Question Number 49583 by ajfour last updated on 08/Dec/18 Commented by ajfour last updated on 08/Dec/18 $${If}\:{the}\:{paraboloid}\:{cup}\:{is}\:{absolutely} \\ $$$${slippery},\:{find}\:{fraction}\:{of}\:{stick} \\ $$$${length}\:{outside}\:{the}\:{cup}. \\ $$ Commented by…
Question Number 49559 by Rio Michael last updated on 07/Dec/18 Commented by Rio Michael last updated on 07/Dec/18 $${The}\:{figure}\:{below}\:{shows}\:{an}\:{object}\:{of}\:{mass}\:\mathrm{60}{kg}\:{pulled}\:{up} \\ $$$${by}\:{an}\:{effort}\:{of}\:\mathrm{4000}{J}\:{through}\:{an}\:{inclined}\:{plane}\:\mathrm{30}°\:{to}\:{the}\: \\ $$$${horizontal}. \\ $$$$\left.{a}\right)\:{Sketch}\:{the}\:{diagram}\:{showing}\:{all}\:{forces}\:{acting}\:{on}\:{the}\:{object}…
Question Number 49491 by Necxx last updated on 07/Dec/18 $${A}\:{rocket}\:{of}\:{mass}\:\mathrm{1000}{kg}\:{containing} \\ $$$${a}\:\:{propellant}\:{gas}\:{of}\:\mathrm{3000}{kg}\:{is}\:{to} \\ $$$${be}\:{launched}\:{vertically}.{If}\:{the}\:{fuel} \\ $$$${is}\:{consumed}\:{at}\:{a}\:{steady}\:{rate}\:{of} \\ $$$$\mathrm{60}{kg}/{s}.{Calculate}\:{the}\:{least}\:{velocith} \\ $$$${of}\:{the}\:{exhaust}\:{gases}\:{if}\:{the}\:{rocket} \\ $$$${and}\:{the}\:{content}\:{will}\:{just}\:{lift}\:{off} \\ $$$${the}\:{launching}\:{pad}\:{immediately} \\…
Question Number 114850 by Rio Michael last updated on 21/Sep/20 $$\mathrm{a}\:\mathrm{man}\:\mathrm{hits}\:\mathrm{a}\:\mathrm{golf}\:\mathrm{ball}\:\mathrm{at}\:\mathrm{the}\:\mathrm{top}\:\mathrm{of}\:\mathrm{a}\:\mathrm{cliff} \\ $$$$\mathrm{which}\:\mathrm{is}\:\mathrm{40}.\mathrm{0}\:\mathrm{m}\:\mathrm{high}.\:\mathrm{given}\:\mathrm{that}\:\mathrm{the} \\ $$$$\mathrm{ball}\:\mathrm{falls}\:\mathrm{into}\:\mathrm{a}\:\mathrm{water}\:\mathrm{down}\:\mathrm{cliff}\:\mathrm{and}\:\mathrm{he} \\ $$$$\mathrm{hears}\:\mathrm{the}\:\mathrm{sound}\:\mathrm{3}\:\mathrm{s}\:\mathrm{after}\:\mathrm{he}\:\mathrm{hit}\:\mathrm{the}\:\mathrm{ball}. \\ $$$$\mathrm{what}\:\mathrm{is}\:\mathrm{the}\:\mathrm{initial}\:\mathrm{speed}\:\mathrm{of}\:\mathrm{the}\:\mathrm{ball}.\:\mathrm{take} \\ $$$$\mathrm{the}\:\mathrm{speed}\:\mathrm{of}\:\mathrm{sound}\:\mathrm{in}\:\mathrm{air}\:\mathrm{as}\:\mathrm{343}\:\mathrm{m}/\mathrm{s}.\:\mathrm{neglect} \\ $$$$\mathrm{air}\:\mathrm{resistance}. \\ $$…
Question Number 49096 by peter frank last updated on 02/Dec/18 Answered by tanmay.chaudhury50@gmail.com last updated on 02/Dec/18 $$\left.{a}\right){velocity}\:{of}\:{man}\:{w}.{r}.{t}\:{ground}\:={V}_{{G}} ^{{m}} ={V}_{{G}} ^{{B}} +{V}_{{B}} ^{{m}} \\ $$$${if}\:{the}\:{was}\:{seated}\:{in}\:{chair}\:{or}\:{standing}\:…
Question Number 49097 by peter frank last updated on 02/Dec/18 Answered by tanmay.chaudhury50@gmail.com last updated on 02/Dec/18 $${T}=\mathrm{3}×\mathrm{10}=\mathrm{30}{N} \\ $$$${Normal}\:{reaction}=\mathrm{5}×\mathrm{10}=\mathrm{50}{N} \\ $$$${limiting}\:{friction}\:{f}_{{L}} =\mathrm{0}.\mathrm{55}×\mathrm{50}=\mathrm{27}.\mathrm{5}{N} \\ $$$${kinetic}\:{friction}\:{f}_{{k}}…
Question Number 49093 by peter frank last updated on 02/Dec/18 Answered by tanmay.chaudhury50@gmail.com last updated on 02/Dec/18 $$\left.\mathrm{12}\right){Normal}\:{reaction}\:{N}=\mathrm{5}×\mathrm{10}=\mathrm{50}{N} \\ $$$${limiting}\:{friction}\:{f}_{{L}} =\mathrm{0}.\mathrm{42}×\mathrm{50}=\mathrm{21}{N} \\ $$$${kinetic}\:{friction}\:{f}_{{k}} =\mathrm{0}.\mathrm{15}×\mathrm{50}=\mathrm{7}.\mathrm{5}\:{N} \\…
Question Number 49008 by peter frank last updated on 01/Dec/18 Answered by afachri last updated on 01/Dec/18 $$ \\ $$$$\boldsymbol{{F}}_{\mathrm{A}} =\:\mathrm{20}\:\mathrm{N}\:\Rightarrow\:\mathrm{The}\:\mathrm{resolved}\:\mathrm{force}\:\mathrm{in} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{direction}\:\mathrm{B}\:\mathrm{is}\:: \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:{F}_{\mathrm{A}\left({x}\right)}…
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Question Number 114512 by Rio Michael last updated on 19/Sep/20 Commented by Rio Michael last updated on 19/Sep/20 $$\mathrm{need}\:\mathrm{some}\:\mathrm{help}\:\mathrm{with}\:\mathrm{the}\:\mathrm{above},\mathrm{am} \\ $$$$\mathrm{particularly}\:\mathrm{stuck}\:\mathrm{at}\:\left(\mathrm{e}\right) \\ $$ Commented by…