Question Number 110467 by ajfour last updated on 29/Aug/20 Commented by ajfour last updated on 29/Aug/20 $${Find}\:{maximum}\:{F}\:{such}\:{that}\:{the} \\ $$$${cylinder}\:{resting}\:{against}\:{the}\:{ground} \\ $$$${and}\:{wall},\:{neither}\:{turns}\:{nor}\:{it}\:{moves}. \\ $$ Answered by…
Question Number 44928 by rahul 19 last updated on 06/Oct/18 Commented by rahul 19 last updated on 06/Oct/18 $$\left.{a}\right)\:{Maximum}\:{compression}\:{in}\:{the} \\ $$$${spring}\:{is}\:\frac{{w}_{{o}} }{\mathrm{2}}\sqrt{\frac{{mr}^{\mathrm{2}} }{{k}}\:}. \\ $$$$\left.{b}\right){Angular}\:{velocity}\:{of}\:{lower}\:{disc}\:{after}…
Question Number 175986 by ajfour last updated on 10/Sep/22 Answered by a.lgnaoui last updated on 11/Sep/22 $$\measuredangle{AOB}=\measuredangle{FDC}\:\:\:\:{OA}\:\mid\mid{DF}\:\:\:\:{CD}\:\mid\mid{OB} \\ $$$$\mathrm{tan}\:\left(\theta\right)=\frac{\mathrm{BF}}{\mathrm{BP}}=\frac{\mathrm{a}}{\mathrm{BP}}\:\:\:\:\mathrm{a}=\mathrm{BPtan}\:\left(\theta\right) \\ $$$$\frac{\mathrm{BP}}{\mathrm{CD}}=\frac{\mathrm{BF}}{\mathrm{FC}}\:\:\:\:\:\frac{\mathrm{a}}{\mathrm{btan}\:\left(\theta\right)}=\frac{{a}}{\mathrm{FC}}=\frac{{a}}{{a}+\mathrm{BC}} \\ $$$$\mathrm{BC}=\mathrm{DPsin}\:\left(\theta\right)\:\:\:\mathrm{DP}=\mathrm{OA}={R}\:\:\: \\ $$$$\:\frac{{a}}{{b}\mathrm{tan}\:\left(\theta\right)}=\frac{{a}}{{a}+{R}\mathrm{sin}\:\left(\theta\right)}…
Question Number 175949 by mr W last updated on 10/Sep/22 Commented by mr W last updated on 10/Sep/22 $${a}\:{mass}\:{m}\:{is}\:{fixed}\:{at}\:{the}\:{midpoint} \\ $$$${of}\:{an}\:{uniform}\:{thin}\:{rope}\:{with}\:{unit}\: \\ $$$${mass}\:\rho.\:{find}\:{the}\:{minimum}\:{length}\:{of} \\ $$$${the}\:{rope}\:{such}\:{that}\:{it}\:{can}\:{be}\:{kept}\:{in}\:…
Question Number 44872 by ajfour last updated on 05/Oct/18 Commented by ajfour last updated on 05/Oct/18 $${Find}\:{equation}\:{of}\:{the}\:{rope}\:{curve}, \\ $$$${bottom}\:{end}\:{of}\:{rope}\:{is}\:{at}\:{the}\:{foot} \\ $$$${of}\:{the}\:{incline}\:{and}\:{a}\:{length}\:\boldsymbol{{b}}\:{of}\:{it} \\ $$$${is}\:{in}\:{contact}\:{with}\:{the}\:{frictionless} \\ $$$${incline}.\:{Height}\:{of}\:{ceiling}\:{is}\:\boldsymbol{{h}}…
Question Number 44874 by Rio Michael last updated on 05/Oct/18 Commented by Rio Michael last updated on 05/Oct/18 $${the}\:{straight}\:{object}\:{above}\:{is}\:\mathrm{1}.\mathrm{0}{m}\:{long}\:{and}\:{is}\:{pivoted}\:{at}\:{a}\: \\ $$$${lesser}\:{seperated}\:{distance}\:\left(\mathrm{20}{cm}\right).\:{a}\:{weight}\:\mathrm{400}{N}\:{is}\:{put}\: \\ $$$${at}\:{the}\:{lesser}\:{end}\:{and}\:{another}\:{weight}\:{M}\:{is}\:{needed}\:{for}\: \\ $$$${the}\:{object}\:{to}\:{be}\:{in}\:{equilibrum}.…
Question Number 175938 by ajfour last updated on 09/Sep/22 Answered by mahdipoor last updated on 09/Sep/22 $$ \\ $$$${point}\:{of}\:{B}\mathrm{1}: \\ $$$$\left({a},{b}\right)+{a}\left({sin}\theta,{cos}\theta\right)\:\:\:\:\:\:\:\:\:\theta={wt}=\frac{{v}}{{a}}{t} \\ $$$${point}\:{of}\:{B}\mathrm{2}: \\ $$$$\left({ut},\mathrm{0}\right)…
Question Number 44779 by Necxx last updated on 04/Oct/18 Commented by Necxx last updated on 04/Oct/18 $${A}\:{cosmic}\:{body}\:{A}\:{moves}\:{towards} \\ $$$${the}\:{sun}\:{with}\:{velocity}\:{v}_{\mathrm{0}} \:\left({when}\right. \\ $$$$\left.{far}\:{from}\:{the}\:{sun}\right)\:{and}\:{aiming} \\ $$$${parameter}\:{l},\:{the}\:{direction}\:{of}\:{the} \\…
Question Number 44761 by ajfour last updated on 04/Oct/18 Commented by ajfour last updated on 05/Oct/18 $${Its}\:{a}\:{solid}\:{sphere}\:{that}'{ll}\:{roll} \\ $$$${down}\:{a}\:{wedge}\:{on}\:{small}\:{wheels}; \\ $$$${find}\:{the}\:{acceleration}\:{of}\:{wedge}. \\ $$$$\left({the}\:{angle}\:{of}\:{inclination}\:{of}\right. \\ $$$$\left.\:\:\:\:{wedge}\:{is}\:\theta\right).…
Question Number 44730 by Necxx last updated on 03/Oct/18 Commented by Necxx last updated on 03/Oct/18 $${please}\:{help}\:{with}\:{no}.\:\mathrm{5} \\ $$ Answered by tanmay.chaudhury50@gmail.com last updated on…