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Category: Mechanics

two-boxes-one-of-mass-20kg-and-the-other-of-mass-30kg-sre-sliding-down-on-a-frictionless-inclined-plane-that-makes-an-angle-of-25-0-with-the-horizontal-find-their-redpective-accelerstions-

Question Number 111196 by aurpeyz last updated on 02/Sep/20 $${two}\:{boxes}\:{one}\:{of}\:{mass}\:\mathrm{20}{kg}\:{and}\:{the}\:{other}\:{of}\: \\ $$$${mass}\:\mathrm{30}{kg}\:{sre}\:{sliding}\:{down}\:{on}\:{a}\:{frictionless} \\ $$$${inclined}\:{plane}\:{that}\:{makes}\:{an}\:{angle}\:{of}\:\mathrm{25}^{\mathrm{0}} \:{with}\:{the}\: \\ $$$${horizontal}.\:{find}\:{their}\:{redpective}\:{accelerstions}. \\ $$ Answered by Dwaipayan Shikari last updated…

Question-176660

Question Number 176660 by mr W last updated on 24/Sep/22 Commented by mr W last updated on 25/Sep/22 $${find}\:{the}\:{time}\:{the}\:{rod}\:{takes}\:{to}\:{reach} \\ $$$${the}\:{ground}.\: \\ $$$${the}\:{coefficient}\:{of}\:{friction}\:{between} \\ $$$${rod}\:{and}\:{wall}\:{is}\:\mu\:{which}\:{is}\:{small}\:{enough}…

A-2000kg-car-start-from-rest-and-accelerated-to-a-final-velocity-of-20m-s-in-16-seconds-Assuming-a-constant-air-resistance-of-500N-find-i-the-average-power-developed-by-the-engine-of-the-car-ii-

Question Number 110926 by Aina Samuel Temidayo last updated on 31/Aug/20 $$\mathrm{A}\:\mathrm{2000kg}\:\mathrm{car}\:\mathrm{start}\:\mathrm{from}\:\mathrm{rest}\:\mathrm{and} \\ $$$$\mathrm{accelerated}\:\mathrm{to}\:\mathrm{a}\:\mathrm{final}\:\mathrm{velocity}\:\mathrm{of} \\ $$$$\mathrm{20m}/\mathrm{s}\:\mathrm{in}\:\mathrm{16}\:\mathrm{seconds}.\:\mathrm{Assuming}\:\mathrm{a} \\ $$$$\mathrm{constant}\:\mathrm{air}\:\mathrm{resistance}\:\mathrm{of}\:\mathrm{500N},\:\mathrm{find} \\ $$$$\left(\mathrm{i}\right)\:\mathrm{the}\:\mathrm{average}\:\mathrm{power}\:\mathrm{developed}\:\mathrm{by} \\ $$$$\mathrm{the}\:\mathrm{engine}\:\mathrm{of}\:\mathrm{the}\:\mathrm{car}. \\ $$$$\left(\mathrm{ii}\right)\:\mathrm{the}\:\mathrm{instantaneous}\:\mathrm{power} \\…

Question-45205

Question Number 45205 by Necxx last updated on 10/Oct/18 Answered by tanmay.chaudhury50@gmail.com last updated on 11/Oct/18 $${w}=\sqrt{\frac{{K}}{{m}+\frac{{I}}{{R}^{\mathrm{2}} }}}\:=\sqrt{\frac{{K}}{{m}+\frac{{M}}{\mathrm{2}}}\:=\sqrt{\frac{\mathrm{1536}}{\mathrm{5}+\mathrm{1}}}\:=\sqrt{\mathrm{256}}\:=\mathrm{16}} \\ $$ Commented by Necxx last updated…

Question-110739

Question Number 110739 by ajfour last updated on 30/Aug/20 Commented by ajfour last updated on 30/Aug/20 $${Find}\:{height}\:{of}\:{center}\:{of}\:{mass}\:{of} \\ $$$${hemisphere}\:{if}\:{its}\:{density}\: \\ $$$$\boldsymbol{\rho}=\:\boldsymbol{\rho}_{\mathrm{0}} \left(\mathrm{1}+\frac{{y}}{{R}}\right). \\ $$ Answered…