Gravitation – Page 3

Question-27492

Tinku Tara June 4, 2023 Gravitation 0 Comments

Question Number 27492 by Tinkutara last updated on 07/Jan/18 Commented by Tinkutara last updated on 07/Jan/18 Terms of Service Privacy Policy Contact: info@tinkutara.com

If-a-planet-is-suddenly-stopped-in-its-orbit-supposed-to-be-circular-then-it-would-fall-into-the-sun-in-a-time-T-4-2-where-T-is-the-time-period-of-revolution-Prove-this-

Tinku Tara June 4, 2023 Gravitation 0 Comments

Question Number 27445 by Tinkutara last updated on 07/Jan/18 $I f a p l a n e t i s s u d d e n l y s t o p p e d i n i t s$ $o r b i t, s u p p o s e d t o b e c i r c u l a r, t h e n i t$ $w o u l d f a l l i n t o t h e s u n i n a t i m e \frac{T}{4 \sqrt{2}},$ $w h e r e T i s t h e t i m e p e r i o d o f$ $r e v o l u t i o n . P r o v e t h i s .$ Answered by mrW1 last updated…

Question-27287

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Question Number 27287 by Tinkutara last updated on 04/Jan/18 Commented by Tinkutara last updated on 04/Jan/18 Please explain (d) part only. Terms of Service Privacy Policy Contact: info@tinkutara.com

Question-27283

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Question Number 27283 by Tinkutara last updated on 04/Jan/18 Terms of Service Privacy Policy Contact: info@tinkutara.com

Question-27074

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Question Number 27074 by Tinkutara last updated on 01/Jan/18 Answered by mrW1 last updated on 01/Jan/18 Commented by mrW1 last updated on 02/Jan/18 $${dm}=\lambda{dx}=\left({a}_{\mathrm{0}} +{b}_{\mathrm{0}}…

Two-balls-each-of-radius-R-equal-mass-and-density-are-placed-in-contact-then-the-force-of-gravitation-between-them-is-proportional-to-1-F-1-R-2-2-F-R-3-F-R-4-4-F-1-R-

Tinku Tara June 4, 2023 Gravitation 0 Comments

Question Number 26959 by Tinkutara last updated on 31/Dec/17 $Two balls, each of radius R, equal mass$ $and density are placed in contact, then$ $the force of gravitation between them$ $is proportional to$ $(1) F \propto \frac{1}{R^{2}}$ $(2) F \propto R$ $(3) F \propto R^{4}$ $$\left(\mathrm{4}\right)\:{F}\:\propto\:\frac{\mathrm{1}}{{R}}…

For-a-geosynchronous-satellite-of-mass-m-moving-in-a-circular-orbit-around-the-earth-at-a-constant-speed-v-and-an-altitude-h-above-the-earth-surface-Show-the-velocity-v-GM-e-R-e-h-1-2-I

Tinku Tara June 4, 2023 Gravitation 0 Comments

Question Number 25684 by NECx last updated on 13/Dec/17 $F o r a g e o s y n c h r o n o u s s a t e l l i t e o f$ $m a s s m m o v i n g i n a c i r c u l a r$ $o r b i t a r o u n d t h e e a r t h a t a c o n s t a n t$ $s p e e d v a n d a n a l t i t u d e h a b o v e$ $t h e e a r t h s u r f a c e . S h o w t h e$ $v e l o c i t y v = {(\frac{{G M}_{e}}{R_{e} + h})}^{\frac{1}{2}} .$ $$…

A-rocket-vertically-from-the-surface-of-the-earth-with-an-initil-velocity-v-o-show-that-its-velocity-v-at-height-h-is-given-by-v-o-2-v-2-2gh-1-h-R-where-R-is-radius-of-earth-and-g-is-the

Tinku Tara June 3, 2023 Gravitation 0 Comments

Question Number 74411 by peter frank last updated on 24/Nov/19 $A r o c k e t v e r t i c a l l y f r o m$ $t h e s u r f a c e o f t h e e a r t h$ $w i t h a n i n i t i l v e l o c i t y (v_{o})$ $s h o w t h a t i t s v e l o c i t y v$ $a t h e i g h t h i s g i v e n b y$ $${v}_{{o}} ^{\mathrm{2}} −{v}^{\mathrm{2}} =\frac{\mathrm{2}{gh}}{\mathrm{1}+\frac{{h}}{{R}}}…

Question-138896

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Question Number 138896 by ajfour last updated on 19/Apr/21 Answered by ajfour last updated on 20/Apr/21 $L e t A b e o r i g i n a n d x a x i s$ $v e r t i c a l l y d o w n t o w a r d s c e n t e r$ $o f c u b e .$ $$−{dg}_{{x}} =\frac{\left({Gdm}\right){x}}{\left({x}^{\mathrm{2}} +{y}^{\mathrm{2}}…

Question-72775

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Question Number 72775 by peter frank last updated on 02/Nov/19 Terms of Service Privacy Policy Contact: info@tinkutara.com

Category: Gravitation