Question Number 47422 by ajfour last updated on 09/Nov/18 Commented by ajfour last updated on 09/Nov/18 $${A}\:{vertical}\:{ellipsoid}\:{shell}\:{of} \\ $$$${frictionless}\:{surface}\:{holds}\:{a} \\ $$$${flexible}\:{rope}\:{ring}\:{of}\:{mass}\:{m}, \\ $$$${radius}\:{R}.\:{Find}\:{the}\:{tension}\:{in}\: \\ $$$${the}\:{rope}.…
Question Number 47344 by Necxx last updated on 08/Nov/18 $${On}\:{the}\:{moon}\:{the}\:{acceleration}\:{of} \\ $$$${free}\:{fall}\:{is}\:{only}\:{about}\:\mathrm{1}.\mathrm{6}{ms}^{−\mathrm{2}} . \\ $$$${About}\:{how}\:{long}\:{should}\:{a}\:{boy}\:{be} \\ $$$${able}\:{to}\:{throw}\:{a}\:{ball}\:{there}\:{if}\:{he}\:{can} \\ $$$${throw}\:{it}\:\mathrm{10}{m}\:{high}\:{on}\:{earth}? \\ $$$$\left({g}=\mathrm{10}{ms}^{−\mathrm{2}} \right) \\ $$ Answered…
Question Number 47342 by ajfour last updated on 08/Nov/18 Commented by ajfour last updated on 08/Nov/18 $${Find}\:{the}\:{Tension}\:{in}\:{rope}\left({light}\right)\:{if}\: \\ $$$${all}\:{surfaces}\:{are}\:{frictioness}. \\ $$ Answered by MrW3 last…
Question Number 47333 by Necxx last updated on 08/Nov/18 $${An}\:{aircraft}\:{flying}\:{horizontally} \\ $$$$\mathrm{100}{m}\:{above}\:{the}\:{ground}\:{and}\:{at}\:\mathrm{720}{km}/{h} \\ $$$${drops}\:{a}\:{bomb}\:{on}\:{a}\:{target}\:{on}\:{the} \\ $$$${ground}.{Determine}\:{the}\:{acute}\:{angle} \\ $$$${between}\:{the}\:{vertical}\:{and}\:{the}\:{line} \\ $$$${joining}\:{the}\:{aircraft}\:{and}\:{target}\:{at} \\ $$$${the}\:{instance}\:{when}\:{the}\:{bomb}\:{is} \\ $$$${released}.\left({g}=\mathrm{10}{ms}^{−\mathrm{2}} \right)…
Question Number 47302 by JDlix last updated on 08/Nov/18 $${A}\:{train}\:{which}\:{travels}\:{at}\:{a}\:{uniform}\:{speed}\:{due}\:{to}\:{mechanical}\: \\ $$$${fault}\:{after}\:{traveling}\:{for}\:{an}\:{hour}\:{goes}\:{at}\:\mathrm{3}/\mathrm{5}\:{th}\:{of}\:{the}\:{original}\: \\ $$$${speed}\:{and}\:{reaches}\:{the}\:{destination}\:\mathrm{2}\:{hours}\:{late}.{If}\:{the}\:{fault} \\ $$$${occured}\:{after}\:{traveling}\:{another}\:\mathrm{50}\:{miles}\:{the}\:{train}\:{would}\:{have} \\ $$$${reached}\:\mathrm{40}\:{minutes}\:{earlier}.\:{What}\:{is}\:{the}\:{distance}\:{between}\:{the}\: \\ $$$${two}\:{stations}\:? \\ $$ Answered by math1967…
Question Number 47289 by Necxx last updated on 07/Nov/18 $${Pls}\:{can}\:{Q}\mathrm{47194}\:{be}\:{solved}\:{by}\:{using} \\ $$$${the}\:{cosine}\:{rule}?{If}\:{possible}\:{please} \\ $$$${show}\:{me}\:{with}\:{the}\:{required}\:{diagram}. \\ $$$${Thanks}\:{in}\:{advance}. \\ $$ Commented by Necxx last updated on 08/Nov/18…
Question Number 47283 by Necxx last updated on 07/Nov/18 $${A}\:{stone}\:{tied}\:{to}\:{a}\:{string}\:{is}\:{made}\:{to} \\ $$$${resolve}\:{in}\:{a}\:{horizontal}\:{circle}\:{of} \\ $$$${radius}\:\mathrm{4}{m}\:{with}\:{another}\:{speed}\:{of} \\ $$$$\mathrm{2}{rads}^{−\mathrm{1}} .{With}\:{what}\:{tangential} \\ $$$${velocity}\:{will}\:{the}\:{stone}\:{be}\:{off}\:{the} \\ $$$${circle}\:{if}\:{the}\:{string}\:{cuts}? \\ $$ Commented by…
Question Number 47266 by MrW3 last updated on 07/Nov/18 Commented by MrW3 last updated on 07/Nov/18 $${Find}\:{the}\:{moment}\:{of}\:{initia}\:{of}\:{the} \\ $$$${solid}\:{body}\:{about}\:{its}\:{diagonal}\:{axis}. \\ $$ Answered by ajfour last…
Question Number 47194 by Necxx last updated on 06/Nov/18 $${The}\:{velocity}\:{of}\:{a}\:{ship}\:{Q}\:{relqtive}\:{to} \\ $$$${a}\:{ship}\:{P}\:\:{is}\:\mathrm{10}{km}/{h}\:{in}\:{a}\:{direction} \\ $$$${N}\mathrm{45}^{.} {E}.{If}\:{the}\:{velocity}\:{of}\:{P}\:\:{is}\:\mathrm{20}{km}/{h} \\ $$$${in}\:{a}\:{direction}\:{N}\mathrm{60}^{.} {W}.{Find}\:{the} \\ $$$${actual}\:{velocity}\:{of}\:{Q}\:{in}\:{magnitude} \\ $$$${and}\:{direction}. \\ $$ Commented…
Question Number 47188 by 23kpratik last updated on 06/Nov/18 $${verify}\:{stoke}\:{theorem}\:{for}\:{f}={y}^{\mathrm{2}} {j}+{x}^{\mathrm{3}} {j}\:{where}\:“{s}''\:{is}\:{the}\:{sircular}\:{disc}\:{x}^{\mathrm{2}} +{y}^{\mathrm{2}} \leqslant\mathrm{1},{z}=\mathrm{0} \\ $$ Answered by tanmay.chaudhury50@gmail.com last updated on 06/Nov/18 $$\int\int\left(\overset{\rightarrow} {\bigtriangledown}×\overset{\rightarrow}…