Question Number 190962 by Spillover last updated on 15/Apr/23 $$\mathrm{A}\:\mathrm{massless}\:\mathrm{spring}\:\mathrm{with}\:\mathrm{a}\:\mathrm{spring}\:\mathrm{constant} \\ $$$$\mathrm{K}=\mathrm{10Nm}^{−\mathrm{1}} \:\mathrm{is}\:\mathrm{suspended}\:\mathrm{from}\:\mathrm{rigid}\:\mathrm{support} \\ $$$$\mathrm{carries}\:\mathrm{a}\:\mathrm{mass}\:\mathrm{m}=\mathrm{100g}\:\mathrm{at}\:\mathrm{it}\:\mathrm{lower}\:\mathrm{end} \\ $$$$\mathrm{the}\:\mathrm{system}\:\mathrm{is}\:\mathrm{subjected}\:\mathrm{to}\:\mathrm{resistive}\:\mathrm{force} \\ $$$$−\mathrm{pv}.\mathrm{it}\:\mathrm{observed}\:\mathrm{that}\:\mathrm{the}\:\mathrm{system}\:\mathrm{oscillates} \\ $$$$\mathrm{and}\:\mathrm{its}\:\mathrm{energy}\:\mathrm{to}\:\mathrm{one}\:\mathrm{third}\:\mathrm{of}\:\mathrm{it}\:\mathrm{initial}\:\mathrm{value} \\ $$$$\mathrm{in}\:\mathrm{one}\:\mathrm{and}\:\mathrm{half}\:\mathrm{minutes}\:\mathrm{calculates}\:\mathrm{the}\: \\ $$$$\mathrm{value}\:\mathrm{of}\:\:\mathrm{p}…
Question Number 190903 by Spillover last updated on 13/Apr/23 Answered by mr W last updated on 14/Apr/23 $${m}_{{P}} {a}={m}_{{P}} {g}\:\mathrm{sin}\:\alpha−{T}\:\:\:…\left({i}\right) \\ $$$${m}_{{Q}} {a}={T}−{m}_{{Q}} {g}\:\mathrm{sin}\:\beta\:\:\:…\left({ii}\right) \\…
Question Number 190902 by Spillover last updated on 13/Apr/23 Answered by mr W last updated on 13/Apr/23 $$\left({i}\right) \\ $$$$\left({m}_{{A}} +{m}_{{B}} \right){a}=\left({m}_{{B}} −{m}_{{A}} \right){g} \\…
Question Number 190813 by Spillover last updated on 12/Apr/23 Answered by manxsol last updated on 12/Apr/23 $$ \\ $$$$ \\ $$$$ \\ $$ Commented by…
Question Number 190793 by 2kdw last updated on 11/Apr/23 $$ \\ $$$$\mathrm{A}\:\mathrm{projectile}\:\mathrm{of}\:\mathrm{mass}\:\boldsymbol{{M}}\:\mathrm{explodes}\:\mathrm{at}\:\mathrm{thee} \\ $$$$\mathrm{highst}\:\mathrm{point}\:\mathrm{of}\:\mathrm{its}\:\mathrm{trajectory}\:\mathrm{when}\:\mathrm{it}\:\mathrm{hase} \\ $$$$\mathrm{vlocity}\:.\:\mathrm{The}\:\mathrm{horizontal}\:\mathrm{distance}\:\mathrm{travelede} \\ $$$$\mathrm{btween}\:\mathrm{launch}\:\mathrm{and}\:\mathrm{explosion}\:\mathrm{is}\:\boldsymbol{{x}}_{\mathrm{0}} \:.\:\mathrm{Two} \\ $$$$\mathrm{fragments}\:\mathrm{are}\:\mathrm{produced}\:\mathrm{with}\:\mathrm{initiale} \\ $$$$\mathrm{velocitis}\:\mathrm{parallel}\:\mathrm{to}\:\mathrm{the}\:\mathrm{ground}.\:\mathrm{They}\: \\ $$$$\mathrm{thenfollow}\:\mathrm{their}\:\mathrm{trajectories}\:\mathrm{until}\:\mathrm{they}\:\mathrm{hitt}…
Question Number 190629 by jlewis last updated on 07/Apr/23 Commented by jlewis last updated on 07/Apr/23 someone help me solve part two of the question Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 59380 by rahul 19 last updated on 09/May/19 Answered by tanmay last updated on 09/May/19 $${N}_{\left({cup}\:{andball}\right)} {cos}\theta=\left({mg}\right)_{{ball}} \\ $$$${N}_{\left({cup}\:{and}\:{ball}\right)} {sin}\theta={N}_{{ball}\:{and}\:{ball}} \\ $$$$\frac{{N}_{{cup}\:{and}\:{ball}} }{{N}_{{ball}\:{and}\:{ball}}…
Question Number 59378 by tanmay last updated on 09/May/19 Answered by tanmay last updated on 09/May/19 $${Total}\:{force}=\mathrm{2}{T} \\ $$$${common}\:{accelaration}\:{a}_{{c}} =\frac{\mathrm{2}{T}}{{m}_{{man}} +{m}_{{plank}} }=\frac{\mathrm{200}}{\mathrm{150}} \\ $$$${a}_{{c}} =\frac{\mathrm{4}}{\mathrm{3}}…
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