Question Number 47917 by Cesar Larez last updated on 16/Nov/18 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 47906 by ajfour last updated on 16/Nov/18 Commented by ajfour last updated on 18/Nov/18 $${If}\:{a}\:{solid}\:{cylinder}\:{released}\:{at} \\ $$$${top}\:{end}\:{of}\:{a}\:{plank}\:{that}\:{is}\:{free} \\ $$$${to}\:{turn}\:{about}\:{the}\:{bottom}\:{hinge} \\ $$$${at}\:{ground},\:{find}\:{linear}\:{velocity} \\ $$$${of}\:{cylinder}\:{and}\:{angular}\:{velocity}…
Question Number 47903 by Necxx last updated on 16/Nov/18 Commented by Necxx last updated on 16/Nov/18 $${mr}\:{Tanmay}\:{mrw}\:{and}\:{mr}\:{Ajfour} \\ $$$${please}\:{help} \\ $$ Commented by mr W…
Question Number 47860 by Cesar Larez last updated on 15/Nov/18 $$\mathrm{Anyone}\:\mathrm{know}\:\mathrm{how}\:\mathrm{it}\:\mathrm{came}\:\mathrm{to}\:\mathrm{the}\: \\ $$$$\mathrm{working}\:\mathrm{equation}? \\ $$ Commented by Necxx last updated on 16/Nov/18 $${what}\:{working}\:{equation}? \\ $$…
Question Number 47848 by Necxx last updated on 15/Nov/18 $${A}\:{body}\:{ascends}\:{a}\:{slope}\:{with}\:{a} \\ $$$${speed}\:{of}\:\mathrm{10}{m}/{s}.{If}\:\mathrm{105}{J}\:{of}\:{energy} \\ $$$${of}\:{the}\:{body}\:{is}\:{lost}\:{due}\:{to}\:{friction}\: \\ $$$${then}\:{the}\:{height}\:{to}\:{which}\:{the}\:{body} \\ $$$${will}\:{rise}\:{is} \\ $$$$\left.{a}\left.\right)\left.\mathrm{0}\left..\mathrm{5}{m}\:\:\:{b}\right)\mathrm{4}.\mathrm{5}{m}\:\:\:{c}\right)\mathrm{3}.\mathrm{5}{m}\:\:\:{d}\right)\mathrm{2}.\mathrm{0}{m} \\ $$ Commented by Necxx…
Question Number 178890 by peter frank last updated on 22/Oct/22 Commented by mr W last updated on 22/Oct/22 $${without}\:{this}\:{red}\:{word}\:{your}\:{question}\:{is} \\ $$$${not}\:{to}\:{understand}\:{properly}. \\ $$ Commented by…
Question Number 47814 by Necxx last updated on 15/Nov/18 $${A}\:{boy}\:{runs}\:{towards}\:{a}\:{man}\:{standing} \\ $$$$\mathrm{150}{m}\:{away}.{Speed}\:{of}\:{boy}\:{is}\:\mathrm{5}{m}/{s} \\ $$$${and}\:{that}\:{of}\:{man}\:{is}\:\mathrm{10}{m}/{s}.{The} \\ $$$${time}\:{and}\:{distance}\:{of}\:{their}\:{meeting} \\ $$$${from}\:{the}\:{boy}^{.} {s}\:{position}\:{are} \\ $$$$\left.{a}\left.\right)\left.\mathrm{15}{s}\:{b}\right)\mathrm{5}{s}\:{and}\:\mathrm{150}{m}\:{c}\right)\mathrm{10}{s}\:{and}\:\mathrm{50}{m} \\ $$$$\left.{d}\right)\mathrm{10}{s}\:{and}\:\mathrm{100}{m} \\ $$…
Question Number 47810 by Necxx last updated on 15/Nov/18 $${A}\:{mobike}\:{rider}\:{moving}\:{from}\:{A}\:{to}\:{B} \\ $$$${with}\:{speed}\:\mathrm{20}{km}/{h}\:{notices}\:{that}\:{a} \\ $$$${bus}\:{goes}\:{past}\:{it}\:{every}\:\mathrm{21}\:{minute}\:{in} \\ $$$${the}\:{direction}\:{of}\:{his}\:{motion}\:{and} \\ $$$${every}\:\mathrm{7}\:{minutes}\:{in}\:{the}\:{opposite} \\ $$$${direction}.{Velocity}\:{of}\:{the}\:{bus}\:{is} \\ $$$$\left.{a}\left.\right)\left.\mathrm{25}{km}/{h}\:{b}\right)\mathrm{35}{km}/{h}\:{c}\right)\mathrm{30}{km}/{h} \\ $$$$\left.{d}\right)\mathrm{40}{km}/{h} \\…
Question Number 178782 by peter frank last updated on 21/Oct/22 Answered by mr W last updated on 22/Oct/22 $${m}\frac{{dv}}{{dt}}={mg}\:\mathrm{sin}\:\theta−{kmv}^{\mathrm{2}} \\ $$$${dt}=\frac{{dv}}{{g}\:\mathrm{sin}\:\theta−{kv}^{\mathrm{2}} } \\ $$$$\int_{\mathrm{0}} ^{{t}}…
Question Number 178746 by Acem last updated on 21/Oct/22 Answered by mr W last updated on 21/Oct/22 $${s}={total}\:{length}\:{of}\:{chain}=\mathrm{3}{L}=\mathrm{3}\:{m} \\ $$$$\frac{\mathrm{2}{mg}}{\mathrm{3}}×\frac{{s}}{\mathrm{3}}−\frac{{mg}}{\mathrm{3}}×\frac{{s}}{\mathrm{6}}=\frac{{mv}^{\mathrm{2}} }{\mathrm{2}} \\ $$$$\Rightarrow{v}=\sqrt{\frac{{gs}}{\mathrm{3}}}=\sqrt{{g}}\:{m}/{s} \\ $$…