Question Number 116355 by Rio Michael last updated on 03/Oct/20 $$\mathrm{the}\:\mathrm{speed}\:{v}\:\mathrm{of}\:\mathrm{a}\:\mathrm{projectile}\:\mathrm{launched}\:\mathrm{at} \\ $$$$\mathrm{an}\:\mathrm{angle}\:\alpha\:\mathrm{to}\:\mathrm{the}\:\mathrm{horizontal}\:\mathrm{is}\:\mathrm{thought}\:\mathrm{to} \\ $$$$\mathrm{be}\:\mathrm{given}\:\mathrm{by}\:: \\ $$$$\:\:\:\:\:\:\:{v}\:=\:\left[\frac{\mathrm{1}}{{k}}\left({A}\:+\:\frac{\mathrm{sin}\:\alpha{t}}{\mathrm{g}}\right)\:+\:{e}^{−{C}/{t}} \right] \\ $$$$\mathrm{where}\:{k},{A},\:\:\alpha\:\mathrm{and}\:{C}\:\mathrm{are}\:\mathrm{constants},\:{t}\:\mathrm{is}\:\mathrm{time} \\ $$$$\mathrm{and}\:\mathrm{g}\:\mathrm{is}\:\mathrm{the}\:\mathrm{gravitational}\:\mathrm{acceleration}. \\ $$$$\mathrm{determine}\:\mathrm{the}\:\mathrm{base}\:\mathrm{units}\:\mathrm{of}\:{A},\:\alpha\:\mathrm{and}\:{C} \\…
Question Number 116338 by Dwaipayan Shikari last updated on 03/Oct/20 Commented by Dwaipayan Shikari last updated on 03/Oct/20 $$\mathrm{Two}\:\mathrm{thin}\:\mathrm{circular}\:\mathrm{discs}\:\mathrm{of}\:\mathrm{mass}\:\mathrm{m}\:\mathrm{and}\:\mathrm{4m}\:,\mathrm{having}\:\mathrm{Radii}\:\mathrm{a}\:\mathrm{and}\:\mathrm{2a} \\ $$$$\mathrm{respectively},\mathrm{are}\:\mathrm{rigidly}\:\mathrm{fixed}\:\mathrm{by}\:\mathrm{massless},\:\mathrm{rigid}\:\mathrm{rod}\:\mathrm{of}\:\mathrm{length} \\ $$$$\mathrm{l}=\sqrt{\mathrm{24}}\mathrm{a},\mathrm{through}\:\mathrm{their}\:\mathrm{centres},\:\mathrm{tbis}\:\mathrm{assembly}\:\mathrm{is}\:\mathrm{laid}\:\mathrm{on}\:\mathrm{a}\:\mathrm{firm}\:\mathrm{and}\:\mathrm{flat} \\ $$$$\mathrm{surface},\mathrm{and}\:\mathrm{set}\:\mathrm{rolling}\:\mathrm{without}\:\mathrm{slipping}\:\mathrm{on}\:\mathrm{the}\:\mathrm{surface}\:\mathrm{so}\:\mathrm{that}…
Question Number 181522 by mr W last updated on 26/Nov/22 Commented by mr W last updated on 26/Nov/22 $${two}\:{objects}\:{are}\:{fired}\:{at}\:{the}\:{same}\:{time} \\ $$$${from}\:{point}\:{A}\:{and}\:{point}\:{B}\:{as}\:{shown}. \\ $$$${what}\:{is}\:{the}\:{smallest}\:{distance}\: \\ $$$${between}\:{them}\:{after}\:{which}\:{time}?…
