Question Number 190813 by Spillover last updated on 12/Apr/23 Answered by manxsol last updated on 12/Apr/23 $$ \\ $$$$ \\ $$$$ \\ $$ Commented by…
Question Number 190793 by 2kdw last updated on 11/Apr/23 $$ \\ $$$$\mathrm{A}\:\mathrm{projectile}\:\mathrm{of}\:\mathrm{mass}\:\boldsymbol{{M}}\:\mathrm{explodes}\:\mathrm{at}\:\mathrm{thee} \\ $$$$\mathrm{highst}\:\mathrm{point}\:\mathrm{of}\:\mathrm{its}\:\mathrm{trajectory}\:\mathrm{when}\:\mathrm{it}\:\mathrm{hase} \\ $$$$\mathrm{vlocity}\:.\:\mathrm{The}\:\mathrm{horizontal}\:\mathrm{distance}\:\mathrm{travelede} \\ $$$$\mathrm{btween}\:\mathrm{launch}\:\mathrm{and}\:\mathrm{explosion}\:\mathrm{is}\:\boldsymbol{{x}}_{\mathrm{0}} \:.\:\mathrm{Two} \\ $$$$\mathrm{fragments}\:\mathrm{are}\:\mathrm{produced}\:\mathrm{with}\:\mathrm{initiale} \\ $$$$\mathrm{velocitis}\:\mathrm{parallel}\:\mathrm{to}\:\mathrm{the}\:\mathrm{ground}.\:\mathrm{They}\: \\ $$$$\mathrm{thenfollow}\:\mathrm{their}\:\mathrm{trajectories}\:\mathrm{until}\:\mathrm{they}\:\mathrm{hitt}…
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Question Number 59380 by rahul 19 last updated on 09/May/19 Answered by tanmay last updated on 09/May/19 $${N}_{\left({cup}\:{andball}\right)} {cos}\theta=\left({mg}\right)_{{ball}} \\ $$$${N}_{\left({cup}\:{and}\:{ball}\right)} {sin}\theta={N}_{{ball}\:{and}\:{ball}} \\ $$$$\frac{{N}_{{cup}\:{and}\:{ball}} }{{N}_{{ball}\:{and}\:{ball}}…
Question Number 59378 by tanmay last updated on 09/May/19 Answered by tanmay last updated on 09/May/19 $${Total}\:{force}=\mathrm{2}{T} \\ $$$${common}\:{accelaration}\:{a}_{{c}} =\frac{\mathrm{2}{T}}{{m}_{{man}} +{m}_{{plank}} }=\frac{\mathrm{200}}{\mathrm{150}} \\ $$$${a}_{{c}} =\frac{\mathrm{4}}{\mathrm{3}}…
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Question Number 59301 by ajfour last updated on 07/May/19 Commented by ajfour last updated on 07/May/19 $$\mathrm{If}\:\mathrm{deceleration}\:\mathrm{of}\:\mathrm{bullet}\:\mathrm{through} \\ $$$$\:\mathrm{wall}\:\mathrm{be}\:\alpha,\:\mathrm{find}\:\mathrm{y}\left(<\mathrm{h}\right)\:\mathrm{for}\:\mathrm{maximum}\:\mathrm{x}. \\ $$$$… \\ $$ Commented by…
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Question Number 59152 by Forkum Michael Choungong last updated on 05/May/19 Commented by Forkum Michael Choungong last updated on 05/May/19 $${In}\:{the}\:{figure}\:\mathrm{1}\:{above}\:{a}\:{craw}\:{bar},{ABC}, \\ $$$${is}\:{shown}\:{being}\:{used}\:{to}\:{dig}\:{and}\:{lift} \\ $$$${a}\:{heavy}\:{stone}\:{from}\:{the}\:{ground}.…