}\:{charge}\:{nearby}.{What}\:{must} \\ $$$${be}\:{the}\:{charge}\:{for}\:{the}\:{first}\:{two}\:{to}\:{be} \\ $$$${in}\:{equilibrium}? \\ $$ Terms…
Question Number 39573 by NECx last updated on 08/Jul/18 $${Point}\:{charges}\:\mathrm{88}\mu{C},−\mathrm{55}\mu{C}\:{and} \\ $$$$\mathrm{70}\mu{C}\:{are}\:{placed}\:{in}\:{a}\:{straight}\:{line}. \\ $$$${The}\:{central}\:{one}\:{is}\:\mathrm{0}.\mathrm{75}{m}\:{from} \\ $$$${each}\:{of}\:{the}\:{others}.{Calculate}\:{the} \\ $$$${net}\:{force}\:{on}\:{each}\:{due}\:{to}\:{the}\:{other} \\ $$$${two}. \\ $$ Commented by NECx…
Question Number 39267 by ajfour last updated on 04/Jul/18 Commented by ajfour last updated on 04/Jul/18 $${Find}\:{electric}\:{field}\:{due}\:{to}\:{ring}\:{of} \\ $$$${charge}\:{Q}\:{at}\:{P}\left({x},{y}\right)\:{in}\:{its}\:{plane}. \\ $$ Answered by ajfour last…