Question Number 109167 by Dwaipayan Shikari last updated on 21/Aug/20 Answered by mr W last updated on 21/Aug/20 $${ball}: \\ $$$${before}\:{collision}\:{v}_{{i}} =\sqrt{\mathrm{2}{gl}} \\ $$$${after}\:{collision}\:{v}_{{f}} =\sqrt{\mathrm{2}{gl}\left(\mathrm{1}−\mathrm{cos}\:\theta\right)}…
Question Number 43585 by ajfour last updated on 12/Sep/18 Commented by ajfour last updated on 12/Sep/18 $${The}\:{small}\:{ball}\:{has}\:{radius}\:\boldsymbol{{r}},\: \\ $$$${while}\:{the}\:{larger}\:{ball}\:{has}\:{radius} \\ $$$$\boldsymbol{{R}},\:{they}\:{collide}\:{on}\:{smooth} \\ $$$${horizontal}\:{ground},\:{impact} \\ $$$${parameter}\:{is}\:{equal}\:{to}\:\boldsymbol{{r}}.…
Question Number 108922 by ajfour last updated on 20/Aug/20 Commented by ajfour last updated on 20/Aug/20 $$\:\:\:\:\:\:\:{Neglect}\:{friction}.\:{Find} \\ $$$$\:\:\:\:\:{initial}\:{acceleration}\:{of}\:{M}. \\ $$ Answered by mr W…
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Question Number 174351 by ajfour last updated on 30/Jul/22 Answered by mr W last updated on 01/Aug/22 Commented by mr W last updated on 01/Aug/22…
Question Number 108619 by ajfour last updated on 18/Aug/20 Commented by ajfour last updated on 18/Aug/20 $${Find}\:{tension}\:{in}\:{rod}\:{connecting} \\ $$$${the}\:{blocks}. \\ $$ Commented by Dwaipayan Shikari…
Question Number 108588 by ajfour last updated on 17/Aug/20 Commented by ajfour last updated on 21/Aug/20 $${There}\:{is}\:{no}\:{friction}\:{between}\:{block} \\ $$$${and}\:{sphere},\:{but}\:{enough}\:{friction} \\ $$$${between}\:{ground}\:{and}\:{sphere},\:{such} \\ $$$${that}\:{sphere}\:{rolls}\:{as}\:{block}\:{slides} \\ $$$${backwards}.\:{Find}\:{maximum}…
Question Number 42654 by ajfour last updated on 30/Aug/18 Commented by ajfour last updated on 30/Aug/18 $${If}\:{the}\:{red}\:{ball}\:{is}\:{to}\:{hit}\:{the}\:{wall} \\ $$$${and}\:{then}\:{the}\:{blue}\:{ball},\:{find}\:{the} \\ $$$${speed}\:\boldsymbol{{u}}\:{and}\:{height}\:\boldsymbol{{h}}\:{where}\:{it} \\ $$$${hits}\:{the}\:{wall}.\:\left({coefficient}\:{of}\right. \\ $$$$\left.{restitution}\:{being}\:\boldsymbol{{e}}\right).…
Question Number 108133 by ajfour last updated on 14/Aug/20 Commented by ajfour last updated on 14/Aug/20 $${Rod}\:{AB}\:{inside}\:{a}\:{smooth}\:{sphere} \\ $$$${of}\:{radius}\:{R},\:{Find}\:{Normal} \\ $$$${reactions}\:{at}\:{A}\:{and}\:{B}. \\ $$ Answered by…
Question Number 108042 by Ar Brandon last updated on 14/Aug/20 $$\mathrm{A}\:\mathrm{particle}\:\mathrm{in}\:\mathrm{an}\:\mathrm{electric}\:\mathrm{and}\:\mathrm{magnetic}\:\mathrm{field}\:\mathrm{is}\:\mathrm{in}\:\mathrm{motion}. \\ $$$$\mathrm{The}\:\mathrm{time}\:\mathrm{equations}\:\mathrm{are}\:\mathrm{in}\:\mathrm{polar}\:\mathrm{coordinates}. \\ $$$$\mathrm{r}=\mathrm{r}_{\mathrm{0}} \mathrm{e}^{−\frac{\mathrm{t}}{\mathrm{b}}} \:\mathrm{and}\:\theta=\frac{\mathrm{t}}{\mathrm{b}}\:\mathrm{and}\:\mathrm{b}\:\mathrm{are}\:\mathrm{positive}\:\mathrm{constants}. \\ $$$$\mathrm{1}\backslash\mathrm{Calculate}\:\mathrm{the}\:\mathrm{vector}\:\mathrm{equation}\:\mathrm{of}\:\mathrm{the}\:\mathrm{velocity}\:\mathrm{of}\:\mathrm{the}\:\mathrm{particle}. \\ $$$$\mathrm{2}\backslash\mathrm{Show}\:\mathrm{that}\:\mathrm{the}\:\mathrm{angle}\:\left(\mathrm{v}_{\mathrm{1}} ^{'} ,\mathrm{u}_{\mathrm{0}} '\right)\:\mathrm{is}\:\mathrm{constant},\:\mathrm{and}\:\mathrm{find}\:\mathrm{the}\:\mathrm{value}. \\…