Question Number 40946 by Necxx last updated on 29/Jul/18 $${Each}\:{of}\:{two}\:{long}\:{straight}\:{wires}\:\mathrm{4}{cm} \\ $$$${apart}\:{carry}\:{equal}\:{electric}\:{currents} \\ $$$${and}\:{experience}\:{a}\:{force}\:{of}\:\mathrm{2}×\mathrm{10}^{−\mathrm{4}} {N}/{m}. \\ $$$${What}\:{is}\:{the}\:{magnitude}\:{of}\:{the} \\ $$$${electric}\:{current}\:{in}\:{each}? \\ $$ Answered by tanmay.chaudhury50@gmail.com last…
Question Number 40945 by Necxx last updated on 29/Jul/18 $${Two}\:{parallel}\:{plate}\:{conductors}\:\mathrm{1}{m} \\ $$$${from}\:{each}\:{other}\:{carry}\:{an}\:{electric} \\ $$$${current}\:{of}\:\mathrm{2}{A}\:{each}.{Find}\:{the}\:{magnetic} \\ $$$${force}\:{per}\:{metre}\:{on}\:{each}\:{wire}. \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 40911 by rahul 19 last updated on 29/Jul/18 Commented by rahul 19 last updated on 29/Jul/18 $$\mathrm{Q}.\mathrm{26}\rightarrow\:\mathrm{I}'\mathrm{m}\:\mathrm{getting}\:\mathrm{i}_{\mathrm{max}.} =\:\mathrm{13V}_{\mathrm{0}\:} \sqrt{\frac{\mathrm{C}}{\mathrm{L}}.} \\ $$ Commented by…
Question Number 40818 by Necxx last updated on 27/Jul/18 $${Two}\:{large}\:{parallel}\:{metal}\:{plates}\:{carrying} \\ $$$${opposite}\:{charges}\:{are}\:{seperated}\:{by}\:{a} \\ $$$${distance}\:{of}\:\mathrm{0}.\mathrm{2}{m},{and}\:{the}\:{potential} \\ $$$${difference}\:{between}\:{them}\:{is}\:\mathrm{0}.\mathrm{5}{KV}. \\ $$$$\left({a}\right){Calculate}\:{the}\:{magnitude}\:{of}\:{the} \\ $$$${uniform}\:{electric}\:{field}\:{between}\:{them}. \\ $$$$\left({b}\right){Also}\:{calculate}\:{the}\:{workdone}\:{by} \\ $$$${this}\:{field}\:{on}\:{a}\:{charge}\:{of}\:\mathrm{4}.\mathrm{0}×\mathrm{10}^{−\mathrm{9}} {C}…
Question Number 40815 by Necxx last updated on 27/Jul/18 $${Calculate}\:{the}\:{magnetic}\:{force},{F}_{{b}} \:{on} \\ $$$${an}\:{electron}\:{with}\:{velocity},{v}=\mathrm{20}\hat {{j}m}/{s} \\ $$$${which}\:{enters}\:{a}\:{magnetic}\:{field}\:{of} \\ $$$${flux}\:{density},{B}=\mathrm{0}.\mathrm{6}\hat {{k}T} \\ $$ Answered by tanmay.chaudhury50@gmail.com last…
Question Number 40519 by rahul 19 last updated on 23/Jul/18 Commented by rahul 19 last updated on 23/Jul/18 $$\mathrm{If}\:\mathrm{the}\:\mathrm{resistance}\:\mathrm{of}\:\mathrm{larger}\:\mathrm{loop}\:\mathrm{is}\:\mathrm{R}, \\ $$$$\mathrm{find}\:\mathrm{current}\:\mathrm{in}\:\mathrm{it}\:\mathrm{as}\:\mathrm{a}\:\mathrm{function}\:\mathrm{of}\:\mathrm{time}? \\ $$ Answered by…
Question Number 40388 by rahul 19 last updated on 21/Jul/18 Answered by ajfour last updated on 21/Jul/18 $${i}=\frac{{E}}{{R}}\left(\mathrm{1}−{e}^{−\frac{{Rt}}{{L}}} \right) \\ $$$${q}=\frac{{E}}{{R}}\left({t}+\frac{{L}}{{R}}{e}^{−{Rt}/{L}} \right)\mid_{\mathrm{0}} ^{{L}/{R}} \\ $$$$\:\:{q}=\frac{{E}}{{R}}\left(\frac{{L}}{{eR}}\right)\:=\:\frac{{EL}}{{eR}^{\mathrm{2}}…
Question Number 38376 by ajfour last updated on 24/Jun/18 Commented by MrW3 last updated on 25/Jun/18 $${what}'{s}\:{the}\:{question}? \\ $$ Commented by ajfour last updated on…
Question Number 34888 by arnabmaiti550@gmail.com last updated on 12/May/18 Commented by arnabmaiti550@gmail.com last updated on 12/May/18 $$\mathrm{please}\:\mathrm{help} \\ $$ Answered by tanmay.chaudhury50@gmail.com last updated on…
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