Question Number 50450 by JDlix last updated on 16/Dec/18 $${how}\:{many}\:{trips}\:{can}\:{a}\:{bird}\:{moving}\:{in}\:\mathrm{120}{m}/{s}\:{make} \\ $$$${between}\:{two}\:{trains}\:{which}\:{are}\:{initially}\:\mathrm{120}{m}\:{apart}\:{and} \\ $$$${moving}\:{in}\:\mathrm{60}{m}/{s}\:{to}\:{each}\:{other}? \\ $$$$ \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 50330 by peter frank last updated on 15/Dec/18 Commented by peter frank last updated on 15/Dec/18 Answered by mr W last updated on…
Question Number 181296 by yaslm last updated on 23/Nov/22 Answered by mr W last updated on 23/Nov/22 $${F}_{{GC}} =\mathrm{0} \\ $$$${F}_{{BG}} ×\frac{\mathrm{3}}{\mathrm{5}}=\mathrm{400}−\mathrm{200}=\mathrm{200} \\ $$$$\Rightarrow{F}_{{BG}} =\frac{\mathrm{1000}}{\mathrm{3}}…
Question Number 50101 by ajfour last updated on 13/Dec/18 Commented by ajfour last updated on 14/Dec/18 $${If}\:{system}\:{of}\:{ring}\:{and}\:{block}\:{be} \\ $$$${released}\:{as}\:{shown},\:{and}\:{later}\:{the} \\ $$$${ring}\:{hits}\:{the}\:{block}\:{as}\:{shown}\:{in} \\ $$$${dashed}\:{lines},\:{determine}\:\boldsymbol{{a}}. \\ $$$${Find}\:{also}\:{the}\:{velocity}\:{of}\:{ring}\:{then}.…
Question Number 181053 by Acem last updated on 22/Nov/22 $${An}\:{open}\:{pipe}\:{of}\:{r}_{{o}} =\:\mathrm{10}\:{Cm},\:\ell=\:\mathrm{3}{m}\:{has}\:{an}\:{outer} \\ $$$$\:{layer}\:{of}\:{ice}\:{that}\:{is}\:{melting}\:{at}\:{the}\:{rate}\:{of}\:\mathrm{2}\pi\:{Cm}^{\mathrm{3}} \\ $$$$\:{per}\:{minute}\:{with}\:{thickness}\:{of}\:\mathrm{20}\:{mm}.\:{How}\:{many} \\ $$$$\:{days}\:{untill}\:{all}\:{the}\:{ice}\:{melts}?\:{and}\:{how}\:{fast}\:{is}\:{the} \\ $$$$\:{thickness}\:{of}\:{the}\:{ice}\:{decreasing}\:{per}\:{hour}? \\ $$ Answered by Acem last…
Question Number 181052 by Acem last updated on 20/Nov/22 Commented by Acem last updated on 20/Nov/22 $$\ast\:{When}\:{the}\:{car}\:{is}\:\mathrm{6}\:{Km}\:{from}\:{A} \\ $$ Commented by mr W last updated…
Question Number 49966 by Necxx last updated on 12/Dec/18 $${A}\:{conveyor}\:{belt}\:{is}\:{driven}\:{at}\:{velocity} \\ $$$${v}\:{by}\:{a}\:{motor}.{Sand}\:{drops}\:{vertically} \\ $$$${on}\:{to}\:{the}\:{belt}\:{at}\:{a}\:{rate}\:{of}\:\boldsymbol{{m}}{kg}/{s}. \\ $$$${What}\:{is}\:{the}\:{additional}\:{power} \\ $$$${needed}\:{to}\:{keep}\:{the}\:{conveyor}\:{belt} \\ $$$${moving}\:{at}\:{a}\:{steady}\:{speed}\:{when} \\ $$$${the}\:{sand}\:{starts}\:{to}\:{fall}\:{on}\:{it}? \\ $$$$\left.{a}\left.\right)\left.\frac{\mathrm{1}}{\mathrm{2}}\left.{mv}\:{b}\right){mv}\:{c}\right)\frac{\mathrm{1}}{\mathrm{2}}{mv}^{\mathrm{2}} \:{d}\right){mv}^{\mathrm{2}}…