Question Number 36980 by Tinkutara last updated on 07/Jun/18 Answered by tanmay.chaudhury50@gmail.com last updated on 08/Jun/18 $${charge}\:{densigy}=\lambda \\ $$$${let}\:{length}\:{of}\:{rod}={l}=\mathrm{10}{cm} \\ $$$${distance}\:{of}\:{point}\:{p}\:{from}\:{the}\:{centre}\:{of}\:{rod}\:{is} \\ $$$${h}=\frac{\sqrt{\mathrm{3}}\:}{\mathrm{2}}{l}….{as}\:{per}\:{question}\:{point}\:{p}\:{and}\:{two}\: \\ $$$${end}\:{of}\:{rods}\:{make}\:{a}\:{equilateral}\:\:{triangle}…
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Question Number 36851 by Tinkutara last updated on 06/Jun/18 Answered by tanmay.chaudhury50@gmail.com last updated on 06/Jun/18 $$\bigtriangleup{V}={V}_{\mathrm{2}} −{V}_{\mathrm{1}} =\mathrm{80}−\mathrm{120}=−\mathrm{40} \\ $$$$\bigtriangleup{r}={r}_{\mathrm{2}} −{r}_{\mathrm{1}} =\mathrm{1}−\left(−\mathrm{1}\right)=\mathrm{2} \\ $$$${E}=−\frac{\bigtriangleup{V}}{\bigtriangleup{r}}=\frac{−\left(−\mathrm{40}\right)}{\mathrm{2}}=\mathrm{20}…
Question Number 36722 by Tinkutara last updated on 04/Jun/18 Answered by tanmay.chaudhury50@gmail.com last updated on 06/Jun/18 $${the}\:{eletric}\:{field}\:{is}\:\overset{\rightarrow} {{E}}={E}\hat {{i}} \\ $$$${let}\:{assume}\:\:{a}\:{positive}\:{charge}\:{Q}\:{is}\:{situated} \\ $$$${at}\:{point}\:{p}\left(−{l},\mathrm{0}\right)\:{which}\:{produce}\:{Electric}\:{field} \\ $$$${now}\:{potential}\:{at}\:{point}\:{A}\:{is}\:{V}_{{A}}…
Question Number 36096 by rahul 19 last updated on 28/May/18 Commented by rahul 19 last updated on 30/May/18 $$?? \\ $$ Commented by tanmay.chaudhury50@gmail.com last…
Question Number 35940 by ajfour last updated on 26/May/18 Commented by ajfour last updated on 26/May/18 $${Find}\:{electric}\:{field}\:{at}\:\boldsymbol{{P}}\:{due}\:{to}\:{a} \\ $$$${a}\:{charged}\:{rectangular}\:{plate}\:{of} \\ $$$${surface}\:{charge}\:{density}\:\boldsymbol{\sigma}. \\ $$ Answered by…
Question Number 35895 by ajfour last updated on 25/May/18 Commented by ajfour last updated on 25/May/18 $${Find}\:{the}\:{electric}\:{field}\:{due}\:{to}\:{a} \\ $$$${uniformly}\:{charged}\:{equilateral} \\ $$$${triangular}\:{plate}\:\left({of}\:{charge}\:\right. \\ $$$$\left.{density}\:\sigma\right)\:{on}\:{the}\:{y}\:{axis}\:{at}\:{a}\: \\ $$$${distance}\:{y}\:{from}\:{origin}\:\left({the}\right.…
Question Number 35851 by ajfour last updated on 24/May/18 Commented by ajfour last updated on 25/May/18 $${Q}.\mathrm{35828}\:{continuation}.. \\ $$$${Find}\:{electric}\:{potential}\:{at}\:{point}\: \\ $$$${P}\left({x}_{\mathrm{0}} ,{y}_{\mathrm{0}} ,{z}_{\mathrm{0}} \right)\:{due}\:{to}\:{the}\:{charged} \\…
Question Number 35828 by ajfour last updated on 24/May/18 Commented by ajfour last updated on 24/May/18 $${Find}\:{the}\:{electric}\:{field}\:{at}\:{point}\:{P} \\ $$$${on}\:{the}\:{y}\:{axis}\:{at}\:{a}\:{distance}\:{y}\:{from} \\ $$$${origin}\:{due}\:{to}\:{a}\:{uniformly}\:{charged} \\ $$$${square}\:{wire}\:{frame}\:{of}\:{linear}\:{charge} \\ $$$${density}\:\lambda.\:{The}\:{frame}\:{lies}\:{in}\:{xz}…
Question Number 34652 by 33 last updated on 09/May/18 $${a}\:{point}\:{charge}\:{q}\:{is}\:{placed} \\ $$$${at}\:\left(\mathrm{0},{a}/\mathrm{2},\mathrm{0}\right)\:.\:{find}\:{flux} \\ $$$${due}\:{to}\:{point}\:{charge}\:{through} \\ $$$${a}\:{square}\:{sheet}\:{of}\:{side}\:{a}\:\: \\ $$$${in}\:{xz}\:{plane}\:{whose}\:{centre} \\ $$$${coincides}\:{with}\:{orign}. \\ $$$$\left(\:{do}\:{not}\:{use}\:{gauss}\:{law}\right) \\ $$ Commented…