Question Number 60748 by ajfour last updated on 25/May/19 Commented by ajfour last updated on 25/May/19 $${Determine}\:{r}\left(\theta\right). \\ $$ Answered by ajfour last updated on…
Question Number 60697 by ajfour last updated on 24/May/19 Commented by ajfour last updated on 24/May/19 $${How}\:{far}\:{can}\:{the}\:{slider}\:{slide}\:{if}\:{it} \\ $$$${ejects}\:{mass}\:{at}\:{rate}\:\frac{{dM}}{{dt}}\:=\:{R}\:,\:{at}\:{a} \\ $$$${relative}\:{speed}\:{u}\:?\: \\ $$$$\left(\frac{{M}_{\mathrm{0}} }{\mathrm{2}}\:\:{of}\:{M}_{\mathrm{0}} \:{doesn}'{t}\:{burn}\:{and}\right.…
Question Number 60237 by rahul 19 last updated on 19/May/19 Commented by rahul 19 last updated on 20/May/19 $$?????? \\ $$ Terms of Service Privacy…
Question Number 60133 by ajfour last updated on 18/May/19 Commented by ajfour last updated on 18/May/19 $$\mathrm{Find}\:\mathrm{angle}\:\alpha\:\mathrm{when}\:\mathrm{m}\:\mathrm{separates} \\ $$$$\mathrm{from}\:\mathrm{M}.\:\left(\mathrm{m}\:\mathrm{slides}\:\mathrm{down}\:\:\mathrm{from}\:\mathrm{top}\right. \\ $$$$\mathrm{of}\:\mathrm{M}\:,\:\mathrm{motion}\:\mathrm{being}\:\mathrm{initiated} \\ $$$$\left.\mathrm{somehow}\:\mathrm{with}\:\mathrm{a}\:\mathrm{slight}\:\mathrm{impulse}\right). \\ $$…
Question Number 60121 by rahul 19 last updated on 18/May/19 Commented by rahul 19 last updated on 18/May/19 $${time}\:{period}\:{is}\:{given}\:{as}\::\:\mathrm{2}\pi\sqrt{\frac{\rho{L}}{\sigma{g}}}\:. \\ $$$${Isn}'{t}\:{data}\:{insufficient}\:? \\ $$ Commented by…
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Question Number 59892 by rahul 19 last updated on 15/May/19 Commented by rahul 19 last updated on 15/May/19 $${Sir}\:,{ans}.\:{is}\:\left({c}\right)! \\ $$ Commented by tanmay last…
Question Number 190962 by Spillover last updated on 15/Apr/23 $$\mathrm{A}\:\mathrm{massless}\:\mathrm{spring}\:\mathrm{with}\:\mathrm{a}\:\mathrm{spring}\:\mathrm{constant} \\ $$$$\mathrm{K}=\mathrm{10Nm}^{−\mathrm{1}} \:\mathrm{is}\:\mathrm{suspended}\:\mathrm{from}\:\mathrm{rigid}\:\mathrm{support} \\ $$$$\mathrm{carries}\:\mathrm{a}\:\mathrm{mass}\:\mathrm{m}=\mathrm{100g}\:\mathrm{at}\:\mathrm{it}\:\mathrm{lower}\:\mathrm{end} \\ $$$$\mathrm{the}\:\mathrm{system}\:\mathrm{is}\:\mathrm{subjected}\:\mathrm{to}\:\mathrm{resistive}\:\mathrm{force} \\ $$$$−\mathrm{pv}.\mathrm{it}\:\mathrm{observed}\:\mathrm{that}\:\mathrm{the}\:\mathrm{system}\:\mathrm{oscillates} \\ $$$$\mathrm{and}\:\mathrm{its}\:\mathrm{energy}\:\mathrm{to}\:\mathrm{one}\:\mathrm{third}\:\mathrm{of}\:\mathrm{it}\:\mathrm{initial}\:\mathrm{value} \\ $$$$\mathrm{in}\:\mathrm{one}\:\mathrm{and}\:\mathrm{half}\:\mathrm{minutes}\:\mathrm{calculates}\:\mathrm{the}\: \\ $$$$\mathrm{value}\:\mathrm{of}\:\:\mathrm{p}…
Question Number 190903 by Spillover last updated on 13/Apr/23 Answered by mr W last updated on 14/Apr/23 $${m}_{{P}} {a}={m}_{{P}} {g}\:\mathrm{sin}\:\alpha−{T}\:\:\:…\left({i}\right) \\ $$$${m}_{{Q}} {a}={T}−{m}_{{Q}} {g}\:\mathrm{sin}\:\beta\:\:\:…\left({ii}\right) \\…
Question Number 190902 by Spillover last updated on 13/Apr/23 Answered by mr W last updated on 13/Apr/23 $$\left({i}\right) \\ $$$$\left({m}_{{A}} +{m}_{{B}} \right){a}=\left({m}_{{B}} −{m}_{{A}} \right){g} \\…